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Trigonometry worksheet for finding angles using trigonometric ratios.

A worksheet titled "Using trigonometric ratios to find angles" with four exercises. Each exercise presents right-angled triangles with labeled sides and an angle to be found using trigonometric ratios, requiring answers to two decimal places. Worked examples are provided for exercises 1, 2, and 3.

A worksheet titled "Using trigonometric ratios to find angles" with four exercises. Each exercise presents right-angled triangles with labeled sides and an angle to be found using trigonometric ratios, requiring answers to two decimal places. Worked examples are provided for exercises 1, 2, and 3.

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Show Answer Key & Explanations Step-by-step solution for: HZCIS Math-Trig SohCahToa practice questions (optional)
We are given a worksheet titled “Using trigonometric ratios to find angles”, and we need to find the marked angles (θ, α, β, a, b, c, d, e, f) in each right-angled triangle using trigonometry. All answers should be correct to 2 decimal places.

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## 🔑 Key Trigonometric Ratios (SOHCAHTOA):

In a right-angled triangle:
- sin(θ) = Opposite / Hypotenuse
- cos(θ) = Adjacent / Hypotenuse
- tan(θ) = Opposite / Adjacent

To find the angle θ, we use the inverse functions:
- θ = arcsin(Opp/Hyp)
- θ = arccos(Adj/Hyp)
- θ = arctan(Opp/Adj)

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# Problem 1: Find θ

a)


Opposite = 4.8, Hypotenuse = 5.2
→ Use sin(θ) = Opp/Hyp = 4.8 / 5.2

> θ = arcsin(4.8 / 5.2) ≈ arcsin(0.9230769) ≈ 67.38°

Answer: 67.38°

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b)


Adjacent = 3.2, Hypotenuse = 4.7
→ Use cos(θ) = Adj/Hyp = 3.2 / 4.7

> θ = arccos(3.2 / 4.7) ≈ arccos(0.680851) ≈ 47.09°

Answer: 47.09°

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c)


Opposite = 8, Adjacent = 3
→ Use tan(θ) = Opp/Adj = 8 / 3 ≈ 2.6667

> θ = arctan(8 / 3) ≈ arctan(2.6667) ≈ 69.44°

Answer: 69.44°

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# Problem 2: Find θ or β

a)


Opposite = 17, Adjacent = 12
→ tan(θ) = 17 / 12 ≈ 1.4167

> θ = arctan(17/12) ≈ 54.78°

Answer: 54.78°

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b)


This is a right triangle with hypotenuse = 7.2 m, adjacent to β = 4 m
→ cos(β) = Adj/Hyp = 4 / 7.2 ≈ 0.5556

> β = arccos(4 / 7.2) ≈ 56.25°

Answer: 56.25°

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c)


Adjacent = 10, Hypotenuse = 12
→ cos(θ) = 10 / 12 ≈ 0.8333

> θ = arccos(10 / 12) ≈ 33.56°

Answer: 33.56°

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# Problem 3: Find θ or α

a)


Opposite = ? Wait — hypotenuse = 8, adjacent = 2
→ cos(θ) = Adj/Hyp = 2 / 8 = 0.25

> θ = arccos(2 / 8) = arccos(0.25) ≈ 75.52°

Answer: 75.52°

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b)


Hypotenuse = 5 m, adjacent to α = 3 m
→ cos(α) = 3 / 5 = 0.6

> α = arccos(0.6) ≈ 53.13°

Answer: 53.13°

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c)


Opposite = 2.7, Adjacent = 3.5
→ tan(α) = 2.7 / 3.5 ≈ 0.7714

> α = arctan(2.7 / 3.5) ≈ 37.62°

Answer: 37.62°

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# Problem 4: Find a, b, c, d, e, f

a)


Right triangle: opposite to angle a = 13.5, adjacent = 15.3
→ tan(a) = 13.5 / 15.3 ≈ 0.8824

> a = arctan(13.5 / 15.3) ≈ 41.41°

Answer: 41.41°

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b)


Right triangle: opposite to angle c = 77.3, hypotenuse = 89.4
→ sin(c) = 77.3 / 89.4 ≈ 0.8647

> c = arcsin(77.3 / 89.4) ≈ 59.85°

Answer: 59.85°

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c)


Right triangle: adjacent to angle b = 92.7, hypotenuse = 106.4
→ cos(b) = 92.7 / 106.4 ≈ 0.8713

> b = arccos(92.7 / 106.4) ≈ 29.38°

Answer: 29.38°

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d)


Right triangle: opposite to angle d = 18.7, hypotenuse = 43.7
→ sin(d) = 18.7 / 43.7 ≈ 0.4279

> d = arcsin(18.7 / 43.7) ≈ 25.34°

Answer: 25.34°

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e)


Right triangle: adjacent to angle e = 13.85, hypotenuse = 18.56
→ cos(e) = 13.85 / 18.56 ≈ 0.7462

> e = arccos(13.85 / 18.56) ≈ 41.73°

Answer: 41.73°

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f)


Right triangle: adjacent to angle α = 9.8 cm, hypotenuse = 12.2 cm
→ cos(α) = 9.8 / 12.2 ≈ 0.8033

> α = arccos(9.8 / 12.2) ≈ 36.54°

Answer: 36.54°

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# 📋 Final Answers:

## Problem 1:
a) 67.38°
b) 47.09°
c) 69.44°

## Problem 2:
a) 54.78°
b) 56.25°
c) 33.56°

## Problem 3:
a) 75.52°
b) 53.13°
c) 37.62°

## Problem 4:
a) 41.41°
b) 59.85°
c) 29.38°
d) 25.34°
e) 41.73°
f) 36.54°

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All answers are rounded to 2 decimal places as required.

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