Dividing Polynomials Worksheets - Free Printable
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Step-by-step solution for: Dividing Polynomials Worksheets
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Show Answer Key & Explanations
Step-by-step solution for: Dividing Polynomials Worksheets
It looks like you've uploaded a worksheet titled "Dividing Polynomials" that contains several polynomial division problems. However, since I can't view images directly, I'll need you to provide the actual problems from the image so I can solve and explain them.
But based on the visible text in your message, here are the problems listed:
---
1) $ x^3 + 5x^2 - 8x - 16 \div (x - 2) $
2) $ 2x^3 + 7x^2 - 12x - 35 \div (x + 5) $
3) $ 2x^3 + x^2 + 5x - 10 \div (x - 2) $
4) $ 3x^3 + 11x^2 - 35x + 24 \div (x - 3) $
5) $ 2x^3 - 8x^2 + 5x - 40 \div (x - 4) $
6) $ 5x^3 + 10x^2 + 19x + 16 \div (x + 2) $
7) $ 3x^3 + 12x^2 + 40x + 10 \div (x + 5) $
8) $ 3x^3 - 8x^2 - 19x + 12 \div (x - 4) $
---
I’ll solve each of these using synthetic division, which is a shortcut method for dividing polynomials by linear divisors of the form $ (x - c) $. Let’s go step-by-step.
---
$ x^3 + 5x^2 - 8x - 16 \div (x - 2) $
Step 1: Use $ c = 2 $ (since divisor is $ x - 2 $)
Set up synthetic division:
```
2 | 1 5 -8 -16
| 2 14 12
-------------------
1 7 6 -4
```
Quotient: $ x^2 + 7x + 6 $
Remainder: $ -4 $
✔ So,
$$
\frac{x^3 + 5x^2 - 8x - 16}{x - 2} = x^2 + 7x + 6 - \frac{4}{x - 2}
$$
---
$ 2x^3 + 7x^2 - 12x - 35 \div (x + 5) $
Note: $ x + 5 = x - (-5) $ → use $ c = -5 $
```
-5 | 2 7 -12 -35
| -10 15 -15
---------------------
2 -3 3 -50
```
Quotient: $ 2x^2 - 3x + 3 $
Remainder: $ -50 $
✔ So,
$$
\frac{2x^3 + 7x^2 - 12x - 35}{x + 5} = 2x^2 - 3x + 3 - \frac{50}{x + 5}
$$
---
$ 2x^3 + x^2 + 5x - 10 \div (x - 2) $
Use $ c = 2 $
```
2 | 2 1 5 -10
| 4 10 30
------------------
2 5 15 20
```
Quotient: $ 2x^2 + 5x + 15 $
Remainder: $ 20 $
✔ So,
$$
\frac{2x^3 + x^2 + 5x - 10}{x - 2} = 2x^2 + 5x + 15 + \frac{20}{x - 2}
$$
---
$ 3x^3 + 11x^2 - 35x + 24 \div (x - 3) $
Use $ c = 3 $
```
3 | 3 11 -35 24
| 9 60 45
-------------------
3 20 25 69
```
Quotient: $ 3x^2 + 20x + 25 $
Remainder: $ 69 $
✔ So,
