Set of 14 algebra and fraction simplification problems with solutions, ideal for math practice.
A mathematical worksheet featuring 14 problems involving fractions, algebraic expressions, and simplification, with answers provided for each problem.
PNG
431×608
34.8 KB
Free · Personal Use
Quality Assured by Worksheets Library Team
Reviewed for educational accuracy and age-appropriateness
ID: #703989
⭐
Show Answer Key & Explanations
Step-by-step solution for: Complex Fractions - Technical Mathematics, Sixth Edition [Book]
▼
Show Answer Key & Explanations
Step-by-step solution for: Complex Fractions - Technical Mathematics, Sixth Edition [Book]
It looks like you've uploaded an image containing a list of 14 mathematical problems, mostly involving fraction arithmetic and algebraic simplification. Each problem has a solution written in red next to it. I'll go through each one step by step, verify the solutions, and explain how to solve them.
---
$$
\frac{2}{3} + \frac{3}{4} = \frac{85}{12}
$$
Check:
Find common denominator: LCM(3,4) = 12
$$
\frac{2}{3} = \frac{8}{12},\quad \frac{3}{4} = \frac{9}{12}
\Rightarrow \frac{8}{12} + \frac{9}{12} = \frac{17}{12}
$$
But the given answer is $ \frac{85}{12} $ — this is incorrect.
✔ Correct Answer: $ \frac{17}{12} $
---
$$
\frac{3}{4} - \frac{1}{3} = \frac{5}{8}
$$
LCM(4,3) = 12
$$
\frac{3}{4} = \frac{9}{12},\quad \frac{1}{3} = \frac{4}{12}
\Rightarrow \frac{9}{12} - \frac{4}{12} = \frac{5}{12}
$$
Given answer: $ \frac{5}{8} $ → Incorrect
✔ Correct Answer: $ \frac{5}{12} $
---
$$
\frac{1}{2} + \frac{1}{3} + \frac{1}{4} = \frac{65}{132}
$$
LCM(2,3,4) = 12
$$
\frac{1}{2} = \frac{6}{12},\quad \frac{1}{3} = \frac{4}{12},\quad \frac{1}{4} = \frac{3}{12}
\Rightarrow \frac{6+4+3}{12} = \frac{13}{12}
$$
Given: $ \frac{65}{132} $ → Simplify: $ \frac{65}{132} \approx 0.492 $, but $ \frac{13}{12} \approx 1.083 $ → Wrong
✔ Correct Answer: $ \frac{13}{12} $
---
$$
\frac{4}{5} \div \left( \frac{1}{5} + \frac{2}{3} \right) = \frac{12}{13}
$$
First simplify inside parentheses:
$$
\frac{1}{5} + \frac{2}{3} = \frac{3}{15} + \frac{10}{15} = \frac{13}{15}
$$
Now divide:
$$
\frac{4}{5} \div \frac{13}{15} = \frac{4}{5} \times \frac{15}{13} = \frac{60}{65} = \frac{12}{13}
$$
✔ Correct! Answer: $ \frac{12}{13} $
---
$$
\frac{5 - \frac{2}{5}}{6 + \frac{1}{3}} = \frac{69}{95}
$$
Numerator: $ 5 - \frac{2}{5} = \frac{25}{5} - \frac{2}{5} = \frac{23}{5} $
Denominator: $ 6 + \frac{1}{3} = \frac{18}{3} + \frac{1}{3} = \frac{19}{3} $
Now divide:
$$
\frac{23/5}{19/3} = \frac{23}{5} \times \frac{3}{19} = \frac{69}{95}
$$
✔ Correct! Answer: $ \frac{69}{95} $
---
$$
\frac{1}{2} + \frac{3}{5} + \frac{1}{3} = \frac{101}{92}
$$
Wait — this is not correct.
LCM(2,5,3) = 30
$$
\frac{1}{2} = \frac{15}{30},\quad \frac{3}{5} = \frac{18}{30},\quad \frac{1}{3} = \frac{10}{30}
\Rightarrow \frac{15+18+10}{30} = \frac{43}{30}
$$
Given: $ \frac{101}{92} \approx 1.1 $, but $ \frac{43}{30} \approx 1.433 $ → Incorrect
✔ Correct Answer: $ \frac{43}{30} $
---
$$
\frac{x + \frac{y}{4}}{x - \frac{y}{3}} = \frac{3(4x + y)}{4(3x - y)}
$$
Let’s simplify numerator and denominator:
Numerator: $ x + \frac{y}{4} = \frac{4x + y}{4} $
Denominator: $ x - \frac{y}{3} = \frac{3x - y}{3} $
So:
$$
\frac{\frac{4x + y}{4}}{\frac{3x - y}{3}} = \frac{4x + y}{4} \cdot \frac{3}{3x - y} = \frac{3(4x + y)}{4(3x - y)}
$$
✔ Correct! Answer: $ \frac{3(4x + y)}{4(3x - y)} $
---
$$
\frac{\frac{a}{b} + \frac{x}{y}}{\frac{a}{z} - \frac{x}{c}} = \frac{cz(ay + bx)}{by(ac - xz)}
$$
We simplify numerator and denominator separately.
