18 - Time Zones Worksheet PDF | PDF - Free Printable

Problem Overview:

The worksheet involves determining the time in different locations based on their longitudes and the given rules for time zone differences. The key reminders provided are:
1. 15 degrees of longitude = 1 hour of time difference.
2. Going east, time increases (gets later).
3. Going west, time decreases (gets earlier).

We will solve the problems step by step using these rules.

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Step 1: Determine the Longitude of Location A

From the map:
- Location A is at approximately 75°W longitude.

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Problem 1: If it is 9:00 a.m. in location A, what time is it in the following locations?

#### (a) Location E
- Longitude of E: Approximately 60°W.
- Difference from A:
- Longitude of A = 75°W
- Longitude of E = 60°W
- Difference = 75°W - 60°W = 15°W
- Since E is to the east of A, time increases.
- Time difference: \( \frac{15°}{15°/\text{hour}} = 1 \text{ hour} \).
- Time in E: 9:00 a.m. + 1 hour = 10:00 a.m..

#### (b) Location B
- Longitude of B: Approximately 45°W.
- Difference from A:
- Longitude of A = 75°W
- Longitude of B = 45°W
- Difference = 75°W - 45°W = 30°W
- Since B is to the east of A, time increases.
- Time difference: \( \frac{30°}{15°/\text{hour}} = 2 \text{ hours} \).
- Time in B: 9:00 a.m. + 2 hours = 11:00 a.m..

#### (c) Location C
- Longitude of C: Approximately 30°E.
- Difference from A:
- Longitude of A = 75°W
- Longitude of C = 30°E
- Total difference = 75°W + 30°E = 105°
- Since C is to the east of A, time increases.
- Time difference: \( \frac{105°}{15°/\text{hour}} = 7 \text{ hours} \).
- Time in C: 9:00 a.m. + 7 hours = 4:00 p.m..

#### (d) Location G
- Longitude of G: Approximately 15°E.
- Difference from A:
- Longitude of A = 75°W
- Longitude of G = 15°E
- Total difference = 75°W + 15°E = 90°
- Since G is to the east of A, time increases.
- Time difference: \( \frac{90°}{15°/\text{hour}} = 6 \text{ hours} \).
- Time in G: 9:00 a.m. + 6 hours = 3:00 p.m..

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Final Answers for Problem 1:

\[
\boxed{
\begin{array}{ll}
\text{E: } & 10:00 \text{ a.m.} \\
\text{B: } & 11:00 \text{ a.m.} \\
\text{C: } & 4:00 \text{ p.m.} \\
\text{G: } & 3:00 \text{ p.m.}
\end{array}
}
\]

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Problem 2: If the time in location F is 6:30 p.m., what time is it in the following locations?

#### (a) Location C
- Longitude of F: Approximately 105°E.
- Longitude of C: Approximately 30°E.
- Difference from F:
- Longitude of F = 105°E
- Longitude of C = 30°E
- Difference = 105°E - 30°E = 75°E
- Since C is to the west of F, time decreases.
- Time difference: \( \frac{75°}{15°/\text{hour}} = 5 \text{ hours} \).
- Time in C: 6:30 p.m. - 5 hours = 1:30 p.m..

#### (b) Location E
- Longitude of E: Approximately 60°W.
- Difference from F:
- Longitude of F = 105°E
- Longitude of E = 60°W
- Total difference = 105°E + 60°W = 165°
- Since E is to the west of F, time decreases.
- Time difference: \( \frac{165°}{15°/\text{hour}} = 11 \text{ hours} \).
- Time in E: 6:30 p.m. - 11 hours = 7:30 a.m..

#### (c) Location H
- Longitude of H: Approximately 105°W.
- Difference from F:
- Longitude of F = 105°E
- Longitude of H = 105°W
- Total difference = 105°E + 105°W = 210°
- Since H is to the west of F, time decreases.
- Time difference: \( \frac{210°}{15°/\text{hour}} = 14 \text{ hours} \).
- Time in H: 6:30 p.m. - 14 hours = 4:30 a.m..

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Final Answers for Problem 2:

\[
\boxed{
\begin{array}{ll}
\text{C: } & 1:30 \text{ p.m.} \\
\text{E: } & 7:30 \text{ a.m.} \\
\text{H: } & 4:30 \text{ a.m.}
\end{array}
}
\]

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Summary of All Answers:

\[
\boxed{
\begin{array}{ll}
\text{Problem 1:} & \\
\text{E: } & 10:00 \text{ a.m.} \\
\text{B: } & 11:00 \text{ a.m.} \\
\text{C: } & 4:00 \text{ p.m.} \\
\text{G: } & 3:00 \text{ p.m.} \\
\text{Problem 2:} & \\
\text{C: } & 1:30 \text{ p.m.} \\
\text{E: } & 7:30 \text{ a.m.} \\
\text{H: } & 4:30 \text{ a.m.}
\end{array}
}
\]