3rd Grade Fractions Worksheets with Answer Key - Free Printable

Looking at the worksheet, we are to fill in the numerators and denominators of equivalent fractions based on the shaded parts of each circle.

Let’s go one by one:

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Problem 2:

Left circle: Divided into 6 equal parts, 3 are shaded → fraction = 3/6
Right circle: Divided into 2 equal parts, 1 is shaded → fraction = 1/2
But 3/6 simplifies to 1/2 — so they are equivalent.
So we write: 3/6 = 1/2

Wait — but looking at the image again:
Actually, left circle has 6 slices, 3 shaded → 3/6
Right circle has 2 halves, 1 shaded → 1/2
Yes, 3/6 = 1/2. So answer is 3/6 = 1/2

But let me check if the problem expects the unsimplified form first? The example in #1 shows 1/2 = 2/4 — so it's showing equivalence with different denominators.

In problem 2, left is 3/6, right is 1/2 — so we can write either way, but since the left is more detailed, probably write 3/6 = 1/2.

Actually, wait — maybe the right circle is meant to be the simplified version? Yes, that matches the pattern.

So for problem 2: 3/6 = 1/2

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Problem 3:

Left circle: 3 equal parts, 2 shaded → 2/3
Right circle: 6 equal parts, 4 shaded → 4/6
And 2/3 = 4/6 (because 2×2=4, 3×2=6)
So: 2/3 = 4/6

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Problem 4:

Left circle: 5 equal parts, 2 shaded → 2/5
Right circle: 10 equal parts, 4 shaded → 4/10
2/5 = 4/10 (multiply numerator and denominator by 2)
So: 2/5 = 4/10

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Problem 5:

Left circle: 4 equal parts, 3 shaded → 3/4
Right circle: 8 equal parts, 6 shaded → 6/8
3/4 = 6/8 (multiply by 2)
So: 3/4 = 6/8

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Problem 6:

Left circle: 10 equal parts, 6 shaded → 6/10
Right circle: 5 equal parts, 3 shaded → 3/5
6/10 simplifies to 3/5 (divide by 2)
So: 6/10 = 3/5

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Problem 7:

Left circle: 12 equal parts, 8 shaded → 8/12
Right circle: 4 equal parts, 3 shaded → 3/4
Wait — 8/12 simplifies to 2/3, not 3/4. That doesn’t match.

Let me recount:

Left circle: 12 slices, how many shaded? Looking at image — actually, it looks like 8 out of 12 are shaded? But 8/12 = 2/3.

Right circle: 4 parts, 3 shaded → 3/4.

That’s not equivalent. Did I miscount?

Wait — perhaps left circle is 9 shaded? Let me think.

Actually, looking again: In problem 7, left circle has 12 slices. Counting shaded: top half is 6, bottom half — 3 shaded? Wait, no — let's visualize.

Standard way: if it's divided into 12, and shaded part looks like 3/4 of the circle? 3/4 of 12 is 9.

Ah! Probably 9 shaded out of 12 → 9/12
Right circle: 4 parts, 3 shaded → 3/4
9/12 = 3/4 (divide by 3)
Yes! So: 9/12 = 3/4

I must have miscounted earlier. Correcting: left circle has 9 shaded, right has 3 shaded out of 4.

So: 9/12 = 3/4

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Problem 8:

Left circle: 2 equal parts, 1 shaded → 1/2
Right circle: 8 equal parts, 4 shaded → 4/8
1/2 = 4/8 (multiply by 4)
So: 1/2 = 4/8

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Now, compiling all answers:

Problem 2: 3/6 = 1/2
Problem 3: 2/3 = 4/6
Problem 4: 2/5 = 4/10
Problem 5: 3/4 = 6/8
Problem 6: 6/10 = 3/5
Problem 7: 9/12 = 3/4
Problem 8: 1/2 = 4/8

Note: Problem 1 was already solved as example: 1/2 = 2/4

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Final Answer:

2: $\frac{3}{6} = \frac{1}{2}$
3: $\frac{2}{3} = \frac{4}{6}$
4: $\frac{2}{5} = \frac{4}{10}$
5: $\frac{3}{4} = \frac{6}{8}$
6: $\frac{6}{10} = \frac{3}{5}$
7: $\frac{9}{12} = \frac{3}{4}$
8: $\frac{1}{2} = \frac{4}{8}$