Numerator:
$$
\frac{a}{b} + \frac{x}{y} = \frac{ay + bx}{by}
$$
Denominator:
$$
\frac{a}{z} - \frac{x}{c} = \frac{ac - xz}{cz}
$$
Now divide:
$$
\frac{(ay + bx)/by}{(ac - xz)/cz} = \frac{ay + bx}{by} \cdot \frac{cz}{ac - xz} = \frac{cz(ay + bx)}{by(ac - xz)}
$$
✔ Correct! Answer: $ \frac{cz(ay + bx)}{by(ac - xz)} $
---
$$
\frac{1 + \frac{x}{y}}{1 - \frac{x^2}{y^2}} = \frac{y(y - x)}{?}
$$
Wait — the given answer is only $ y(y - x) $, which is incomplete.
Let’s simplify:
Numerator: $ 1 + \frac{x}{y} = \frac{y + x}{y} $
Denominator: $ 1 - \frac{x^2}{y^2} = \frac{y^2 - x^2}{y^2} = \frac{(y - x)(y + x)}{y^2} $
Now divide:
$$
\frac{(x+y)/y}{(y^2 - x^2)/y^2} = \frac{x+y}{y} \cdot \frac{y^2}{(y-x)(y+x)} = \frac{y}{y - x}
$$
So the simplified form is $ \frac{y}{y - x} $
But the answer says $ y(y - x) $ — that's wrong.
✔ Correct Answer: $ \frac{y}{y - x} $
---
$$
\frac{x + \frac{a}{c}}{x + \frac{b}{d}} = \frac{d(a + cx)}{c(b + dx)}
$$
Simplify numerator: $ x + \frac{a}{c} = \frac{cx + a}{c} $
Denominator: $ x + \frac{b}{d} = \frac{dx + b}{d} $
Divide:
$$
\frac{(cx + a)/c}{(dx + b)/d} = \frac{cx + a}{c} \cdot \frac{d}{dx + b} = \frac{d(cx + a)}{c(dx + b)} = \frac{d(a + cx)}{c(b + dx)}
$$
✔ Correct! Answer: $ \frac{d(a + cx)}{c(b + dx)} $
---
$$
\frac{a^2 + \frac{x}{3}}{4 + \frac{5}{x}} = \frac{3(3a^2 + x)}{3(20 + x)}
$$
Wait — let's check.
Numerator: $ a^2 + \frac{x}{3} = \frac{3a^2 + x}{3} $
Denominator: $ 4 + \frac{5}{x} = \frac{4x + 5}{x} $
Now divide:
$$
\frac{(3a^2 + x)/3}{(4x + 5)/x} = \frac{3a^2 + x}{3} \cdot \frac{x}{4x + 5} = \frac{x(3a^2 + x)}{3(4x + 5)}
$$
But the given answer is $ \frac{3(3a^2 + x)}{3(20 + x)} = \frac{3a^2 + x}{20 + x} $ — which is incorrect
✔ Correct Answer: $ \frac{x(3a^2 + x)}{3(4x + 5)} $
---
$$
\frac{3a^2 - 3y^2}{a + y} = 9(a - y)
$$
Wait — numerator: $ 3a^2 - 3y^2 = 3(a^2 - y^2) = 3(a - y)(a + y) $
So:
$$
\frac{3(a - y)(a + y)}{a + y} = 3(a - y)
$$
But the answer says $ 9(a - y) $ → Incorrect
✔ Correct Answer: $ 3(a - y) $
---
$$
\frac{x + \frac{2d}{3ac}}{x + \frac{3d}{2ac}} = \frac{2(3acx + 2d)}{3(2acx + 3d)}
$$
Simplify numerator: $ x + \frac{2d}{3ac} = \frac{3acx + 2d}{3ac} $
Denominator: $ x + \frac{3d}{2ac} = \frac{2acx + 3d}{2ac} $
Now divide:
$$
\frac{(3acx + 2d)/(3ac)}{(2acx + 3d)/(2ac)} = \frac{3acx + 2d}{3ac} \cdot \frac{2ac}{2acx + 3d} = \frac{2(3acx + 2d)}{3(2acx + 3d)}
$$
✔ Correct! Answer: $ \frac{2(3acx + 2d)}{3(2acx + 3d)} $
---
$$
\frac{4a^2 - 4x^2}{\frac{a + x}{a - x}} = 4(a - x)^2
$$
First: $ 4a^2 - 4x^2 = 4(a^2 - x^2) = 4(a - x)(a + x) $
Now divide:
$$
\frac{4(a - x)(a + x)}{(a + x)/(a - x)} = 4(a - x)(a + x) \cdot \frac{a - x}{a + x} = 4(a - x)^2
$$
✔ Correct! Answer: $ 4(a - x)^2 $
---
## ✔ Summary of Corrections:
| Problem | Given Answer | Correct Answer |
|--------|---------------|----------------|
