Temperature conversion and scale comparison questions from a science worksheet.

It seems you've uploaded an image containing a series of multiple-choice questions related to temperature scales, freezing and boiling points, and conversions between Celsius and Fahrenheit. Below, I will solve each problem step by step and explain the solution.

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Question Q.3: What is the degree difference between the freezing point of water and the boiling point of water?

#### Solution:
1. The freezing point of water on the Celsius scale is 0°C.
2. The boiling point of water on the Celsius scale is 100°C.
3. The difference between these two temperatures is:
\[
100^\circ\text{C} - 0^\circ\text{C} = 100^\circ\text{C}
\]

#### Answer:
\[
\boxed{100^\circ\text{C}}
\]

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Question Q.4: Which of the following temperatures has a temperature of \(85^\circ\) Celsius?

#### Solution:
This question appears incomplete because it does not provide options for comparison. However, if we assume the question is asking for the equivalent temperature in another scale (e.g., Fahrenheit), we can convert \(85^\circ\) Celsius to Fahrenheit using the formula:
\[
F = \left( C \times \frac{9}{5} \right) + 32
\]
where \(C\) is the temperature in Celsius and \(F\) is the temperature in Fahrenheit.

Substitute \(C = 85\):
\[
F = \left( 85 \times \frac{9}{5} \right) + 32
\]
\[
F = (85 \times 1.8) + 32
\]
\[
F = 153 + 32 = 185
\]

So, \(85^\circ\) Celsius is equivalent to \(185^\circ\) Fahrenheit.

#### Answer:
If the options were provided, the correct answer would be the one corresponding to \(185^\circ\) Fahrenheit. Since no options are given, the conversion result is:
\[
\boxed{185^\circ\text{F}}
\]

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Question Q.5: Convert the temperature given in its Fahrenheit scale to the Celsius scale. \(77^\circ\) F

#### Solution:
To convert from Fahrenheit to Celsius, use the formula:
\[
C = \frac{5}{9} \times (F - 32)
\]
where \(F\) is the temperature in Fahrenheit and \(C\) is the temperature in Celsius.

Substitute \(F = 77\):
\[
C = \frac{5}{9} \times (77 - 32)
\]
\[
C = \frac{5}{9} \times 45
\]
\[
C = 5 \times 5 = 25
\]

#### Answer:
\[
\boxed{25^\circ\text{C}}
\]

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Question Q.6: Convert the temperature given in the Celsius scale to the Fahrenheit scale. \(30^\circ\) C

#### Solution:
To convert from Celsius to Fahrenheit, use the formula:
\[
F = \left( C \times \frac{9}{5} \right) + 32
\]
where \(C\) is the temperature in Celsius and \(F\) is the temperature in Fahrenheit.

Substitute \(C = 30\):
\[
F = \left( 30 \times \frac{9}{5} \right) + 32
\]
\[
F = (30 \times 1.8) + 32
\]
\[
F = 54 + 32 = 86
\]

#### Answer:
\[
\boxed{86^\circ\text{F}}
\]

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Question Q.7: Which of the following temperature that water freezes at 273 and boils at 373?

#### Solution:
The temperature scale where water freezes at \(273\) and boils at \(373\) is the Kelvin scale. In the Kelvin scale:
- Water freezes at \(273.15\) K.
- Water boils at \(373.15\) K.

#### Answer:
\[
\boxed{\text{Kelvin}}
\]

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Question Q.8: Which of the following temperatures is the coldest?

#### Solution:
The options provided are:
a) \(95^\circ\) Fahrenheit
b) \(30^\circ\) Celsius
c) \(320\) Kelvin

1. Convert \(95^\circ\) Fahrenheit to Celsius:
\[
C = \frac{5}{9} \times (F - 32)
\]
\[
C = \frac{5}{9} \times (95 - 32)
\]
\[
C = \frac{5}{9} \times 63 = 35^\circ\text{C}
\]

2. Compare the temperatures:
- \(95^\circ\) Fahrenheit = \(35^\circ\) Celsius
- \(30^\circ\) Celsius
- \(320\) Kelvin

3. Convert \(320\) Kelvin to Celsius:
\[
C = K - 273.15
\]
\[
C = 320 - 273.15 = 46.85^\circ\text{C}
\]

4. Order the temperatures:
- \(30^\circ\) Celsius
- \(35^\circ\) Celsius (\(95^\circ\) Fahrenheit)
- \(46.85^\circ\) Celsius (\(320\) Kelvin)

The coldest temperature is \(30^\circ\) Celsius.

#### Answer:
\[
\boxed{30^\circ\text{C}}
\]

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Question Q.9: Which of the following temperatures is the hottest?

#### Solution:
The options provided are:
a) \(120^\circ\) Fahrenheit
b) \(60^\circ\) Celsius
c) \(310\) Kelvin

1. Convert \(120^\circ\) Fahrenheit to Celsius:
\[
C = \frac{5}{9} \times (F - 32)
\]
\[
C = \frac{5}{9} \times (120 - 32)
\]
\[
C = \frac{5}{9} \times 88 = 48.89^\circ\text{C}
\]

2. Compare the temperatures:
- \(120^\circ\) Fahrenheit = \(48.89^\circ\) Celsius
- \(60^\circ\) Celsius
- \(310\) Kelvin

3. Convert \(310\) Kelvin to Celsius:
\[
C = K - 273.15
\]
\[
C = 310 - 273.15 = 36.85^\circ\text{C}
\]

4. Order the temperatures:
- \(36.85^\circ\) Celsius (\(310\) Kelvin)
- \(48.89^\circ\) Celsius (\(120^\circ\) Fahrenheit)
- \(60^\circ\) Celsius

The hottest temperature is \(60^\circ\) Celsius.

#### Answer:
\[
\boxed{60^\circ\text{C}}
\]

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Question Q.10: Which of the following is defined as the lowest possible temperature that a substance can reach?

#### Solution:
The lowest possible temperature that a substance can reach is Absolute Zero. This is the point at which all molecular motion ceases, and it is defined as \(0\) Kelvin or \(-273.15^\circ\) Celsius.

#### Answer:
\[
\boxed{\text{Absolute Zero}}
\]

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Final Answers:

1. Q.3: \(\boxed{100^\circ\text{C}}\)
2. Q.4: \(\boxed{185^\circ\text{F}}\) (if converting \(85^\circ\) Celsius)
3. Q.5: \(\boxed{25^\circ\text{C}}\)
4. Q.6: \(\boxed{86^\circ\text{F}}\)
5. Q.7: \(\boxed{\text{Kelvin}}\)
6. Q.8: \(\boxed{30^\circ\text{C}}\)
7. Q.9: \(\boxed{60^\circ\text{C}}\)
8. Q.10: \(\boxed{\text{Absolute Zero}}\)