Practice worksheet for simplifying rational expressions, featuring 30 algebraic problems.
A worksheet titled "Simplifying Rational Expressions—Practice" with 30 problems involving algebraic fractions to simplify, numbered 1 to 30, with blank lines for answers.
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Step-by-step solution for: Free Printable Simplifying Rational Expressions Worksheets
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Show Answer Key & Explanations
Step-by-step solution for: Free Printable Simplifying Rational Expressions Worksheets
Let's go through each of these rational expressions and simplify them step by step. The goal is to factor both the numerator and denominator, then cancel common factors.
---
- Factor:
$= \frac{8x^2}{12x^4} = \frac{2 \cdot 4 \cdot x^2}{3 \cdot 4 \cdot x^4}$
- Cancel common terms:
$= \frac{2}{3x^2}$
✔ Answer: $\boxed{\frac{2}{3x^2}}$
---
- Factor:
$= \frac{8 \cdot 3 \cdot x^2 \cdot y}{8 \cdot 4 \cdot x \cdot y^3}$
- Cancel:
$= \frac{3x}{4y^2}$
✔ Answer: $\boxed{\frac{3x}{4y^2}}$
---
- Cancel $(x+1)^3$:
$= \frac{1}{(x+1)^2}$
✔ Answer: $\boxed{\frac{1}{(x+1)^2}}$
---
- Cancel $(3x - 2)^4$:
$= (3x - 2)^2$
✔ Answer: $\boxed{(3x - 2)^2}$
---
- Notice: $3 - 2n = -(2n - 3)$
- So:
$= \frac{2n - 3}{-(2n - 3)} = -1$
✔ Answer: $\boxed{-1}$
---
- Cancel $y^2$, $(y+3)$:
$= \frac{15}{20y} = \frac{3}{4y}$
✔ Answer: $\boxed{\frac{3}{4y}}$
---
- Cancel $15y(y+1)$:
$= \frac{1}{3y}$
✔ Answer: $\boxed{\frac{1}{3y}}$
---
- Cancel $6x(4 - x)$:
$= \frac{24x^3}{18x} = \frac{4x^2}{3}$
✔ Answer: $\boxed{\frac{4x^2}{3}}$
---
- Cancel $6x(2 - x)$:
$= \frac{x^2}{2}$
✔ Answer: $\boxed{\frac{x^2}{2}}$
---
- Note: $2x - 5 = -(5 - 2x)$
- So:
$= \frac{12x^2(5 - 2x)}{18x \cdot (-(5 - 2x))} = \frac{12x^2}{-18x} = -\frac{2x}{3}$
✔ Answer: $\boxed{-\frac{2x}{3}}$
---
- Factor numerator: $a(a + 6)$
- Denominator: $c(a + 6)$
- Cancel $(a + 6)$:
$= \frac{a}{c}$
✔ Answer: $\boxed{\frac{a}{c}}$
---
- Numerator: $x(x + 4)$
- Denominator: $3(x + 4)$
- Cancel $(x + 4)$:
$= \frac{x}{3}$
✔ Answer: $\boxed{\frac{x}{3}}$
---
- Numerator: $-2(4x - 3)$
- Denominator: $x(4x - 3)$
- Cancel $(4x - 3)$:
$= \frac{-2}{x}$
✔ Answer: $\boxed{-\frac{2}{x}}$
---
- Factor:
Numerator: $(x + 5)(x - 3)$
Denominator: $(x - 7)(x - 3)$
- Cancel $(x - 3)$:
