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Example:
- Formula: q = m x c x ΔT
- Given: m = 50 g, c = 0.129 J/g°C, ΔT = 29.3°C - 115°C = -85.7°C
- Calculation: q = 50 g × 0.129 J/g°C × (-85.7°C) = -552.765 J
- Answer: q metal = -553 J (rounded to three significant figures)
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Problem 1:
- Formula: q = m x c x ΔT
- Given: m = 34.4 g, c = 2.44 J/g°C, ΔT = 78.8°C - 25°C = 53.8°C
- Calculation: q = 34.4 g × 2.44 J/g°C × 53.8°C = 4533.3248 J
- Answer: 4530 J (rounded to three significant figures)
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Problem 2:
- Formula: c = q / (m x ΔT)
- Given: q = 1728 J, m = 3 g, ΔT = 662°C - 20°C = 642°C
- Calculation: c = 1728 J / (3 g × 642°C) = 0.898 J/g°C
- Answer: 0.90 J/g°C (rounded to two significant figures)
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Problem 3:
- Formula: c = q / (m x ΔT)
- Given: q = 240 J, m = 5 g, ΔT = 200°C
- Calculation: c = 240 J / (5 g × 200°C) = 0.24 J/g°C
- Answer: 0.24 J/g°C
Parent Tip: Review the logic above to help your child master the concept of specific heat and heat capacity worksheet.