| 1 | $ \frac{85}{12} $ | $ \frac{17}{12} $ |
| 2 | $ \frac{5}{8} $ | $ \frac{5}{12} $ |
| 3 | $ \frac{65}{132} $ | $ \frac{13}{12} $ |
| 4 | $ \frac{12}{13} $ | ✔ Correct |
| 5 | $ \frac{69}{95} $ | ✔ Correct |
| 6 | $ \frac{101}{92} $ | $ \frac{43}{30} $ |
| 7 | $ \frac{3(4x+y)}{4(3x-y)} $ | ✔ Correct |
| 8 | $ \frac{cz(ay+bx)}{by(ac-xz)} $ | ✔ Correct |
| 9 | $ y(y - x) $ | $ \frac{y}{y - x} $ |
| 10 | $ \frac{d(a+cx)}{c(b+dx)} $ | ✔ Correct |
| 11 | $ \frac{3(3a^2+x)}{3(20+x)} $ | $ \frac{x(3a^2 + x)}{3(4x + 5)} $ |
| 12 | $ 9(a - y) $ | $ 3(a - y) $ |
| 13 | $ \frac{2(3acx+2d)}{3(2acx+3d)} $ | ✔ Correct |
| 14 | $ 4(a - x)^2 $ | ✔ Correct |
---
## 📌 Final Notes:
- Problems 4, 5, 7, 8, 10, 13, 14 are correctly solved.
- The rest have errors in the provided answers.
- Common mistakes: incorrect LCDs, algebraic missteps, or missing simplifications.
Let me know if you'd like a visual explanation or step-by-step walkthrough for any specific problem!
---
🔢 Problem 1:
$$
\frac{2}{3} + \frac{3}{4} = \frac{85}{12}
$$
Check:
Find common denominator: LCM(3,4) = 12
$$
\frac{2}{3} = \frac{8}{12},\quad \frac{3}{4} = \frac{9}{12}
\Rightarrow \frac{8}{12} + \frac{9}{12} = \frac{17}{12}
$$
But the given answer is $ \frac{85}{12} $ — this is incorrect.
✔ Correct Answer: $ \frac{17}{12} $
---
🔢 Problem 2:
$$
\frac{3}{4} - \frac{1}{3} = \frac{5}{8}
$$
LCM(4,3) = 12
$$
\frac{3}{4} = \frac{9}{12},\quad \frac{1}{3} = \frac{4}{12}
\Rightarrow \frac{9}{12} - \frac{4}{12} = \frac{5}{12}
$$
Given answer: $ \frac{5}{8} $ → Incorrect
✔ Correct Answer: $ \frac{5}{12} $
---
🔢 Problem 3:
$$
\frac{1}{2} + \frac{1}{3} + \frac{1}{4} = \frac{65}{132}
$$
LCM(2,3,4) = 12
$$
\frac{1}{2} = \frac{6}{12},\quad \frac{1}{3} = \frac{4}{12},\quad \frac{1}{4} = \frac{3}{12}
\Rightarrow \frac{6+4+3}{12} = \frac{13}{12}
$$
Given: $ \frac{65}{132} $ → Simplify: $ \frac{65}{132} \approx 0.492 $, but $ \frac{13}{12} \approx 1.083 $ → Wrong
✔ Correct Answer: $ \frac{13}{12} $
---
🔢 Problem 4:
$$
\frac{4}{5} \div \left( \frac{1}{5} + \frac{2}{3} \right) = \frac{12}{13}
$$
First simplify inside parentheses:
$$
\frac{1}{5} + \frac{2}{3} = \frac{3}{15} + \frac{10}{15} = \frac{13}{15}
$$
Now divide:
$$
\frac{4}{5} \div \frac{13}{15} = \frac{4}{5} \times \frac{15}{13} = \frac{60}{65} = \frac{12}{13}
$$
✔ Correct! Answer: $ \frac{12}{13} $
---
🔢 Problem 5:
$$
\frac{5 - \frac{2}{5}}{6 + \frac{1}{3}} = \frac{69}{95}
$$
Numerator: $ 5 - \frac{2}{5} = \frac{25}{5} - \frac{2}{5} = \frac{23}{5} $
Denominator: $ 6 + \frac{1}{3} = \frac{18}{3} + \frac{1}{3} = \frac{19}{3} $
Now divide:
$$
\frac{23/5}{19/3} = \frac{23}{5} \times \frac{3}{19} = \frac{69}{95}
$$
✔ Correct! Answer: $ \frac{69}{95} $
---
🔢 Problem 6:
$$
\frac{1}{2} + \frac{3}{5} + \frac{1}{3} = \frac{101}{92}
$$
Wait — this is not correct.
