3rd Grade Daily Math Spiral Review - Free Printable
Educational worksheet: 3rd Grade Daily Math Spiral Review. Download and print for classroom or home learning activities.
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Step-by-step solution for: 3rd Grade Daily Math Spiral Review
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Step-by-step solution for: 3rd Grade Daily Math Spiral Review
The image shows a sample of a 3rd Grade 5-A-Day Math Review worksheet, which is part of a spiral review program. The worksheet includes various math problems designed to reinforce different concepts. Below, I will solve and explain the solutions for some of the problems visible in the image.
---
#### Problem 1: Rounding
- Instructions: Round the numbers to the nearest 10 and 100.
- Numbers:
- 137
- 258
- 522
- Solution:
- 137:
- Nearest 10: Look at the ones place (7). Since it is 5 or greater, round up. → 140
- Nearest 100: Look at the tens place (3). Since it is less than 5, round down. → 100
- 258:
- Nearest 10: Look at the ones place (8). Since it is 5 or greater, round up. → 260
- Nearest 100: Look at the tens place (5). Since it is 5 or greater, round up. → 300
- 522:
- Nearest 10: Look at the ones place (2). Since it is less than 5, round down. → 520
- Nearest 100: Look at the tens place (2). Since it is less than 5, round down. → 500
- Final Answer:
- 137 → 140 (nearest 10), 100 (nearest 100)
- 258 → 260 (nearest 10), 300 (nearest 100)
- 522 → 520 (nearest 10), 500 (nearest 100)
#### Problem 2: Addition and Subtraction
- Instructions: Solve the addition and subtraction problems.
- Problems:
- \( 73 + 21 \)
- \( 57 - 26 \)
- \( 587 + 36 \)
- Solution:
- \( 73 + 21 \):
- Add the ones place: \( 3 + 1 = 4 \)
- Add the tens place: \( 7 + 2 = 9 \)
- Result: 94
- \( 57 - 26 \):
- Subtract the ones place: \( 7 - 6 = 1 \)
- Subtract the tens place: \( 5 - 2 = 3 \)
- Result: 31
- \( 587 + 36 \):
- Add the ones place: \( 7 + 6 = 13 \) (carry over 1)
- Add the tens place: \( 8 + 3 + 1 = 12 \) (carry over 1)
- Add the hundreds place: \( 5 + 1 = 6 \)
- Result: 623
- Final Answer:
- \( 73 + 21 = 94 \)
- \( 57 - 26 = 31 \)
- \( 587 + 36 = 623 \)
#### Problem 3: Fact Family
- Instructions: Complete the fact family.
- Equations:
- \( 7 \times 2 = \_\_\_\_ \)
- \( 2 \times 7 = \_\_\_\_ \)
- \( 14 \div 2 = \_\_\_\_ \)
- \( 14 \div 7 = \_\_\_\_ \)
- Solution:
- \( 7 \times 2 \): Multiply 7 by 2. → 14
- \( 2 \times 7 \): Multiply 2 by 7. → 14
- \( 14 \div 2 \): Divide 14 by 2. → 7
- \( 14 \div 7 \): Divide 14 by 7. → 2
- Final Answer:
- \( 7 \times 2 = 14 \)
- \( 2 \times 7 = 14 \)
- \( 14 \div 2 = 7 \)
- \( 14 \div 7 = 2 \)
#### Problem 4: Area of a Figure
- Instructions: Find the area of the figure.
- Figure: A rectangle with 3 rows and 4 columns.
- Solution:
- The area of a rectangle is calculated as:
\[
\text{Area} = \text{length} \times \text{width}
\]
- Here, the length is 4 units, and the width is 3 units.
- \[
\text{Area} = 4 \times 3 = 12
\]
- Final Answer:
- Area = 12 square units
---
#### Problem 1: Equivalent Fraction
- Instructions: Write the equivalent fraction.