$= \frac{x + 5}{x - 7}$
✔ Answer: $\boxed{\frac{x + 5}{x - 7}}$
---
- Numerator: $(x - 3)(x + 1)$
- Denominator: $(x - 6)(x + 1)$
- Cancel $(x + 1)$:
$= \frac{x - 3}{x - 6}$
✔ Answer: $\boxed{\frac{x - 3}{x - 6}}$
---
- Numerator: $(x - 3)(x - 4)$
- Denominator: $(x - 4)(x + 3)$
- Cancel $(x - 4)$:
$= \frac{x - 3}{x + 3}$
✔ Answer: $\boxed{\frac{x - 3}{x + 3}}$
---
- Numerator: $(x - 5)(x + 2)$
- Denominator: $(x - 5)(x - 1)$
- Cancel $(x - 5)$:
$= \frac{x + 2}{x - 1}$
✔ Answer: $\boxed{\frac{x + 2}{x - 1}}$
---
- Numerator: $(x - 4)^2$
- Denominator: $(x - 4)(x - 5)$
- Cancel $(x - 4)$:
$= \frac{x - 4}{x - 5}$
✔ Answer: $\boxed{\frac{x - 4}{x - 5}}$
---
- Numerator: $(x - 2)(x - 5)$
- Denominator: $(x - 5)(x + 1)$
- Cancel $(x - 5)$:
$= \frac{x - 2}{x + 1}$
✔ Answer: $\boxed{\frac{x - 2}{x + 1}}$
---
- Numerator: $(x + 3)^2$
- Denominator: $(x + 3)(x - 1)$
- Cancel $(x + 3)$:
$= \frac{x + 3}{x - 1}$
✔ Answer: $\boxed{\frac{x + 3}{x - 1}}$
---
- Numerator: $(x - 6)(x + 4)$
- Denominator: $-(x^2 - 16) = -(x - 4)(x + 4)$
- Cancel $(x + 4)$:
$= \frac{x - 6}{-(x - 4)} = -\frac{x - 6}{x - 4}$
✔ Answer: $\boxed{-\frac{x - 6}{x - 4}}$
---
- Numerator: $-(y^2 - 9) = -(y - 3)(y + 3)$
- Denominator: $(y + 5)(y - 3)$
- Cancel $(y - 3)$:
$= \frac{-(y + 3)}{y + 5} = -\frac{y + 3}{y + 5}$
✔ Answer: $\boxed{-\frac{y + 3}{y + 5}}$
---
- Factor out $x$ from both:
$= \frac{x(3x^2 + 18x - 21)}{x(x^2 + 5x - 14)} = \frac{3x^2 + 18x - 21}{x^2 + 5x - 14}$
Now factor:
- Numerator: $3(x^2 + 6x - 7) = 3(x + 7)(x - 1)$
- Denominator: $(x + 7)(x - 2)$
Cancel $(x + 7)$:
$= \frac{3(x - 1)}{x - 2}$
✔ Answer: $\boxed{\frac{3(x - 1)}{x - 2}}$
---
- Factor numerator: $2x(x - 9)$
- Denominator: $4x(x^2 - 8x - 9) = 4x(x - 9)(x + 1)$
- Cancel $2x(x - 9)$:
$= \frac{1}{2(x + 1)}$
✔ Answer: $\boxed{\frac{1}{2(x + 1)}}$
---
Try factoring:
- Numerator: $5x^2 - 11x + 2 = (5x - 1)(x - 2)$
Check: $5x \cdot x = 5x^2$, $5x(-2) + (-1)x = -10x - x = -11x$, $(-1)(-2)=2$ → ✔
- Denominator: $5x^2 - 7x - 6 = (5x + 3)(x - 2)$
Check: $5x \cdot x = 5x^2$, $5x(-2) + 3x = -10x + 3x = -7x$, $3 \cdot (-2) = -6$ → ✔
Cancel $(x - 2)$:
$= \frac{5x - 1}{5x + 3}$
✔ Answer: $\boxed{\frac{5x - 1}{5x + 3}}$
---
Factor:
- Numerator: $2x^2 - 7x + 3 = (2x - 1)(x - 3)$