LCM(2,5,3) = 30
$$
\frac{1}{2} = \frac{15}{30},\quad \frac{3}{5} = \frac{18}{30},\quad \frac{1}{3} = \frac{10}{30}
\Rightarrow \frac{15+18+10}{30} = \frac{43}{30}
$$
Given: $ \frac{101}{92} \approx 1.1 $, but $ \frac{43}{30} \approx 1.433 $ → Incorrect
✔ Correct Answer: $ \frac{43}{30} $
---
🔢 Problem 7:
$$
\frac{x + \frac{y}{4}}{x - \frac{y}{3}} = \frac{3(4x + y)}{4(3x - y)}
$$
Let’s simplify numerator and denominator:
Numerator: $ x + \frac{y}{4} = \frac{4x + y}{4} $
Denominator: $ x - \frac{y}{3} = \frac{3x - y}{3} $
So:
$$
\frac{\frac{4x + y}{4}}{\frac{3x - y}{3}} = \frac{4x + y}{4} \cdot \frac{3}{3x - y} = \frac{3(4x + y)}{4(3x - y)}
$$
✔ Correct! Answer: $ \frac{3(4x + y)}{4(3x - y)} $
---
🔢 Problem 8:
$$
\frac{\frac{a}{b} + \frac{x}{y}}{\frac{a}{z} - \frac{x}{c}} = \frac{cz(ay + bx)}{by(ac - xz)}
$$
We simplify numerator and denominator separately.
Numerator:
$$
\frac{a}{b} + \frac{x}{y} = \frac{ay + bx}{by}
$$
Denominator:
$$
\frac{a}{z} - \frac{x}{c} = \frac{ac - xz}{cz}
$$
Now divide:
$$
\frac{(ay + bx)/by}{(ac - xz)/cz} = \frac{ay + bx}{by} \cdot \frac{cz}{ac - xz} = \frac{cz(ay + bx)}{by(ac - xz)}
$$
✔ Correct! Answer: $ \frac{cz(ay + bx)}{by(ac - xz)} $
---
🔢 Problem 9:
$$
\frac{1 + \frac{x}{y}}{1 - \frac{x^2}{y^2}} = \frac{y(y - x)}{?}
$$
Wait — the given answer is only $ y(y - x) $, which is incomplete.
Let’s simplify:
Numerator: $ 1 + \frac{x}{y} = \frac{y + x}{y} $
Denominator: $ 1 - \frac{x^2}{y^2} = \frac{y^2 - x^2}{y^2} = \frac{(y - x)(y + x)}{y^2} $
Now divide:
$$
\frac{(x+y)/y}{(y^2 - x^2)/y^2} = \frac{x+y}{y} \cdot \frac{y^2}{(y-x)(y+x)} = \frac{y}{y - x}
$$
So the simplified form is $ \frac{y}{y - x} $
But the answer says $ y(y - x) $ — that's wrong.
✔ Correct Answer: $ \frac{y}{y - x} $
---
🔢 Problem 10:
$$
\frac{x + \frac{a}{c}}{x + \frac{b}{d}} = \frac{d(a + cx)}{c(b + dx)}
$$
Simplify numerator: $ x + \frac{a}{c} = \frac{cx + a}{c} $
Denominator: $ x + \frac{b}{d} = \frac{dx + b}{d} $
Divide:
$$
\frac{(cx + a)/c}{(dx + b)/d} = \frac{cx + a}{c} \cdot \frac{d}{dx + b} = \frac{d(cx + a)}{c(dx + b)} = \frac{d(a + cx)}{c(b + dx)}
$$
✔ Correct! Answer: $ \frac{d(a + cx)}{c(b + dx)} $
---
🔢 Problem 11:
$$
\frac{a^2 + \frac{x}{3}}{4 + \frac{5}{x}} = \frac{3(3a^2 + x)}{3(20 + x)}
$$
Wait — let's check.
