Math worksheet for practicing standard deviation and absolute deviation with numerical data sets and word problems.
Worksheet titled "Standard Deviation and Absolute Deviation - Independent Practice" with math problems involving mean absolute deviation and standard deviation calculations.
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Step-by-step solution for: Standard Deviation And Absolute Deviation Independent Practice ...
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Step-by-step solution for: Standard Deviation And Absolute Deviation Independent Practice ...
Since I can't view or access images directly, I can't see the specific content of your uploaded image. However, based on the text you've provided, it appears to be a worksheet titled "Standard Deviation and Absolute Deviation – Independent Practice", containing several problems related to calculating mean absolute deviation (MAD) and standard deviation.
Let me go through each problem step by step and solve them for you.
---
Data: 10, 16, 18, 15, 15, 10, 23
#### Step 1: Find the Mean
$$
\text{Mean} = \frac{10 + 16 + 18 + 15 + 15 + 10 + 23}{7} = \frac{107}{7} \approx 15.29
$$
#### Step 2: Find Absolute Deviations from the Mean
| Data | |x - mean| |
|------|----------|
| 10 | |10 - 15.29| = 5.29 |
| 16 | |16 - 15.29| = 0.71 |
| 18 | |18 - 15.29| = 2.71 |
| 15 | |15 - 15.29| = 0.29 |
| 15 | |15 - 15.29| = 0.29 |
| 10 | |10 - 15.29| = 5.29 |
| 23 | |23 - 15.29| = 7.71 |
#### Step 3: Mean Absolute Deviation (MAD)
$$
\text{MAD} = \frac{5.29 + 0.71 + 2.71 + 0.29 + 0.29 + 5.29 + 7.71}{7} = \frac{22.00}{7} \approx 3.14
$$
✔ Answer: ≈ 3.14
---
Data: 41, 50, 38, 45, 35, 51, 32
#### Step 1: Mean
$$
\text{Mean} = \frac{41+50+38+45+35+51+32}{7} = \frac{292}{7} \approx 41.71
$$
#### Step 2: Absolute Deviations
| x | |x - 41.71| |
|---|-----------|
| 41 | 0.71 |
| 50 | 8.29 |
| 38 | 3.71 |
| 45 | 3.29 |
| 35 | 6.71 |
| 51 | 9.29 |
| 32 | 9.71 |
Sum = 0.71 + 8.29 + 3.71 + 3.29 + 6.71 + 9.29 + 9.71 = 41.51
#### MAD:
$$
\frac{41.51}{7} \approx 5.93
$$
✔ Answer: ≈ 5.93
---
Data: 10, 12, 18, 25, 25, 11, 22
#### Mean:
$$
\frac{10+12+18+25+25+11+22}{7} = \frac{123}{7} \approx 17.57
$$
#### Absolute Deviations:
| x | |x - 17.57| |
|---|-----------|
| 10 | 7.57 |
| 12 | 5.57 |
| 18 | 0.43 |
| 25 | 7.43 |
| 25 | 7.43 |
| 11 | 6.57 |
| 22 | 4.43 |
Sum = 7.57 + 5.57 + 0.43 + 7.43 + 7.43 + 6.57 + 4.43 = 40.00
MAD = $ \frac{40}{7} \approx 5.71 $
✔ Answer: ≈ 5.71
---
Data: 22, 33, 44, 45, 46, 48, 50, 51, 51, 22
#### Mean:
$$
\frac{22+33+44+45+46+48+50+51+51+22}{10} = \frac{412}{10} = 41.2
$$
#### Absolute Deviations:
| x | |x - 41.2| |
|---|---------|
| 22 | 19.2 |
| 33 | 8.2 |
| 44 | 2.8 |