Check: $2x \cdot x = 2x^2$, $2x(-3) + (-1)x = -6x - x = -7x$, $(-1)(-3)=3$ → ✔
- Denominator: $2x^2 + 9x - 5 = (2x - 1)(x + 5)$
Check: $2x \cdot x = 2x^2$, $2x(5) + (-1)x = 10x - x = 9x$, $(-1)(5) = -5$ → ✔
Cancel $(2x - 1)$:
$= \frac{x - 3}{x + 5}$
✔ Answer: $\boxed{\frac{x - 3}{x + 5}}$
---
Rewrite denominator:
$12 - 4x - x^2 = -x^2 - 4x + 12 = -(x^2 + 4x - 12)$
Factor:
- Numerator: $x^2 + 2x - 24 = (x + 6)(x - 4)$
- Denominator: $-(x^2 + 4x - 12) = -(x + 6)(x - 2)$
So expression:
$\frac{(x + 6)(x - 4)}{-(x + 6)(x - 2)} = \frac{x - 4}{-(x - 2)} = -\frac{x - 4}{x - 2}$
✔ Answer: $\boxed{-\frac{x - 4}{x - 2}}$
---
- Numerator: $2(x^2 - 4) = 2(x - 2)(x + 2)$
- Denominator: $(x + 6)(x - 2)$
- Cancel $(x - 2)$:
$= \frac{2(x + 2)}{x + 6}$
✔ Answer: $\boxed{\frac{2(x + 2)}{x + 6}}$
---
Factor:
- Numerator: $2x^2 - 9x + 7 = (2x - 7)(x - 1)$
Check: $2x \cdot x = 2x^2$, $2x(-1) + (-7)x = -2x -7x = -9x$, $(-7)(-1)=7$ → ✔
- Denominator: $(x + 3)(x - 1)$
Cancel $(x - 1)$:
$= \frac{2x - 7}{x + 3}$
✔ Answer: $\boxed{\frac{2x - 7}{x + 3}}$
---
Factor numerator:
$8x^2 - 14x + 6 = 2(4x^2 - 7x + 3)$
Now factor $4x^2 - 7x + 3$:
$(4x - 3)(x - 1)$ → check: $4x \cdot x = 4x^2$, $4x(-1) + (-3)x = -4x -3x = -7x$, $(-3)(-1)=3$ → ✔
So numerator: $2(4x - 3)(x - 1)$
Denominator: $4x - 3$
Cancel $(4x - 3)$:
$= 2(x - 1)$
✔ Answer: $\boxed{2(x - 1)}$
---
## ✔ Final Answers:
| Problem | Answer |
|--------|--------|
| 1 | $\frac{2}{3x^2}$ |
| 2 | $\frac{3x}{4y^2}$ |
| 3 | $\frac{1}{(x+1)^2}$ |
| 4 | $(3x - 2)^2$ |
| 5 | $-1$ |
| 6 | $\frac{3}{4y}$ |
| 7 | $\frac{1}{3y}$ |
| 8 | $\frac{4x^2}{3}$ |
| 9 | $\frac{x^2}{2}$ |
| 10 | $-\frac{2x}{3}$ |
| 11 | $\frac{a}{c}$ |
| 12 | $\frac{x}{3}$ |
| 13 | $-\frac{2}{x}$ |
| 14 | $\frac{x + 5}{x - 7}$ |
| 15 | $\frac{x - 3}{x - 6}$ |
| 16 | $\frac{x - 3}{x + 3}$ |
| 17 | $\frac{x + 2}{x - 1}$ |
| 18 | $\frac{x - 4}{x - 5}$ |
| 19 | $\frac{x - 2}{x + 1}$ |
| 20 | $\frac{x + 3}{x - 1}$ |
| 21 | $-\frac{x - 6}{x - 4}$ |
| 22 | $-\frac{y + 3}{y + 5}$ |
| 23 | $\frac{3(x - 1)}{x - 2}$ |
| 24 | $\frac{1}{2(x + 1)}$ |
| 25 | $\frac{5x - 1}{5x + 3}$ |
| 26 | $\frac{x - 3}{x + 5}$ |
| 27 | $-\frac{x - 4}{x - 2}$ |
| 28 | $\frac{2(x + 2)}{x + 6}$ |
| 29 | $\frac{2x - 7}{x + 3}$ |
| 30 | $2(x - 1)$ |
Let me know if you'd like this formatted as a printable answer key!
