Trigonometry GR 10: Basic Ratios, Finding Sides, and Finding Angles in Right Triangles

I need to solve the trigonometry problem shown in the image. Let me work through it step by step.

Looking at the triangle ABC:
- It's a right triangle with the right angle at A
- Angle C = 63°
- Side CB (hypotenuse) = 6.2 cm
- We need to find side AB (which is opposite to angle C)

Step 1: Identify what we have and what we want
- Given angle: 63°
- Have: Hypotenuse = 6.2 cm
- Want: Opposite side (AB)

Step 2: Choose the correct ratio
Since we have the hypotenuse and want the opposite side, we use sine:
sin θ = opposite/hypotenuse

Step 3: Set up the equation
sin 63° = AB/6.2

Step 4: Solve for AB
AB = sin 63° × 6.2

Let me calculate this: