Square Roots of Perfect Squares | Interactive Worksheet ... - Free Printable

Problem:

The task is to evaluate the square root of each perfect square listed in the image. Here are the numbers provided:

1. \( \sqrt{9} \)
2. \( \sqrt{100} \)
3. \( \sqrt{36} \)
4. \( \sqrt{16} \)
5. \( \sqrt{7} \)
6. \( \sqrt{25} \)
7. \( \sqrt{144} \)
8. \( \sqrt{81} \)
9. \( \sqrt{64} \)
10. \( \sqrt{400} \)
11. \( \sqrt{121} \)
12. \( \sqrt{225} \)
13. \( \sqrt{900} \)
14. \( \sqrt{196} \)
15. \( \sqrt{49} \)
16. \( \sqrt{289} \)
17. \( \sqrt{625} \)
18. \( \sqrt{324} \)

Solution:

To solve this, we need to find the square root of each number. The square root of a number \( x \) is a value \( y \) such that \( y^2 = x \). Let's calculate each one step by step.

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#### 1. \( \sqrt{9} \)
- \( 3^2 = 9 \)
- Therefore, \( \sqrt{9} = 3 \)

#### 2. \( \sqrt{100} \)
- \( 10^2 = 100 \)
- Therefore, \( \sqrt{100} = 10 \)

#### 3. \( \sqrt{36} \)
- \( 6^2 = 36 \)
- Therefore, \( \sqrt{36} = 6 \)

#### 4. \( \sqrt{16} \)
- \( 4^2 = 16 \)
- Therefore, \( \sqrt{16} = 4 \)

#### 5. \( \sqrt{7} \)
- Note: 7 is not a perfect square, so its square root is an irrational number.
- However, since the task specifies "perfect squares," we can assume this might be a typo or error. For now, we'll leave it as \( \sqrt{7} \).

#### 6. \( \sqrt{25} \)
- \( 5^2 = 25 \)
- Therefore, \( \sqrt{25} = 5 \)

#### 7. \( \sqrt{144} \)
- \( 12^2 = 144 \)
- Therefore, \( \sqrt{144} = 12 \)

#### 8. \( \sqrt{81} \)
- \( 9^2 = 81 \)
- Therefore, \( \sqrt{81} = 9 \)

#### 9. \( \sqrt{64} \)
- \( 8^2 = 64 \)
- Therefore, \( \sqrt{64} = 8 \)

#### 10. \( \sqrt{400} \)
- \( 20^2 = 400 \)
- Therefore, \( \sqrt{400} = 20 \)

#### 11. \( \sqrt{121} \)
- \( 11^2 = 121 \)
- Therefore, \( \sqrt{121} = 11 \)

#### 12. \( \sqrt{225} \)
- \( 15^2 = 225 \)
- Therefore, \( \sqrt{225} = 15 \)

#### 13. \( \sqrt{900} \)
- \( 30^2 = 900 \)
- Therefore, \( \sqrt{900} = 30 \)

#### 14. \( \sqrt{196} \)
- \( 14^2 = 196 \)
- Therefore, \( \sqrt{196} = 14 \)

#### 15. \( \sqrt{49} \)
- \( 7^2 = 49 \)
- Therefore, \( \sqrt{49} = 7 \)

#### 16. \( \sqrt{289} \)
- \( 17^2 = 289 \)
- Therefore, \( \sqrt{289} = 17 \)

#### 17. \( \sqrt{625} \)
- \( 25^2 = 625 \)
- Therefore, \( \sqrt{625} = 25 \)

#### 18. \( \sqrt{324} \)
- \( 18^2 = 324 \)
- Therefore, \( \sqrt{324} = 18 \)

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Final Answers:

\[
\begin{aligned}
1. & \quad \sqrt{9} = 3 \\
2. & \quad \sqrt{100} = 10 \\
3. & \quad \sqrt{36} = 6 \\
4. & \quad \sqrt{16} = 4 \\
5. & \quad \sqrt{7} = \sqrt{7} \quad (\text{not a perfect square}) \\
6. & \quad \sqrt{25} = 5 \\
7. & \quad \sqrt{144} = 12 \\
8. & \quad \sqrt{81} = 9 \\
9. & \quad \sqrt{64} = 8 \\
10. & \quad \sqrt{400} = 20 \\
11. & \quad \sqrt{121} = 11 \\
12. & \quad \sqrt{225} = 15 \\
13. & \quad \sqrt{900} = 30 \\
14. & \quad \sqrt{196} = 14 \\
15. & \quad \sqrt{49} = 7 \\
16. & \quad \sqrt{289} = 17 \\
17. & \quad \sqrt{625} = 25 \\
18. & \quad \sqrt{324} = 18 \\
\end{aligned}
\]

Boxed Final Answer:

\[
\boxed{
\begin{aligned}
1. & \quad 3 \\
2. & \quad 10 \\
3. & \quad 6 \\
4. & \quad 4 \\
5. & \quad \sqrt{7} \\
6. & \quad 5 \\
7. & \quad 12 \\
8. & \quad 9 \\
9. & \quad 8 \\
10. & \quad 20 \\
11. & \quad 11 \\
12. & \quad 15 \\
13. & \quad 30 \\
14. & \quad 14 \\
15. & \quad 7 \\
16. & \quad 17 \\
17. & \quad 25 \\
18. & \quad 18 \\
\end{aligned}
}
\]