---
1. $\frac{8x^2}{12x^4}$
- Factor:
$= \frac{8x^2}{12x^4} = \frac{2 \cdot 4 \cdot x^2}{3 \cdot 4 \cdot x^4}$
- Cancel common terms:
$= \frac{2}{3x^2}$
✔ Answer: $\boxed{\frac{2}{3x^2}}$
---
2. $\frac{24x^2y}{32xy^3}$
- Factor:
$= \frac{8 \cdot 3 \cdot x^2 \cdot y}{8 \cdot 4 \cdot x \cdot y^3}$
- Cancel:
$= \frac{3x}{4y^2}$
✔ Answer: $\boxed{\frac{3x}{4y^2}}$
---
3. $\frac{(x+1)^3}{(x+1)^5}$
- Cancel $(x+1)^3$:
$= \frac{1}{(x+1)^2}$
✔ Answer: $\boxed{\frac{1}{(x+1)^2}}$
---
4. $\frac{(3x - 2)^6}{(3x - 2)^4}$
- Cancel $(3x - 2)^4$:
$= (3x - 2)^2$
✔ Answer: $\boxed{(3x - 2)^2}$
---
5. $\frac{2n - 3}{3 - 2n}$
- Notice: $3 - 2n = -(2n - 3)$
- So:
$= \frac{2n - 3}{-(2n - 3)} = -1$
✔ Answer: $\boxed{-1}$
---
6. $\frac{15y^2(y + 3)}{20y^3(y + 3)}$
- Cancel $y^2$, $(y+3)$:
$= \frac{15}{20y} = \frac{3}{4y}$
✔ Answer: $\boxed{\frac{3}{4y}}$
---
7. $\frac{15y(y + 1)}{45y^2(y + 1)}$
- Cancel $15y(y+1)$:
$= \frac{1}{3y}$
✔ Answer: $\boxed{\frac{1}{3y}}$
---
8. $\frac{24x^3(4 - x)}{18x(4 - x)}$
- Cancel $6x(4 - x)$:
$= \frac{24x^3}{18x} = \frac{4x^2}{3}$
✔ Answer: $\boxed{\frac{4x^2}{3}}$
---
9. $\frac{6x^3(2 - x)}{12x(2 - x)}$
- Cancel $6x(2 - x)$:
$= \frac{x^2}{2}$
✔ Answer: $\boxed{\frac{x^2}{2}}$
---
10. $\frac{12x^2(5 - 2x)}{18x(2x - 5)}$
- Note: $2x - 5 = -(5 - 2x)$
- So:
$= \frac{12x^2(5 - 2x)}{18x \cdot (-(5 - 2x))} = \frac{12x^2}{-18x} = -\frac{2x}{3}$
✔ Answer: $\boxed{-\frac{2x}{3}}$
---
11. $\frac{a^2 + 6a}{ac + 6c}$
- Factor numerator: $a(a + 6)$
- Denominator: $c(a + 6)$
- Cancel $(a + 6)$:
$= \frac{a}{c}$
✔ Answer: $\boxed{\frac{a}{c}}$
---
12. $\frac{x^2 + 4x}{3x + 12}$
- Numerator: $x(x + 4)$
- Denominator: $3(x + 4)$
- Cancel $(x + 4)$:
$= \frac{x}{3}$
✔ Answer: $\boxed{\frac{x}{3}}$
---
13. $\frac{6 - 8x}{4x^2 - 3x}$
- Numerator: $-2(4x - 3)$
- Denominator: $x(4x - 3)$
- Cancel $(4x - 3)$:
$= \frac{-2}{x}$
✔ Answer: $\boxed{-\frac{2}{x}}$
---
14. $\frac{x^2 + 2x - 15}{x^2 - 10x + 21}$
- Factor:
Numerator: $(x + 5)(x - 3)$
Denominator: $(x - 7)(x - 3)$
- Cancel $(x - 3)$:
$= \frac{x + 5}{x - 7}$
✔ Answer: $\boxed{\frac{x + 5}{x - 7}}$
---
15. $\frac{x^2 - 2x - 3}{x^2 - 5x - 6}$
- Numerator: $(x - 3)(x + 1)$
- Denominator: $(x - 6)(x + 1)$
- Cancel $(x + 1)$:
$= \frac{x - 3}{x - 6}$
✔ Answer: $\boxed{\frac{x - 3}{x - 6}}$
---
16. $\frac{x^2 - 7x + 12}{x^2 - x - 12}$
- Numerator: $(x - 3)(x - 4)$
- Denominator: $(x - 4)(x + 3)$
- Cancel $(x - 4)$:
$= \frac{x - 3}{x + 3}$
✔ Answer: $\boxed{\frac{x - 3}{x + 3}}$
