Free Printable Solubility Worksheets - Free Printable

Let's go through each question step by step and solve the problems with clear explanations.

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1. Match the following. Write the correct letter in the blank provided.

| Term | Matching Letter |
|-------------|-----------------|
| 1. Solute | B |
| 2. Solvent | E |
| 3. Dissolve | D |
| 4. Stirring | C |
| 5. Concentration | A |

Explanation:
- Solute (B): The substance that dissolves into the solution.
- Solvent (E): The substance that does the dissolving (e.g., water).
- Dissolve (D): When a solute disappears into the solvent.
- Stirring (C): Increases the rate of dissolution by moving molecules faster.
- Concentration (A): Tells how much solute is dissolved in the solution.

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2. Determine if the following statements are true or false.

a. Solubility increases if you stir a solute into a solution.
✘ False
→ Stirring speeds up the rate of dissolving, but it does not change the solubility (the maximum amount that can dissolve). Solubility is a physical property dependent on temperature and pressure.

b. All solutes have the same solubility in a given solvent.
✘ False
→ Different solutes have different solubilities in the same solvent. For example, sugar is more soluble in water than sand.

c. There is a limit on the amount of solute that can dissolve in a given solvent.
✔ True
→ This is the definition of solubility. Once this limit is reached, the solution is saturated.

d. You can dissolve additional solutes in an unsaturated solution.
✔ True
→ An unsaturated solution can dissolve more solute.

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3. Give three ways to make sugar dissolve faster.

✔ Stirring, heating the solution, and using powdered sugar (smaller particles)

Explanation:
- Stirring increases contact between solute and solvent.
- Heating increases molecular motion.
- Smaller particles have more surface area exposed to the solvent.

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4. Which one will dissolve faster? Circle the correct answer.

a. Powdered sugar ✔
→ Smaller particles dissolve faster due to greater surface area.

b. In hot water ✔
→ Higher temperature increases kinetic energy, speeding up dissolution.

c. Stirred ✔
→ Stirring helps distribute solute particles.

d. Small particles ✔
→ More surface area = faster dissolution.

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5. 65 g of sugar is dissolved in 750 ml of water. What is the concentration of the solution?

We calculate concentration as:

$$
\text{Concentration} = \frac{\text{mass of solute}}{\text{volume of solution}} = \frac{65\ \text{g}}{750\ \text{ml}}
$$

$$
= 0.0867\ \text{g/ml}
$$

Or express as grams per milliliter:
$$
\boxed{0.0867\ \text{g/mL}}
$$

Alternatively, you might express it as g/100 mL for comparison:
$$
\frac{65}{750} \times 100 = 8.67\ \text{g/100 mL}
$$

So, 8.67 g/100 mL is also acceptable depending on context.

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6. Which is more concentrated: 34 g of salt in 100 ml of water or 100 g of salt in 1500 ml of water?

Let’s calculate concentration for both:

- First solution:
$$
\frac{34\ \text{g}}{100\ \text{mL}} = 0.34\ \text{g/mL}
$$

- Second solution:
$$
\frac{100\ \text{g}}{1500\ \text{mL}} = 0.0667\ \text{g/mL}
$$

Compare:
0.34 > 0.0667 → So, 34 g in 100 mL is more concentrated.

✔ Answer: 34 g of salt in 100 mL of water is more concentrated.

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7. If the solubility of salt in water was determined to be 0.5 g/ml, would a solution with 50 g of salt in 150 ml of water be considered saturated?

First, calculate how much salt can dissolve in 150 mL based on solubility:

$$
\text{Maximum solute} = 0.5\ \text{g/mL} \times 150\ \text{mL} = 75\ \text{g}
$$

But only 50 g is dissolved.

Since 50 g < 75 g, the solution is unsaturated.

✔ Answer: No, it is not saturated because less salt is dissolved than the maximum possible.

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✔ Final Answers Summary:

1.
1-B, 2-E, 3-D, 4-C, 5-A

2.
a. False
b. False
c. True
d. True

3. Stirring, heating, using smaller particles (powdered sugar)

4.
a. Powdered sugar
b. In hot water
c. Stirred
d. Small particles

5. 0.0867 g/mL or 8.67 g/100 mL

6. 34 g of salt in 100 mL of water is more concentrated.

7. No, the solution is not saturated.

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