We are asked to simplify the following rational expression:
$$
\frac{v^2 - 8v - 9}{v^2 + 3v + 2}
$$
---
Step 1: Factor the numerator and denominator
#### Factor the numerator: $ v^2 - 8v - 9 $
We need two numbers that multiply to $-9$ and add to $-8$.
Let's find such a pair:
- $1$ and $-9$: $1 \cdot (-9) = -9$, $1 + (-9) = -8$
✔
So:
$$
v^2 - 8v - 9 = (v + 1)(v - 9)
$$
#### Factor the denominator: $ v^2 + 3v + 2 $
We need two numbers that multiply to $2$ and add to $3$.
Try:
- $1$ and $2$: $1 \cdot 2 = 2$, $1 + 2 = 3$
✔
So:
$$
v^2 + 3v + 2 = (v + 1)(v + 2)
$$
---
Step 2: Rewrite the expression with factored forms
$$
\frac{(v + 1)(v - 9)}{(v + 1)(v + 2)}
$$
---
Step 3: Cancel common factors
Both numerator and denominator have a factor of $ (v + 1) $, so we can cancel it
as long as $ v \neq -1 $ (since division by zero is undefined).
After canceling:
$$
\frac{v - 9}{v + 2}, \quad \text{for } v \neq -1
$$
---
✔ Final Answer:
$$
\boxed{\frac{v - 9}{v + 2}}, \quad v \neq -1
$$
This is the simplified form of the given ratio.
Parent Tip: Review the logic above to help your child master the concept of simplifying polynomials worksheet.