$$
\frac{3x^3 + 11x^2 - 35x + 24}{x - 3} = 3x^2 + 20x + 25 + \frac{69}{x - 3}
$$
---
$ 2x^3 - 8x^2 + 5x - 40 \div (x - 4) $
Use $ c = 4 $
```
4 | 2 -8 5 -40
| 8 0 20
-------------------
2 0 5 -20
```
Quotient: $ 2x^2 + 0x + 5 = 2x^2 + 5 $
Remainder: $ -20 $
✔ So,
$$
\frac{2x^3 - 8x^2 + 5x - 40}{x - 4} = 2x^2 + 5 - \frac{20}{x - 4}
$$
---
$ 5x^3 + 10x^2 + 19x + 16 \div (x + 2) $
$ x + 2 = x - (-2) $ → $ c = -2 $
```
-2 | 5 10 19 16
| -10 0 -38
-------------------
5 0 19 -22
```
Quotient: $ 5x^2 + 0x + 19 = 5x^2 + 19 $
Remainder: $ -22 $
✔ So,
$$
\frac{5x^3 + 10x^2 + 19x + 16}{x + 2} = 5x^2 + 19 - \frac{22}{x + 2}
$$
---
$ 3x^3 + 12x^2 + 40x + 10 \div (x + 5) $
Use $ c = -5 $
```
-5 | 3 12 40 10
| -15 15 -275
-------------------
3 -3 55 -265
```
Quotient: $ 3x^2 - 3x + 55 $
Remainder: $ -265 $
✔ So,
$$
\frac{3x^3 + 12x^2 + 40x + 10}{x + 5} = 3x^2 - 3x + 55 - \frac{265}{x + 5}
$$
---
$ 3x^3 - 8x^2 - 19x + 12 \div (x - 4) $
Use $ c = 4 $
```
4 | 3 -8 -19 12
| 12 16 -12
--------------------
3 4 -3 0
```
Quotient: $ 3x^2 + 4x - 3 $
Remainder: $ 0 $
✔ So, this divides evenly:
$$
\frac{3x^3 - 8x^2 - 19x + 12}{x - 4} = 3x^2 + 4x - 3
$$
---
1) $ x^2 + 7x + 6 - \frac{4}{x - 2} $
2) $ 2x^2 - 3x + 3 - \frac{50}{x + 5} $
3) $ 2x^2 + 5x + 15 + \frac{20}{x - 2} $
4) $ 3x^2 + 20x + 25 + \frac{69}{x - 3} $
5) $ 2x^2 + 5 - \frac{20}{x - 4} $
6) $ 5x^2 + 19 - \frac{22}{x + 2} $
7) $ 3x^2 - 3x + 55 - \frac{265}{x + 5} $
8) $ 3x^2 + 4x - 3 $ (exact division)
---
Let me know if you'd like explanations of any steps or want to verify with long division!
But based on the visible text in your message, here are the problems listed:
---
Divide by synthetic division:
1) $ x^3 + 5x^2 - 8x - 16 \div (x - 2) $
2) $ 2x^3 + 7x^2 - 12x - 35 \div (x + 5) $
3) $ 2x^3 + x^2 + 5x - 10 \div (x - 2) $
4) $ 3x^3 + 11x^2 - 35x + 24 \div (x - 3) $
5) $ 2x^3 - 8x^2 + 5x - 40 \div (x - 4) $
6) $ 5x^3 + 10x^2 + 19x + 16 \div (x + 2) $
7) $ 3x^3 + 12x^2 + 40x + 10 \div (x + 5) $
8) $ 3x^3 - 8x^2 - 19x + 12 \div (x - 4) $
---
I’ll solve each of these using synthetic division, which is a shortcut method for dividing polynomials by linear divisors of the form $ (x - c) $. Let’s go step-by-step.