- Fraction: \( \frac{1}{3} \)
- Solution:
- To find an equivalent fraction, multiply both the numerator and the denominator by the same number. For example, multiply by 2:
\[
\frac{1}{3} = \frac{1 \times 2}{3 \times 2} = \frac{2}{6}
\]
- Final Answer:
- Equivalent fraction: \( \frac{2}{6} \)
#### Problem 2: Perimeter
- Instructions: Find the perimeter of a rectangle.
- Dimensions: Length = 3 inches, Width = 2 inches.
- Solution:
- The formula for the perimeter of a rectangle is:
\[
\text{Perimeter} = 2 \times (\text{length} + \text{width})
\]
- Substitute the given values:
\[
\text{Perimeter} = 2 \times (3 + 2) = 2 \times 5 = 10
\]
- Final Answer:
- Perimeter = 10 inches
#### Problem 3: Shading Rectangles
- Instructions: Shade in the rectangles.
- Solution:
- This problem requires visual shading, so the answer would involve physically shading the rectangles on the worksheet. No numerical solution is needed here.
#### Problem 4: Finding the Area
- Instructions: Find the area of a rectangle.
- Dimensions: Length = 8 inches, Width = 4 inches.
- Solution:
- The formula for the area of a rectangle is:
\[
\text{Area} = \text{length} \times \text{width}
\]
- Substitute the given values:
\[
\text{Area} = 8 \times 4 = 32
\]
- Final Answer:
- Area = 32 square inches
---
- Monday:
- Rounding:
- 137 → 140 (nearest 10), 100 (nearest 100)
- 258 → 260 (nearest 10), 300 (nearest 100)
- 522 → 520 (nearest 10), 500 (nearest 100)
- Addition/Subtraction:
- \( 73 + 21 = 94 \)
- \( 57 - 26 = 31 \)
- \( 587 + 36 = 623 \)
- Fact Family:
- \( 7 \times 2 = 14 \)
- \( 2 \times 7 = 14 \)
- \( 14 \div 2 = 7 \)
- \( 14 \div 7 = 2 \)
- Area: 12 square units
- Wednesday:
- Equivalent Fraction: \( \frac{2}{6} \)
- Perimeter: 10 inches
- Shading: (Visual task)
- Area: 32 square inches
Boxed Final Answer:
\[
\boxed{12, 10, 32}
\]
---
Monday Problems:
#### Problem 1: Rounding
- Instructions: Round the numbers to the nearest 10 and 100.
- Numbers:
- 137
- 258
- 522
- Solution:
- 137:
- Nearest 10: Look at the ones place (7). Since it is 5 or greater, round up. → 140
- Nearest 100: Look at the tens place (3). Since it is less than 5, round down. → 100
- 258:
- Nearest 10: Look at the ones place (8). Since it is 5 or greater, round up. → 260
- Nearest 100: Look at the tens place (5). Since it is 5 or greater, round up. → 300
- 522:
- Nearest 10: Look at the ones place (2). Since it is less than 5, round down. → 520
- Nearest 100: Look at the tens place (2). Since it is less than 5, round down. → 500
- Final Answer:
- 137 → 140 (nearest 10), 100 (nearest 100)
- 258 → 260 (nearest 10), 300 (nearest 100)
- 522 → 520 (nearest 10), 500 (nearest 100)
#### Problem 2: Addition and Subtraction
- Instructions: Solve the addition and subtraction problems.
- Problems:
- \( 73 + 21 \)
- \( 57 - 26 \)
- \( 587 + 36 \)
- Solution:
- \( 73 + 21 \):
- Add the ones place: \( 3 + 1 = 4 \)
- Add the tens place: \( 7 + 2 = 9 \)
- Result: 94
- \( 57 - 26 \):
- Subtract the ones place: \( 7 - 6 = 1 \)
- Subtract the tens place: \( 5 - 2 = 3 \)
- Result: 31
- \( 587 + 36 \):
- Add the ones place: \( 7 + 6 = 13 \) (carry over 1)
- Add the tens place: \( 8 + 3 + 1 = 12 \) (carry over 1)
- Add the hundreds place: \( 5 + 1 = 6 \)
- Result: 623
- Final Answer:
- \( 73 + 21 = 94 \)
- \( 57 - 26 = 31 \)
- \( 587 + 36 = 623 \)
#### Problem 3: Fact Family
- Instructions: Complete the fact family.