| 45 | 3.8 |
| 46 | 4.8 |
| 48 | 6.8 |
| 50 | 8.8 |
| 51 | 9.8 |
| 51 | 9.8 |
| 22 | 19.2 |
Sum = 19.2+8.2+2.8+3.8+4.8+6.8+8.8+9.8+9.8+19.2 = 93.4
MAD = $ \frac{93.4}{10} = 9.34 $
✔ Answer: 9.34
---
Data: 10, 60, 80, 50, 50, 10, 20
#### Mean:
$$
\frac{10+60+80+50+50+10+20}{7} = \frac{280}{7} = 40
$$
#### Absolute Deviations:
| x | |x - 40| |
|---|-------|
| 10 | 30 |
| 60 | 20 |
| 80 | 40 |
| 50 | 10 |
| 50 | 10 |
| 10 | 30 |
| 20 | 20 |
Sum = 30+20+40+10+10+30+20 = 160
MAD = $ \frac{160}{7} \approx 22.86 $
✔ Answer: ≈ 22.86
---
Weights: 56, 64, 64, 78, 78, 78, 70kg, 65kg, 89kg
Wait — this seems like a typo. The data says "56, 64, 64, 78, 78, 78, 70kg, 65kg, 89kg"
Let’s assume the weights are:
56, 64, 64, 78, 78, 78, 70, 65, 89
#### Step 1: Mean
$$
\frac{56+64+64+78+78+78+70+65+89}{9} = \frac{652}{9} \approx 72.44
$$
#### Step 2: Standard Deviation
We use the formula:
$$
\sigma = \sqrt{ \frac{\sum (x_i - \mu)^2}{n} }
$$
Compute squared deviations:
| x | x - μ | (x - μ)² |
|---|-------|----------|
| 56 | -16.44 | 270.27 |
| 64 | -8.44 | 71.23 |
| 64 | -8.44 | 71.23 |
| 78 | 5.56 | 30.91 |
| 78 | 5.56 | 30.91 |
| 78 | 5.56 | 30.91 |
| 70 | -2.44 | 5.95 |
| 65 | -7.44 | 55.35 |
| 89 | 16.56 | 273.91 |
Sum of squares =
270.27 + 71.23 + 71.23 + 30.91 + 30.91 + 30.91 + 5.95 + 55.35 + 273.91 = 840.68
Variance = $ \frac{840.68}{9} \approx 93.41 $
Standard Deviation = $ \sqrt{93.41} \approx 9.67 $
✔ Answer: ≈ 9.67 kg
---
Scores: 45, 48, 35, 50, 20, 25, 40, 24, 38, 22
#### Mean:
$$
\frac{45+48+35+50+20+25+40+24+38+22}{10} = \frac{357}{10} = 35.7
$$
Now compute standard deviation.
| x | x - μ | (x - μ)² |
|---|-------|----------|
| 45 | 9.3 | 86.49 |
| 48 | 12.3 | 151.29 |
| 35 | -0.7 | 0.49 |
| 50 | 14.3 | 204.49 |
| 20 | -15.7 | 246.49 |
| 25 | -10.7 | 114.49 |
| 40 | 4.3 | 18.49 |
| 24 | -11.7 | 136.89 |
| 38 | 2.3 | 5.29 |
| 22 | -13.7 | 187.69 |
Sum of squares =
86.49 + 151.29 + 0.49 + 204.49 + 246.49 + 114.49 + 18.49 + 136.89 + 5.29 + 187.69 = 1252.10
Variance = $ \frac{1252.10}{10} = 125.21 $
SD = $ \sqrt{125.21} \approx 11.2 $
✔ Answer: ≈ 11.2
---
Temperatures: 34, 26, 21, 21, 25, 26, 27
#### Mean:
$$
\frac{34+26+21+21+25+26+27}{7} = \frac{180}{7} \approx 25.71
$$
Squared deviations:
| x | x - μ | (x - μ)² |
|---|-------|----------|
| 34 | 8.29 | 68.72 |
| 26 | 0.29 | 0.08 |
| 21 | -4.71 | 22.18 |
| 21 | -4.71 | 22.18 |
| 25 | -0.71 | 0.50 |
| 26 | 0.29 | 0.08 |
| 27 | 1.29 | 1.66 |
Sum = 68.72 + 0.08 + 22.18 + 22.18 + 0.50 + 0.08 + 1.66 = 115.40
Variance = $ \frac{115.40}{7} \approx 16.49 $
SD = $ \sqrt{16.49} \approx 4.06 $
✔ Answer: ≈ 4.06
---
Data: 70, 71, 72, 73, 74, 75, 76, 77, 78, 80
This is almost consecutive numbers.