---
🔹 Problem 1:
$ x^3 + 5x^2 - 8x - 16 \div (x - 2) $
Step 1: Use $ c = 2 $ (since divisor is $ x - 2 $)
Set up synthetic division:
```
2 | 1 5 -8 -16
| 2 14 12
-------------------
1 7 6 -4
```
Quotient: $ x^2 + 7x + 6 $
Remainder: $ -4 $
✔ So,
$$
\frac{x^3 + 5x^2 - 8x - 16}{x - 2} = x^2 + 7x + 6 - \frac{4}{x - 2}
$$
---
🔹 Problem 2:
$ 2x^3 + 7x^2 - 12x - 35 \div (x + 5) $
Note: $ x + 5 = x - (-5) $ → use $ c = -5 $
```
-5 | 2 7 -12 -35
| -10 15 -15
---------------------
2 -3 3 -50
```
Quotient: $ 2x^2 - 3x + 3 $
Remainder: $ -50 $
✔ So,
$$
\frac{2x^3 + 7x^2 - 12x - 35}{x + 5} = 2x^2 - 3x + 3 - \frac{50}{x + 5}
$$
---
🔹 Problem 3:
$ 2x^3 + x^2 + 5x - 10 \div (x - 2) $
Use $ c = 2 $
```
2 | 2 1 5 -10
| 4 10 30
------------------
2 5 15 20
```
Quotient: $ 2x^2 + 5x + 15 $
Remainder: $ 20 $
✔ So,
$$
\frac{2x^3 + x^2 + 5x - 10}{x - 2} = 2x^2 + 5x + 15 + \frac{20}{x - 2}
$$
---
🔹 Problem 4:
$ 3x^3 + 11x^2 - 35x + 24 \div (x - 3) $
Use $ c = 3 $
```
3 | 3 11 -35 24
| 9 60 45
-------------------
3 20 25 69
```
Quotient: $ 3x^2 + 20x + 25 $
Remainder: $ 69 $
✔ So,
$$
\frac{3x^3 + 11x^2 - 35x + 24}{x - 3} = 3x^2 + 20x + 25 + \frac{69}{x - 3}
$$
---
🔹 Problem 5:
$ 2x^3 - 8x^2 + 5x - 40 \div (x - 4) $
Use $ c = 4 $
```
4 | 2 -8 5 -40
| 8 0 20
-------------------
2 0 5 -20
```
Quotient: $ 2x^2 + 0x + 5 = 2x^2 + 5 $
Remainder: $ -20 $
✔ So,
$$
\frac{2x^3 - 8x^2 + 5x - 40}{x - 4} = 2x^2 + 5 - \frac{20}{x - 4}
$$
---
🔹 Problem 6:
$ 5x^3 + 10x^2 + 19x + 16 \div (x + 2) $
$ x + 2 = x - (-2) $ → $ c = -2 $
```
-2 | 5 10 19 16
| -10 0 -38
-------------------
5 0 19 -22
```
Quotient: $ 5x^2 + 0x + 19 = 5x^2 + 19 $
Remainder: $ -22 $
✔ So,
$$
\frac{5x^3 + 10x^2 + 19x + 16}{x + 2} = 5x^2 + 19 - \frac{22}{x + 2}
$$
---
🔹 Problem 7:
$ 3x^3 + 12x^2 + 40x + 10 \div (x + 5) $
Use $ c = -5 $
```
-5 | 3 12 40 10
| -15 15 -275
-------------------
3 -3 55 -265
```
Quotient: $ 3x^2 - 3x + 55 $
Remainder: $ -265 $
✔ So,
$$
\frac{3x^3 + 12x^2 + 40x + 10}{x + 5} = 3x^2 - 3x + 55 - \frac{265}{x + 5}
$$
---
🔹 Problem 8:
$ 3x^3 - 8x^2 - 19x + 12 \div (x - 4) $
Use $ c = 4 $
```
4 | 3 -8 -19 12
| 12 16 -12
--------------------
3 4 -3 0
```
Quotient: $ 3x^2 + 4x - 3 $
Remainder: $ 0 $
✔ So, this divides evenly:
$$
\frac{3x^3 - 8x^2 - 19x + 12}{x - 4} = 3x^2 + 4x - 3
$$
---
✔ Final Answers Summary:
1) $ x^2 + 7x + 6 - \frac{4}{x - 2} $
2) $ 2x^2 - 3x + 3 - \frac{50}{x + 5} $
3) $ 2x^2 + 5x + 15 + \frac{20}{x - 2} $
4) $ 3x^2 + 20x + 25 + \frac{69}{x - 3} $
5) $ 2x^2 + 5 - \frac{20}{x - 4} $
6) $ 5x^2 + 19 - \frac{22}{x + 2} $
7) $ 3x^2 - 3x + 55 - \frac{265}{x + 5} $
8) $ 3x^2 + 4x - 3 $ (exact division)
---
Let me know if you'd like explanations of any steps or want to verify with long division!
Parent Tip: Review the logic above to help your child master the concept of synthetic division worksheet answers.