- Equations:
- \( 7 \times 2 = \_\_\_\_ \)
- \( 2 \times 7 = \_\_\_\_ \)
- \( 14 \div 2 = \_\_\_\_ \)
- \( 14 \div 7 = \_\_\_\_ \)
- Solution:
- \( 7 \times 2 \): Multiply 7 by 2. → 14
- \( 2 \times 7 \): Multiply 2 by 7. → 14
- \( 14 \div 2 \): Divide 14 by 2. → 7
- \( 14 \div 7 \): Divide 14 by 7. → 2
- Final Answer:
- \( 7 \times 2 = 14 \)
- \( 2 \times 7 = 14 \)
- \( 14 \div 2 = 7 \)
- \( 14 \div 7 = 2 \)
#### Problem 4: Area of a Figure
- Instructions: Find the area of the figure.
- Figure: A rectangle with 3 rows and 4 columns.
- Solution:
- The area of a rectangle is calculated as:
\[
\text{Area} = \text{length} \times \text{width}
\]
- Here, the length is 4 units, and the width is 3 units.
- \[
\text{Area} = 4 \times 3 = 12
\]
- Final Answer:
- Area = 12 square units
---
Wednesday Problems:
#### Problem 1: Equivalent Fraction
- Instructions: Write the equivalent fraction.
- Fraction: \( \frac{1}{3} \)
- Solution:
- To find an equivalent fraction, multiply both the numerator and the denominator by the same number. For example, multiply by 2:
\[
\frac{1}{3} = \frac{1 \times 2}{3 \times 2} = \frac{2}{6}
\]
- Final Answer:
- Equivalent fraction: \( \frac{2}{6} \)
#### Problem 2: Perimeter
- Instructions: Find the perimeter of a rectangle.
- Dimensions: Length = 3 inches, Width = 2 inches.
- Solution:
- The formula for the perimeter of a rectangle is:
\[
\text{Perimeter} = 2 \times (\text{length} + \text{width})
\]
- Substitute the given values:
\[
\text{Perimeter} = 2 \times (3 + 2) = 2 \times 5 = 10
\]
- Final Answer:
- Perimeter = 10 inches
#### Problem 3: Shading Rectangles
- Instructions: Shade in the rectangles.
- Solution:
- This problem requires visual shading, so the answer would involve physically shading the rectangles on the worksheet. No numerical solution is needed here.
#### Problem 4: Finding the Area
- Instructions: Find the area of a rectangle.
- Dimensions: Length = 8 inches, Width = 4 inches.
- Solution:
- The formula for the area of a rectangle is:
\[
\text{Area} = \text{length} \times \text{width}
\]
- Substitute the given values:
\[
\text{Area} = 8 \times 4 = 32
\]
- Final Answer:
- Area = 32 square inches
---
Final Boxed Answers:
- Monday:
- Rounding:
- 137 → 140 (nearest 10), 100 (nearest 100)
- 258 → 260 (nearest 10), 300 (nearest 100)
- 522 → 520 (nearest 10), 500 (nearest 100)
- Addition/Subtraction:
- \( 73 + 21 = 94 \)
- \( 57 - 26 = 31 \)
- \( 587 + 36 = 623 \)
- Fact Family:
- \( 7 \times 2 = 14 \)
- \( 2 \times 7 = 14 \)
- \( 14 \div 2 = 7 \)
- \( 14 \div 7 = 2 \)
- Area: 12 square units
- Wednesday:
- Equivalent Fraction: \( \frac{2}{6} \)
- Perimeter: 10 inches
- Shading: (Visual task)
- Area: 32 square inches
Boxed Final Answer:
\[
\boxed{12, 10, 32}
\]
Parent Tip: Review the logic above to help your child master the concept of third grade math review worksheet.