The task involves solving 2-digit subtraction problems
without regrouping. This means that in each subtraction, the digit in the ones place of the minuend (top number) is greater than or equal to the digit in the ones place of the subtrahend (bottom number), and the same applies to the tens place.
Let's solve each problem step by step:
---
Problem 1:
\[
\begin{array}{c@{}c}
& \text{Tens} & \text{Ones} \\
& 5 & 4 \\
- & 2 & 1 \\
\hline
& ? & ?
\end{array}
\]
- Subtract the ones place: \(4 - 1 = 3\)
- Subtract the tens place: \(5 - 2 = 3\)
- Result: \(33\)
---
Problem 2:
\[
\begin{array}{c@{}c}
& \text{Tens} & \text{Ones} \\
& 6 & 8 \\
- & 4 & 0 \\
\hline
& ? & ?
\end{array}
\]
- Subtract the ones place: \(8 - 0 = 8\)
- Subtract the tens place: \(6 - 4 = 2\)
- Result: \(28\)
---
Problem 3:
\[
\begin{array}{c@{}c}
& \text{Tens} & \text{Ones} \\
& 7 & 2 \\
- & 4 & 1 \\
\hline
& ? & ?
\end{array}
\]
- Subtract the ones place: \(2 - 1 = 1\)
- Subtract the tens place: \(7 - 4 = 3\)
- Result: \(31\)
---
Problem 4:
\[
\begin{array}{c@{}c}
& \text{Tens} & \text{Ones} \\
& 8 & 7 \\
- & 3 & 1 \\
\hline
& ? & ?
\end{array}
\]
- Subtract the ones place: \(7 - 1 = 6\)
- Subtract the tens place: \(8 - 3 = 5\)
- Result: \(56\)
---
Problem 5:
\[
\begin{array}{c@{}c}
& \text{Tens} & \text{Ones} \\
& 4 & 5 \\
- & 2 & 3 \\
\hline
& ? & ?
\end{array}
\]
- Subtract the ones place: \(5 - 3 = 2\)
- Subtract the tens place: \(4 - 2 = 2\)
- Result: \(22\)
---
Problem 6:
\[
\begin{array}{c@{}c}
& \text{Tens} & \text{Ones} \\
& 1 & 3 \\
- & 1 & 3 \\
\hline
& ? & ?
\end{array}
\]
- Subtract the ones place: \(3 - 3 = 0\)
- Subtract the tens place: \(1 - 1 = 0\)
- Result: \(00\) (or simply \(0\))
---
Problem 7:
\[
\begin{array}{c@{}c}
& \text{Tens} & \text{Ones} \\
& 3 & 6 \\
- & 1 & 5 \\
\hline
& ? & ?
\end{array}
\]
- Subtract the ones place: \(6 - 5 = 1\)
- Subtract the tens place: \(3 - 1 = 2\)
- Result: \(21\)
---
Problem 8:
\[
\begin{array}{c@{}c}
& \text{Tens} & \text{Ones} \\
& 8 & 7 \\
- & 1 & 1 \\
\hline
& ? & ?
\end{array}
\]
- Subtract the ones place: \(7 - 1 = 6\)
- Subtract the tens place: \(8 - 1 = 7\)
- Result: \(76\)
---
Problem 9:
\[
\begin{array}{c@{}c}
& \text{Tens} & \text{Ones} \\
& 4 & 8 \\
- & 3 & 7 \\
\hline
& ? & ?
\end{array}
\]
- Subtract the ones place: \(8 - 7 = 1\)
- Subtract the tens place: \(4 - 3 = 1\)
- Result: \(11\)
---
Final Answers:
\[
\boxed{
\begin{array}{ccc}
33 & 28 & 31 \\
56 & 22 & 0 \\
21 & 76 & 11
\end{array}
}
\]
Parent Tip: Review the logic above to help your child master the concept of two digit subtraction without regrouping worksheet.
