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Worksheet for predicting molecular shapes using Lewis structures and VSEPR theory.

A worksheet titled "Lewis Structures: Predicting the 3-D Shapes of Molecules" with a table listing molecules like CH₄, BeF₂, BF₃, CO₂, PF₅, and SO₂, each with columns for molecular formula, Lewis structure, electron domain geometry, molecular geometry, bond angles, and hybridization.

A worksheet titled "Lewis Structures: Predicting the 3-D Shapes of Molecules" with a table listing molecules like CH₄, BeF₂, BF₃, CO₂, PF₅, and SO₂, each with columns for molecular formula, Lewis structure, electron domain geometry, molecular geometry, bond angles, and hybridization.

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Show Answer Key & Explanations Step-by-step solution for: VSEPR Theory: Predicting the 3-D Shapes of Molecules Worksheet for ...
Let’s go step by step to fill in the table for each molecule. We’ll use basic rules of chemistry that you’ve probably learned:

1. Lewis structure – shows how atoms are bonded and where lone pairs are.
2. Molecular shape (VSEPR) – based on electron domains around central atom.
3. Bond angle – depends on shape (e.g., tetrahedral = 109.5°, trigonal planar = 120°, etc.)
4. Polarity – if bonds are polar AND shape doesn’t cancel them out → molecule is polar.

We’ll do one row at a time.

---

Row 1: CH₄ (already done as example)


- Lewis: C with 4 H’s, no lone pairs
- Shape: Tetrahedral
- Bond angle: 109.5°
- Polar? No — symmetric, all bonds same → nonpolar

Already correct.

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Row 2: BeF₂



Step 1: Lewis Structure
- Beryllium (Be) has 2 valence electrons.
- Each F has 7, needs 1 more → forms single bond with Be.
- So: F–Be–F
- Be has only 2 bonds, no lone pairs → total electron domains = 2

Step 2: Molecular Shape
- 2 bonding domains, 0 lone pairs → Linear

Step 3: Bond Angle
- Linear → 180°

Step 4: Polarity
- Be-F bonds are polar (F is very electronegative), but because it’s linear and symmetric, dipoles cancel → Nonpolar

Fill in:
- A: F–Be–F (with two dots on each F for lone pairs — but since we’re writing simply, just show bonds)
- B: Linear
- C: 180°
- D: Nonpolar

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Row 3: PCl₃



Step 1: Lewis Structure
- Phosphorus (P) has 5 valence electrons.
- Each Cl has 7, needs 1 → forms single bond with P.
- So P bonded to 3 Cl atoms → uses 3 electrons → 2 left → 1 lone pair on P.
- Total electron domains: 3 bonds + 1 lone pair = 4

Step 2: Molecular Shape
- Electron geometry: tetrahedral (4 domains)
- But one is lone pair → molecular shape = Trigonal Pyramidal

Step 3: Bond Angle
- Less than 109.5° because lone pair pushes bonds closer → about 107° (we can write “<109.5°” or “~107°”)

Step 4: Polarity
- P-Cl bonds are polar, and shape is not symmetric (pyramid) → dipoles don’t cancel → Polar

Fill in:
- A: P with 3 Cl’s and one lone pair (drawn as :PCl₃ or describe)
- B: Trigonal Pyramidal
- C: ~107° (or <109.5°)
- D: Polar

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Row 4: CO₂



Step 1: Lewis Structure
- Carbon has 4 valence electrons.
- Oxygen has 6, needs 2 → so double bonds!
- O=C=O
- No lone pairs on C, each O has 2 lone pairs.
- Electron domains on C: 2 double bonds → count as 2 domains

Step 2: Molecular Shape
- 2 bonding domains, 0 lone pairs → Linear

Step 3: Bond Angle
- 180°

Step 4: Polarity
- C=O bonds are polar, but linear and symmetric → dipoles cancel → Nonpolar

Fill in:
- A: O=C=O (each O with two lone pairs)
- B: Linear
- C: 180°
- D: Nonpolar

---

Row 5: PF₅



Step 1: Lewis Structure
- Phosphorus (P) has 5 valence electrons.
- Each F needs 1 → forms 5 single bonds.
- P has 5 bonds, no lone pairs → 5 electron domains