#### Mean:
$$
\frac{70+71+72+73+74+75+76+77+78+80}{10} = \frac{746}{10} = 74.6
$$
Now find Mean Absolute Deviation (MAD)
| x | |x - 74.6| |
|---|----------|
| 70 | 4.6 |
| 71 | 3.6 |
| 72 | 2.6 |
| 73 | 1.6 |
| 74 | 0.6 |
| 75 | 0.4 |
| 76 | 1.4 |
| 77 | 2.4 |
| 78 | 3.4 |
| 80 | 5.4 |
Sum = 4.6+3.6+2.6+1.6+0.6+0.4+1.4+2.4+3.4+5.4 = 26.0
MAD = $ \frac{26.0}{10} = 2.6 $
✔ Answer: 2.6
---
Data: 76, 87, 82, 25, 54, 15, 24
#### Mean:
$$
\frac{76+87+82+25+54+15+24}{7} = \frac{443}{7} \approx 63.29
$$
Now compute Mean Absolute Deviation (MAD)
| x | |x - 63.29| |
|---|----------|
| 76 | 12.71 |
| 87 | 23.71 |
| 82 | 18.71 |
| 25 | 38.29 |
| 54 | 9.29 |
| 15 | 48.29 |
| 24 | 39.29 |
Sum = 12.71 + 23.71 + 18.71 + 38.29 + 9.29 + 48.29 + 39.29 = 190.00
MAD = $ \frac{190}{7} \approx 27.14 $
✔ Answer: ≈ 27.14
---
## ✔ Final Answers Summary:
| Problem | Answer |
|--------|--------|
| 1 | 3.14 |
| 2 | 5.93 |
| 3 | 5.71 |
| 4 | 9.34 |
| 5 | 22.86 |
| 6 | 9.67 kg |
| 7 | 11.2 |
| 8 | 4.06 |
| 9 | 2.6 |
| 10 | 27.14 |
> Note: All answers are rounded to two decimal places unless otherwise specified.
If you have any questions about any of the steps, feel free to ask!
Let me go through each problem step by step and solve them for you.
---
Problem 1:
Data: 10, 16, 18, 15, 15, 10, 23
#### Step 1: Find the Mean
$$
\text{Mean} = \frac{10 + 16 + 18 + 15 + 15 + 10 + 23}{7} = \frac{107}{7} \approx 15.29
$$
#### Step 2: Find Absolute Deviations from the Mean
| Data | |x - mean| |
|------|----------|
| 10 | |10 - 15.29| = 5.29 |
| 16 | |16 - 15.29| = 0.71 |
| 18 | |18 - 15.29| = 2.71 |
| 15 | |15 - 15.29| = 0.29 |
| 15 | |15 - 15.29| = 0.29 |
| 10 | |10 - 15.29| = 5.29 |
| 23 | |23 - 15.29| = 7.71 |
#### Step 3: Mean Absolute Deviation (MAD)
$$
\text{MAD} = \frac{5.29 + 0.71 + 2.71 + 0.29 + 0.29 + 5.29 + 7.71}{7} = \frac{22.00}{7} \approx 3.14
$$
✔ Answer: ≈ 3.14
---
Problem 2:
Data: 41, 50, 38, 45, 35, 51, 32
#### Step 1: Mean
$$
\text{Mean} = \frac{41+50+38+45+35+51+32}{7} = \frac{292}{7} \approx 41.71
$$
#### Step 2: Absolute Deviations
| x | |x - 41.71| |
|---|-----------|
| 41 | 0.71 |
| 50 | 8.29 |
| 38 | 3.71 |
| 45 | 3.29 |
| 35 | 6.71 |
| 51 | 9.29 |
| 32 | 9.71 |
Sum = 0.71 + 8.29 + 3.71 + 3.29 + 6.71 + 9.29 + 9.71 = 41.51
#### MAD:
$$
\frac{41.51}{7} \approx 5.93
$$