---
17. $\frac{x^2 - 3x - 10}{x^2 - 6x + 5}$
- Numerator: $(x - 5)(x + 2)$
- Denominator: $(x - 5)(x - 1)$
- Cancel $(x - 5)$:
$= \frac{x + 2}{x - 1}$
✔ Answer: $\boxed{\frac{x + 2}{x - 1}}$
---
18. $\frac{x^2 - 8x + 16}{x^2 - 9x + 20}$
- Numerator: $(x - 4)^2$
- Denominator: $(x - 4)(x - 5)$
- Cancel $(x - 4)$:
$= \frac{x - 4}{x - 5}$
✔ Answer: $\boxed{\frac{x - 4}{x - 5}}$
---
19. $\frac{x^2 - 7x + 10}{x^2 - 4x - 5}$
- Numerator: $(x - 2)(x - 5)$
- Denominator: $(x - 5)(x + 1)$
- Cancel $(x - 5)$:
$= \frac{x - 2}{x + 1}$
✔ Answer: $\boxed{\frac{x - 2}{x + 1}}$
---
20. $\frac{x^2 + 6x + 9}{x^2 + 2x - 3}$
- Numerator: $(x + 3)^2$
- Denominator: $(x + 3)(x - 1)$
- Cancel $(x + 3)$:
$= \frac{x + 3}{x - 1}$
✔ Answer: $\boxed{\frac{x + 3}{x - 1}}$
---
21. $\frac{x^2 - 2x - 24}{16 - x^2}$
- Numerator: $(x - 6)(x + 4)$
- Denominator: $-(x^2 - 16) = -(x - 4)(x + 4)$
- Cancel $(x + 4)$:
$= \frac{x - 6}{-(x - 4)} = -\frac{x - 6}{x - 4}$
✔ Answer: $\boxed{-\frac{x - 6}{x - 4}}$
---
22. $\frac{9 - y^2}{y^2 + 2y - 15}$
- Numerator: $-(y^2 - 9) = -(y - 3)(y + 3)$
- Denominator: $(y + 5)(y - 3)$
- Cancel $(y - 3)$:
$= \frac{-(y + 3)}{y + 5} = -\frac{y + 3}{y + 5}$
✔ Answer: $\boxed{-\frac{y + 3}{y + 5}}$
---
23. $\frac{3x^3 + 18x^2 - 21x}{x^3 + 5x^2 - 14x}$
- Factor out $x$ from both:
$= \frac{x(3x^2 + 18x - 21)}{x(x^2 + 5x - 14)} = \frac{3x^2 + 18x - 21}{x^2 + 5x - 14}$
Now factor:
- Numerator: $3(x^2 + 6x - 7) = 3(x + 7)(x - 1)$
- Denominator: $(x + 7)(x - 2)$
Cancel $(x + 7)$:
$= \frac{3(x - 1)}{x - 2}$
✔ Answer: $\boxed{\frac{3(x - 1)}{x - 2}}$
---
24. $\frac{2x^2 - 18x}{4x^3 - 32x^2 - 36x}$
- Factor numerator: $2x(x - 9)$
- Denominator: $4x(x^2 - 8x - 9) = 4x(x - 9)(x + 1)$
- Cancel $2x(x - 9)$:
$= \frac{1}{2(x + 1)}$
✔ Answer: $\boxed{\frac{1}{2(x + 1)}}$
---
25. $\frac{5x^2 - 11x + 2}{5x^2 - 7x - 6}$
Try factoring:
- Numerator: $5x^2 - 11x + 2 = (5x - 1)(x - 2)$
Check: $5x \cdot x = 5x^2$, $5x(-2) + (-1)x = -10x - x = -11x$, $(-1)(-2)=2$ → ✔
- Denominator: $5x^2 - 7x - 6 = (5x + 3)(x - 2)$
Check: $5x \cdot x = 5x^2$, $5x(-2) + 3x = -10x + 3x = -7x$, $3 \cdot (-2) = -6$ → ✔
Cancel $(x - 2)$:
$= \frac{5x - 1}{5x + 3}$
✔ Answer: $\boxed{\frac{5x - 1}{5x + 3}}$
---
26. $\frac{2x^2 - 7x + 3}{2x^2 + 9x - 5}$
Factor:
- Numerator: $2x^2 - 7x + 3 = (2x - 1)(x - 3)$
Check: $2x \cdot x = 2x^2$, $2x(-3) + (-1)x = -6x - x = -7x$, $(-1)(-3)=3$ → ✔
- Denominator: $2x^2 + 9x - 5 = (2x - 1)(x + 5)$
Check: $2x \cdot x = 2x^2$, $2x(5) + (-1)x = 10x - x = 9x$, $(-1)(5) = -5$ → ✔
Cancel $(2x - 1)$:
$= \frac{x - 3}{x + 5}$
✔ Answer: $\boxed{\frac{x - 3}{x + 5}}$
---
27. $\frac{x^2 + 2x - 24}{12 - 4x - x^2}$
Rewrite denominator:
$12 - 4x - x^2 = -x^2 - 4x + 12 = -(x^2 + 4x - 12)$
Factor:
- Numerator: $x^2 + 2x - 24 = (x + 6)(x - 4)$
- Denominator: $-(x^2 + 4x - 12) = -(x + 6)(x - 2)$
So expression:
$\frac{(x + 6)(x - 4)}{-(x + 6)(x - 2)} = \frac{x - 4}{-(x - 2)} = -\frac{x - 4}{x - 2}$
✔ Answer: $\boxed{-\frac{x - 4}{x - 2}}$
---
28. $\frac{2x^2 - 8}{x^2 + 4x - 12}$
- Numerator: $2(x^2 - 4) = 2(x - 2)(x + 2)$
- Denominator: $(x + 6)(x - 2)$
- Cancel $(x - 2)$:
$= \frac{2(x + 2)}{x + 6}$
✔ Answer: $\boxed{\frac{2(x + 2)}{x + 6}}$
---
29. $\frac{2x^2 - 9x + 7}{x^2 + 2x - 3}$
Factor:
- Numerator: $2x^2 - 9x + 7 = (2x - 7)(x - 1)$
Check: $2x \cdot x = 2x^2$, $2x(-1) + (-7)x = -2x -7x = -9x$, $(-7)(-1)=7$ → ✔
- Denominator: $(x + 3)(x - 1)$
Cancel $(x - 1)$:
$= \frac{2x - 7}{x + 3}$
✔ Answer: $\boxed{\frac{2x - 7}{x + 3}}$
---
30. $\frac{8x^2 - 14x + 6}{4x - 3}$
Factor numerator:
$8x^2 - 14x + 6 = 2(4x^2 - 7x + 3)$
Now factor $4x^2 - 7x + 3$:
$(4x - 3)(x - 1)$ → check: $4x \cdot x = 4x^2$, $4x(-1) + (-3)x = -4x -3x = -7x$, $(-3)(-1)=3$ → ✔
So numerator: $2(4x - 3)(x - 1)$
Denominator: $4x - 3$
Cancel $(4x - 3)$:
$= 2(x - 1)$
✔ Answer: $\boxed{2(x - 1)}$
---
## ✔ Final Answers:
| Problem | Answer |
|--------|--------|
| 1 | $\frac{2}{3x^2}$ |
| 2 | $\frac{3x}{4y^2}$ |
| 3 | $\frac{1}{(x+1)^2}$ |
| 4 | $(3x - 2)^2$ |
| 5 | $-1$ |
| 6 | $\frac{3}{4y}$ |
| 7 | $\frac{1}{3y}$ |
| 8 | $\frac{4x^2}{3}$ |
| 9 | $\frac{x^2}{2}$ |
| 10 | $-\frac{2x}{3}$ |
| 11 | $\frac{a}{c}$ |
| 12 | $\frac{x}{3}$ |
| 13 | $-\frac{2}{x}$ |
| 14 | $\frac{x + 5}{x - 7}$ |
| 15 | $\frac{x - 3}{x - 6}$ |
| 16 | $\frac{x - 3}{x + 3}$ |
| 17 | $\frac{x + 2}{x - 1}$ |
| 18 | $\frac{x - 4}{x - 5}$ |
| 19 | $\frac{x - 2}{x + 1}$ |
| 20 | $\frac{x + 3}{x - 1}$ |
| 21 | $-\frac{x - 6}{x - 4}$ |
| 22 | $-\frac{y + 3}{y + 5}$ |
| 23 | $\frac{3(x - 1)}{x - 2}$ |
| 24 | $\frac{1}{2(x + 1)}$ |
| 25 | $\frac{5x - 1}{5x + 3}$ |
| 26 | $\frac{x - 3}{x + 5}$ |
| 27 | $-\frac{x - 4}{x - 2}$ |
| 28 | $\frac{2(x + 2)}{x + 6}$ |
| 29 | $\frac{2x - 7}{x + 3}$ |
| 30 | $2(x - 1)$ |
Let me know if you'd like this formatted as a printable answer key!
Parent Tip: Review the logic above to help your child master the concept of simplifying rational expressions worksheet key.