Step 2: Molecular Shape
- 5 bonding domains → Trigonal Bipyramidal

Step 3: Bond Angles
- In trigonal bipyramidal: equatorial angles = 120°, axial-equatorial = 90°
- Usually we say “90° and 120°”

Step 4: Polarity
- All P-F bonds are polar, but shape is symmetric → dipoles cancel → Nonpolar

Fill in:
- A: P with 5 F’s (three in plane, one up, one down)
- B: Trigonal Bipyramidal
- C: 90° and 120°
- D: Nonpolar

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Row 6: SO₂



Step 1: Lewis Structure
- Sulfur (S) has 6 valence electrons.
- Each O needs 2 → but S can form double bonds.
- One common structure: S double bonded to one O, single bonded to other O (which has negative charge), and S has positive charge → resonance.
- Or simpler: S with one double bond, one single bond, and one lone pair → total 3 electron domains.

Actually, best way:
- S central, bonded to two O’s.
- One double bond, one single bond (with formal charges), and one lone pair on S → total 3 electron domains.

Step 2: Molecular Shape
- 3 electron domains: 2 bonding, 1 lone pair → Bent (or V-shaped)

Step 3: Bond Angle
- Less than 120° because lone pair pushes → about 119° (we can say “<120°”)

Step 4: Polarity
- Bonds are polar, shape is bent → dipoles don’t cancel → Polar

Fill in:
- A: S with one double bond to O, one single bond to O (and lone pair on S)
- B: Bent
- C: ~119° (or <120°)
- D: Polar

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Now let’s answer question Q3 at bottom:

> Q3: What does "VSEPR" stand for? Is the molecular shape the same as associated with their shapes, what is the minimum number of atoms a molecule must have? Explain.

Wait — the question seems cut off. Let me read again:

> “What does 'VSEPR' stand for? Is the molecular shape the same as associated with their shapes, what is the minimum number of atoms a molecule must have? Explain.”

That middle part is confusing. Probably meant:

> “What does ‘VSEPR’ stand for? Is the molecular shape always the same as the electron domain geometry? What is the minimum number of atoms a molecule must have? Explain.”

But since it says “Is the molecular shape the same as associated with their shapes” — maybe typo.

Let’s assume standard questions:

1. VSEPR stands for: Valence Shell Electron Pair Repulsion

2. Is molecular shape same as electron domain geometry? → No, because lone pairs affect shape but aren’t part of molecular shape. Example: NH₃ has tetrahedral electron geometry but trigonal pyramidal molecular shape.

3. Minimum number of atoms in a molecule? → 2 (like O₂, N₂, HCl). A molecule must have at least two atoms bonded together. Single atoms (like He) are not molecules.

So answer:

VSEPR = Valence Shell Electron Pair Repulsion
Molecular shape ≠ electron domain geometry when there are lone pairs.
Minimum atoms in a molecule = 2

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Final Answer:

Here’s the completed table:

| # | Molecule | A. Lewis Structure | B. Molecular Shape | C. Bond Angle | D. Polar/Nonpolar |
|---|----------|-----------------------------|----------------------------|---------------------|-------------------|
| 1 | CH₄ | H-C-H (tetrahedral) | Tetrahedral | 109.5° | Nonpolar |
| 2 | BeF₂ | F-Be-F | Linear | 180° | Nonpolar |
| 3 | PCl₃ | P with 3 Cl and 1 lone pair | Trigonal Pyramidal | ~107° | Polar |
| 4 | CO₂ | O=C=O | Linear | 180° | Nonpolar |
| 5 | PF₅ | P with 5 F | Trigonal Bipyramidal | 90° and 120° | Nonpolar |
| 6 | SO₂ | S with 2 O (one double, one single, lone pair) | Bent | ~119° | Polar |

Q3 Answer:
- VSEPR stands for Valence Shell Electron Pair Repulsion.
- Molecular shape is NOT always the same as electron domain geometry — lone pairs change the shape.
- Minimum number of atoms in a molecule is 2 (e.g., O₂).
Parent Tip: Review the logic above to help your child master the concept of shapes of molecules worksheet.
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