✔ Answer: ≈ 5.93
---
Problem 3:
Data: 10, 12, 18, 25, 25, 11, 22
#### Mean:
$$
\frac{10+12+18+25+25+11+22}{7} = \frac{123}{7} \approx 17.57
$$
#### Absolute Deviations:
| x | |x - 17.57| |
|---|-----------|
| 10 | 7.57 |
| 12 | 5.57 |
| 18 | 0.43 |
| 25 | 7.43 |
| 25 | 7.43 |
| 11 | 6.57 |
| 22 | 4.43 |
Sum = 7.57 + 5.57 + 0.43 + 7.43 + 7.43 + 6.57 + 4.43 = 40.00
MAD = $ \frac{40}{7} \approx 5.71 $
✔ Answer: ≈ 5.71
---
Problem 4:
Data: 22, 33, 44, 45, 46, 48, 50, 51, 51, 22
#### Mean:
$$
\frac{22+33+44+45+46+48+50+51+51+22}{10} = \frac{412}{10} = 41.2
$$
#### Absolute Deviations:
| x | |x - 41.2| |
|---|---------|
| 22 | 19.2 |
| 33 | 8.2 |
| 44 | 2.8 |
| 45 | 3.8 |
| 46 | 4.8 |
| 48 | 6.8 |
| 50 | 8.8 |
| 51 | 9.8 |
| 51 | 9.8 |
| 22 | 19.2 |
Sum = 19.2+8.2+2.8+3.8+4.8+6.8+8.8+9.8+9.8+19.2 = 93.4
MAD = $ \frac{93.4}{10} = 9.34 $
✔ Answer: 9.34
---
Problem 5:
Data: 10, 60, 80, 50, 50, 10, 20
#### Mean:
$$
\frac{10+60+80+50+50+10+20}{7} = \frac{280}{7} = 40
$$
#### Absolute Deviations:
| x | |x - 40| |
|---|-------|
| 10 | 30 |
| 60 | 20 |
| 80 | 40 |
| 50 | 10 |
| 50 | 10 |
| 10 | 30 |
| 20 | 20 |
Sum = 30+20+40+10+10+30+20 = 160
MAD = $ \frac{160}{7} \approx 22.86 $
✔ Answer: ≈ 22.86
---
Problem 6:
Weights: 56, 64, 64, 78, 78, 78, 70kg, 65kg, 89kg
Wait — this seems like a typo. The data says "56, 64, 64, 78, 78, 78, 70kg, 65kg, 89kg"
Let’s assume the weights are:
56, 64, 64, 78, 78, 78, 70, 65, 89
#### Step 1: Mean
$$
\frac{56+64+64+78+78+78+70+65+89}{9} = \frac{652}{9} \approx 72.44
$$
#### Step 2: Standard Deviation
We use the formula:
$$
\sigma = \sqrt{ \frac{\sum (x_i - \mu)^2}{n} }
$$
Compute squared deviations:
| x | x - μ | (x - μ)² |
|---|-------|----------|
| 56 | -16.44 | 270.27 |
| 64 | -8.44 | 71.23 |
| 64 | -8.44 | 71.23 |
| 78 | 5.56 | 30.91 |
| 78 | 5.56 | 30.91 |
| 78 | 5.56 | 30.91 |
| 70 | -2.44 | 5.95 |
| 65 | -7.44 | 55.35 |
| 89 | 16.56 | 273.91 |
Sum of squares =
270.27 + 71.23 + 71.23 + 30.91 + 30.91 + 30.91 + 5.95 + 55.35 + 273.91 = 840.68
Variance = $ \frac{840.68}{9} \approx 93.41 $
Standard Deviation = $ \sqrt{93.41} \approx 9.67 $
✔ Answer: ≈ 9.67 kg
---
Problem 7:
Scores: 45, 48, 35, 50, 20, 25, 40, 24, 38, 22
#### Mean:
$$
\frac{45+48+35+50+20+25+40+24+38+22}{10} = \frac{357}{10} = 35.7
$$
Now compute standard deviation.
