- The image displays a worksheet titled "Titration Calculations" focused on determining the concentration of sodium hydroxide (NaOH) using titration with hydrochloric acid (HCl).
- The worksheet presents three distinct problems, each requiring the calculation of NaOH concentration based on given volumes and concentrations of HCl used in titrations.
- Each problem follows a structured approach: writing the balanced chemical equation, calculating moles of HCl used, using the mole ratio from the equation to find moles of NaOH, and finally calculating the concentration of NaOH.
- The balanced chemical equation for all problems is HCl + NaOH → NaCl + H₂O, indicating a 1:1 mole ratio between HCl and NaOH.
- For Problem 1, 25.0 cm³ of NaOH reacts with 20.0 cm³ of 0.1 mol/dm³ HCl. Moles of HCl = 0.1 × (20.0/1000) = 0.002 moles. Since the ratio is 1:1, moles of NaOH = 0.002. Concentration of NaOH = 0.002 / (25.0/1000) = 0.08 mol/dm³.
- For Problem 2, 25.0 cm³ of NaOH reacts with 30.0 cm³ of 0.1 mol/dm³ HCl. Moles of HCl = 0.1 × (30.0/1000) = 0.003 moles. Moles of NaOH = 0.003. Concentration of NaOH = 0.003 / (25.0/1000) = 0.12 mol/dm³.
- For Problem 3, 25.0 cm³ of NaOH reacts with 40.0 cm³ of 0.1 mol/dm³ HCl. Moles of HCl = 0.1 × (40.0/1000) = 0.004 moles. Moles of NaOH = 0.004. Concentration of NaOH = 0.004 / (25.0/1000) = 0.16 mol/dm³.
- The worksheet includes a diagram illustrating the titration setup with a burette, conical flask, and indicator, emphasizing the experimental context.
- A pen is placed next to the worksheet, suggesting it is ready for student use or marking.
- The bottom right corner indicates "B&W Options Available," implying the worksheet can be printed in black and white.
- The solutions demonstrate the application of stoichiometry and concentration calculations in acid-base titrations, reinforcing key chemistry concepts.
Parent Tip: Review the logic above to help your child master the concept of titration practice worksheet.
