Match root words with suffixes to create new words in this educational worksheet.

To solve this problem, we need to match each root word on the left with a suffix on the right to form a real, common English word. Then write the new word in the box.

Let’s go step by step:

1. free + ? → Try adding suffixes:
- free + est = freest ✔ (means “most free”)
- free + ly = freely ✔ (also valid)
- But we have to use each suffix only once, and match all 7 pairs uniquely.

We’ll look at all root words and see which suffix fits best without repeating.

List of roots:
1. free
2. great
3. great ← wait, “great” appears twice? That might be a trick — maybe one is for “greater”, one for “greatest”? Let’s check.

Actually, looking again:
Roots are:
1. free
2. great
3. great ← yes, duplicated? Or typo? Probably intentional — perhaps one becomes “greater”, one “greatest”.

Suffixes:
est, ly, er, less, ful, s, ed

Let’s try matching logically:

→ free + ly = freely ✔
→ great + er = greater ✔
→ great + est = greatest ✔
→ grate + ful = grateful ✔ (common word!)
→ age + less = ageless ✔
→ work + s = works ✔ (as in “he works” or “artworks”)
→ friend + ed = friended? ✘ Not common. Wait — “friend” + “ly” = friendly ✔ but we already used “ly” for “freely”. Hmm.

Wait — let’s reassign carefully so no suffix repeats.

Try this pairing:

1. free + est = freest ✔
2. great + er = greater ✔
3. great + est = greatest ✔ → but “est” already used? Conflict.

Ah — here’s the issue: “great” is listed twice. So likely:

- One “great” goes with “er” → greater
- Other “great” goes with “est” → greatest

Then what about “free”? Can’t use “est” again.

Alternative plan:

Let’s list possible valid combinations first:

Possible valid words from these roots + suffixes:

- free + ly = freely
- free + est = freest
- great + er = greater
- great + est = greatest
- grate + ful = grateful
- age + less = ageless
- work + s = works
- friend + ly = friendly
- friend + ed = friended? (rare, not standard)
- work + ed = worked ✔
- age + s = ages ✔
- grate + s = grates ✔
- free + s = frees ✔
- etc.

But we must use each suffix exactly once, and each root exactly once (even though “great” appears twice — treat as two separate entries).

So let’s assign:

Root 1: free → best fit with ly → freely
Root 2: great → er → greater
Root 3: great → est → greatest
Root 4: grate → ful → grateful
Root 5: age → less → ageless
Root 6: work → s → works
Root 7: friend → ed → ??? “friended” is not standard. Better: friend + ly = friendly — but “ly” is taken.

Wait — if we give “free” → “est” = freest
then “friend” → “ly” = friendly
that works!

Let’s try:

1. free + est = freest
2. great + er = greater
3. great + est → conflict! “est” already used.

No — can’t reuse “est”.

Another idea: Maybe “work” + “ed” = worked ✔
“friend” + “ly” = friendly ✔
“free” + “s” = frees ✔ (but weak)
“age” + “s” = ages ✔
“grate” + “s” = grates ✔

But we have to use all suffixes: est, ly, er, less, ful, s, ed

Let’s force unique matches:

Best logical set:

1. free + ly = freely
2. great + er = greater
3. great + est = greatest → but “est” not yet used? Wait, we haven’t assigned it yet.

Hold on — let’s number the suffixes as given:

Suffixes column:
● est
● ly
● er
● less
● ful
● s
● ed

So 7 suffixes, 7 roots.

Now pair them uniquely:

Try:

1. free + ly = freely → uses “ly”
2. great + er = greater → uses “er”
3. great + est = greatest → uses “est”
4. grate + ful = grateful → uses “ful”
5. age + less = ageless → uses “less”
6. work + s = works → uses “s”
7. friend + ed = ??? → “friended” is not standard. Problem.

What if:

7. friend + ly = friendly → but “ly” already used by #1.

Conflict.

Alternative:

Give “free” + “est” = freest → uses “est”
Then “great” + “er” = greater → uses “er”
Other “great” + ??? → only “est” left? No.

Wait — maybe “work” + “ed” = worked ✔
“friend” + “ly” = friendly ✔
“free” + “s” = frees ✔ (acceptable)
“age” + “less” = ageless ✔
“grate” + “ful” = grateful ✔
“great” + “er” = greater ✔
“great” + “est” = greatest ✔

That uses:

- free + s → frees
- great + er → greater
- great + est → greatest
- grate + ful → grateful
- age + less → ageless
- work + ed → worked
- friend + ly → friendly

Check suffixes used: s, er, est, ful, less, ed, ly → all 7! Perfect.

And all are real words.

So final matching:

1. free + s = frees
2. great + er = greater
3. great + est = greatest
4. grate + ful = grateful
5. age + less = ageless
6. work + ed = worked
7. friend + ly = friendly

But wait — the roots are numbered 1 to 7, and we must write the new word in order 1 to 7 based on the root numbering.

So:

Root 1: free → paired with s → frees
Root 2: great → paired with er → greater
Root 3: great → paired with est → greatest
Root 4: grate → paired with ful → grateful
Root 5: age → paired with less → ageless
Root 6: work → paired with ed → worked
Root 7: friend → paired with ly → friendly

Yes — this uses every suffix exactly once and forms real words.

Double-check:

- frees ✔ (verb: he frees the bird)
- greater ✔
- greatest ✔
- grateful ✔
- ageless ✔
- worked ✔
- friendly ✔

Perfect.

Final Answer:
1. frees
2. greater
3. greatest
4. grateful
5. ageless
6. worked
7. friendly