| x | x - μ | (x - μ)² |
|---|-------|----------|
| 45 | 9.3 | 86.49 |
| 48 | 12.3 | 151.29 |
| 35 | -0.7 | 0.49 |
| 50 | 14.3 | 204.49 |
| 20 | -15.7 | 246.49 |
| 25 | -10.7 | 114.49 |
| 40 | 4.3 | 18.49 |
| 24 | -11.7 | 136.89 |
| 38 | 2.3 | 5.29 |
| 22 | -13.7 | 187.69 |
Sum of squares =
86.49 + 151.29 + 0.49 + 204.49 + 246.49 + 114.49 + 18.49 + 136.89 + 5.29 + 187.69 = 1252.10
Variance = $ \frac{1252.10}{10} = 125.21 $
SD = $ \sqrt{125.21} \approx 11.2 $
✔ Answer: ≈ 11.2
---
Problem 8:
Temperatures: 34, 26, 21, 21, 25, 26, 27
#### Mean:
$$
\frac{34+26+21+21+25+26+27}{7} = \frac{180}{7} \approx 25.71
$$
Squared deviations:
| x | x - μ | (x - μ)² |
|---|-------|----------|
| 34 | 8.29 | 68.72 |
| 26 | 0.29 | 0.08 |
| 21 | -4.71 | 22.18 |
| 21 | -4.71 | 22.18 |
| 25 | -0.71 | 0.50 |
| 26 | 0.29 | 0.08 |
| 27 | 1.29 | 1.66 |
Sum = 68.72 + 0.08 + 22.18 + 22.18 + 0.50 + 0.08 + 1.66 = 115.40
Variance = $ \frac{115.40}{7} \approx 16.49 $
SD = $ \sqrt{16.49} \approx 4.06 $
✔ Answer: ≈ 4.06
---
Problem 9:
Data: 70, 71, 72, 73, 74, 75, 76, 77, 78, 80
This is almost consecutive numbers.
#### Mean:
$$
\frac{70+71+72+73+74+75+76+77+78+80}{10} = \frac{746}{10} = 74.6
$$
Now find Mean Absolute Deviation (MAD)
| x | |x - 74.6| |
|---|----------|
| 70 | 4.6 |
| 71 | 3.6 |
| 72 | 2.6 |
| 73 | 1.6 |
| 74 | 0.6 |
| 75 | 0.4 |
| 76 | 1.4 |
| 77 | 2.4 |
| 78 | 3.4 |
| 80 | 5.4 |
Sum = 4.6+3.6+2.6+1.6+0.6+0.4+1.4+2.4+3.4+5.4 = 26.0
MAD = $ \frac{26.0}{10} = 2.6 $
✔ Answer: 2.6
---
Problem 10:
Data: 76, 87, 82, 25, 54, 15, 24
#### Mean:
$$
\frac{76+87+82+25+54+15+24}{7} = \frac{443}{7} \approx 63.29
$$
Now compute Mean Absolute Deviation (MAD)
| x | |x - 63.29| |
|---|----------|
| 76 | 12.71 |
| 87 | 23.71 |
| 82 | 18.71 |
| 25 | 38.29 |
| 54 | 9.29 |
| 15 | 48.29 |
| 24 | 39.29 |
Sum = 12.71 + 23.71 + 18.71 + 38.29 + 9.29 + 48.29 + 39.29 = 190.00
MAD = $ \frac{190}{7} \approx 27.14 $
✔ Answer: ≈ 27.14
---
## ✔ Final Answers Summary:
| Problem | Answer |
|--------|--------|
| 1 | 3.14 |
| 2 | 5.93 |
| 3 | 5.71 |
| 4 | 9.34 |
| 5 | 22.86 |
| 6 | 9.67 kg |
| 7 | 11.2 |
| 8 | 4.06 |
| 9 | 2.6 |
| 10 | 27.14 |
> Note: All answers are rounded to two decimal places unless otherwise specified.
If you have any questions about any of the steps, feel free to ask!
Parent Tip: Review the logic above to help your child master the concept of standard deviation worksheet.