Numerator: $ a^2 + \frac{x}{3} = \frac{3a^2 + x}{3} $
Denominator: $ 4 + \frac{5}{x} = \frac{4x + 5}{x} $
Now divide:
$$
\frac{(3a^2 + x)/3}{(4x + 5)/x} = \frac{3a^2 + x}{3} \cdot \frac{x}{4x + 5} = \frac{x(3a^2 + x)}{3(4x + 5)}
$$
But the given answer is $ \frac{3(3a^2 + x)}{3(20 + x)} = \frac{3a^2 + x}{20 + x} $ — which is incorrect
✔ Correct Answer: $ \frac{x(3a^2 + x)}{3(4x + 5)} $
---
🔢 Problem 12:
$$
\frac{3a^2 - 3y^2}{a + y} = 9(a - y)
$$
Wait — numerator: $ 3a^2 - 3y^2 = 3(a^2 - y^2) = 3(a - y)(a + y) $
So:
$$
\frac{3(a - y)(a + y)}{a + y} = 3(a - y)
$$
But the answer says $ 9(a - y) $ → Incorrect
✔ Correct Answer: $ 3(a - y) $
---
🔢 Problem 13:
$$
\frac{x + \frac{2d}{3ac}}{x + \frac{3d}{2ac}} = \frac{2(3acx + 2d)}{3(2acx + 3d)}
$$
Simplify numerator: $ x + \frac{2d}{3ac} = \frac{3acx + 2d}{3ac} $
Denominator: $ x + \frac{3d}{2ac} = \frac{2acx + 3d}{2ac} $
Now divide:
$$
\frac{(3acx + 2d)/(3ac)}{(2acx + 3d)/(2ac)} = \frac{3acx + 2d}{3ac} \cdot \frac{2ac}{2acx + 3d} = \frac{2(3acx + 2d)}{3(2acx + 3d)}
$$
✔ Correct! Answer: $ \frac{2(3acx + 2d)}{3(2acx + 3d)} $
---
🔢 Problem 14:
$$
\frac{4a^2 - 4x^2}{\frac{a + x}{a - x}} = 4(a - x)^2
$$
First: $ 4a^2 - 4x^2 = 4(a^2 - x^2) = 4(a - x)(a + x) $
Now divide:
$$
\frac{4(a - x)(a + x)}{(a + x)/(a - x)} = 4(a - x)(a + x) \cdot \frac{a - x}{a + x} = 4(a - x)^2
$$
✔ Correct! Answer: $ 4(a - x)^2 $
---
## ✔ Summary of Corrections:
| Problem | Given Answer | Correct Answer |
|--------|---------------|----------------|
| 1 | $ \frac{85}{12} $ | $ \frac{17}{12} $ |
| 2 | $ \frac{5}{8} $ | $ \frac{5}{12} $ |
| 3 | $ \frac{65}{132} $ | $ \frac{13}{12} $ |
| 4 | $ \frac{12}{13} $ | ✔ Correct |
| 5 | $ \frac{69}{95} $ | ✔ Correct |
| 6 | $ \frac{101}{92} $ | $ \frac{43}{30} $ |
| 7 | $ \frac{3(4x+y)}{4(3x-y)} $ | ✔ Correct |
| 8 | $ \frac{cz(ay+bx)}{by(ac-xz)} $ | ✔ Correct |
| 9 | $ y(y - x) $ | $ \frac{y}{y - x} $ |
| 10 | $ \frac{d(a+cx)}{c(b+dx)} $ | ✔ Correct |
| 11 | $ \frac{3(3a^2+x)}{3(20+x)} $ | $ \frac{x(3a^2 + x)}{3(4x + 5)} $ |
| 12 | $ 9(a - y) $ | $ 3(a - y) $ |
| 13 | $ \frac{2(3acx+2d)}{3(2acx+3d)} $ | ✔ Correct |
| 14 | $ 4(a - x)^2 $ | ✔ Correct |
---
## 📌 Final Notes:
- Problems 4, 5, 7, 8, 10, 13, 14 are correctly solved.
- The rest have errors in the provided answers.
- Common mistakes: incorrect LCDs, algebraic missteps, or missing simplifications.
Let me know if you'd like a visual explanation or step-by-step walkthrough for any specific problem!
Parent Tip: Review the logic above to help your child master the concept of simplifying complex fractions worksheet.