Since the user options (ExplainAnswer, TeachTopic, GeneratePractice) are all false, I will proceed directly to solving each problem step by step, verifying calculations, and then providing the final answers in order.
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Problem 1:
Three resistors in series: 650 Ω, 350 Ω, 1000 Ω.
In series, total resistance = sum of all resistances.
R_total = 650 + 350 + 1000 = 2000 Ω
✔ Verified.
Problem 2:
Ten 120 Ω resistors in series.
R_total = 10 × 120 = 1200 Ω
✔ Verified.
Problem 3:
Fifty 15 Ω lights in series.
R_total = 50 × 15 = 750 Ω
✔ Verified.
Problem 4:
Two 180 Ω resistors in parallel.
Formula for two equal resistors in parallel: R_total = R / 2
R_total = 180 / 2 = 90 Ω
✔ Verified.
Problem 5:
Resistors: 10 Ω, 20 Ω, 100 Ω in parallel.
Formula: 1/R_total = 1/10 + 1/20 + 1/100
Find common denominator (100):
= 10/100 + 5/100 + 1/100 = 16/100
So R_total = 100/16 = 6.25 Ω
✔ Verified.
Problem 6:
Fifty 15 Ω lights in parallel.
For n identical resistors in parallel: R_total = R / n
R_total = 15 / 50 = 0.3 Ω
✔ Verified.
Problem 7:
Two 100 Ω resistors in series → R_total = 200 Ω
Connected to 1.5 V battery.
Use Ohm’s Law: I = V / R = 1.5 / 200 = 0.0075 A = 7.5 mA
✔ Verified.
Problem 8:
Fifty 15 Ω in series → R_total = 750 Ω (from Problem 3)
Connected to 115 V source.
I = V / R = 115 / 750 ≈ 0.1533 A → Round to 0.153 A or 153 mA
✔ Verified.
Problem 9:
Fifty 15 Ω in parallel → R_total = 0.3 Ω (from Problem 6)
Connected to 115 V source.
I = V / R = 115 / 0.3 ≈ 383.33 A
✔ Verified.
Problem 10:
Three 1.2 Ω lamps in series → R_total = 3 × 1.2 = 3.6 Ω
Connected to 3 V battery.
I = V / R = 3 / 3.6 ≈ 0.833 A
✔ Verified.
Problem 11:
Three identical lamps in series connected to 6 V battery.
Voltage divides equally in series if resistances are equal.
Each lamp gets 6 V / 3 = 2 V
✔ Verified.
Problem 12:
How does current behave in a series circuit?
Current is the same at every point in a series circuit.
✔ Conceptual — no calculation needed.
Problem 13:
Two 33 Ω in parallel → R1 = 33/2 = 16.5 Ω
Another two 33 Ω in parallel → R2 = 33/2 = 16.5 Ω
Now these two groups are connected... but the problem says “followed by” — likely meaning in series? Let’s read again:
> “Two 33 ohm resistors are connected in parallel followed by two more 33 ohm resistors connected in parallel.”
This implies the first parallel pair is connected in series with the second parallel pair.
So total R = 16.5 + 16.5 = 33 Ω
Thus, one 33 Ω resistor can replace them.
✔ Verified.
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Final Answer:
1. 2000 Ω
2. 1200 Ω
3. 750 Ω
4. 90 Ω
5. 6.25 Ω
6. 0.3 Ω
7. 0.0075 A (or 7.5 mA)
8. 0.153 A (or 153 mA)
9. 383.33 A
10. 0.833 A
11. 2 V
12. Current is the same everywhere in a series circuit.
13. 33 Ω
Parent Tip: Review the logic above to help your child master the concept of series and parallel circuit worksheet.
