Balancing Equations Worksheet featuring 20 chemical reactions to solve.

Here are the balanced chemical equations for the worksheet. To balance them, we make sure the number of atoms for each element is the same on both the left (reactants) and right (products) sides.

Step-by-Step Solutions:

1) Na₃PO₄ + KOH → NaOH + K₃PO₄
- Balance Potassium (K): There are 3 K on the right, so put a 3 in front of KOH.
- Balance Sodium (Na): There are 3 Na on the left, so put a 3 in front of NaOH.
- Check: Everything else matches.
- Answer: 1, 3, 3, 1

2) MgF₂ + Li₂CO₃ → MgCO₃ + LiF
- Balance Lithium (Li): There are 2 Li on the left, so put a 2 in front of LiF.
- Check: Mg, F, C, and O are now balanced.
- Answer: 1, 1, 1, 2

3) P₄ + O₂ → P₂O₃
- Balance Phosphorus (P): There are 4 P on the left, so put a 2 in front of P₂O₃.
- Balance Oxygen (O): Now there are $2 \times 3 = 6$ O on the right. Put a 3 in front of O₂.
- Answer: 1, 3, 2

4) RbNO₃ + BeF₂ → Be(NO₃)₂ + RbF
- Balance Nitrate (NO₃): There are 2 groups on the right, so put a 2 in front of RbNO₃.
- Balance Rubidium (Rb): Now there are 2 Rb on the left, so put a 2 in front of RbF.
- Answer: 2, 1, 1, 2

5) AgNO₃ + Cu → Cu(NO₃)₂ + Ag
- Balance Nitrate (NO₃): There are 2 groups on the right, so put a 2 in front of AgNO₃.
- Balance Silver (Ag): Now there are 2 Ag on the left, so put a 2 in front of Ag.
- Answer: 2, 1, 1, 2

6) CF₄ + Br₂ → CBr₄ + F₂
- Balance Fluorine (F): There are 4 F on the left, so put a 2 in front of F₂.
- Balance Bromine (Br): There are 4 Br on the right, so put a 2 in front of Br₂.
- Answer: 1, 2, 1, 2

7) HCN + CuSO₄ → H₂SO₄ + Cu(CN)₂
- Balance Cyanide (CN): There are 2 CN groups on the right, so put a 2 in front of HCN.
- Balance Hydrogen (H): Now there are 2 H on the left, which matches the right.
- Answer: 2, 1, 1, 1

8) GaF₃ + Cs → CsF + Ga
- Balance Fluorine (F): There are 3 F on the left, so put a 3 in front of CsF.
- Balance Cesium (Cs): Now there are 3 Cs on the right, so put a 3 in front of Cs.
- Answer: 1, 3, 3, 1

9) BaS + PtF₂ → BaF₂ + PtS
- Check atoms: 1 Ba, 1 S, 1 Pt, 2 F on both sides. It is already balanced.
- Answer: 1, 1, 1, 1

10) N₂ + H₂ → NH₃
- Balance Nitrogen (N): There are 2 N on the left, so put a 2 in front of NH₃.
- Balance Hydrogen (H): Now there are $2 \times 3 = 6$ H on the right. Put a 3 in front of H₂.
- Answer: 1, 3, 2

11) NaF + Br₂ → NaBr + F₂
- Balance Fluorine (F): There are 2 F on the right, so put a 2 in front of NaF.
- Balance Sodium (Na): Now there are 2 Na on the left, so put a 2 in front of NaBr.
- Answer: 2, 1, 2, 1

12) Pb(OH)₂ + HCl → H₂O + PbCl₂
- Balance Chlorine (Cl): There are 2 Cl on the right, so put a 2 in front of HCl.
- Balance Hydrogen (H) and Oxygen (O): On the left, we have 2 H from OH and 2 H from HCl (total 4 H). On the right, put a 2 in front of H₂O to get 4 H and 2 O.
- Answer: 1, 2, 2, 1

13) AlBr₃ + K₂SO₄ → KBr + Al₂(SO₄)₃
- Balance Aluminum (Al): There are 2 Al on the right, so put a 2 in front of AlBr₃.
- Balance Bromine (Br): Now there are $2 \times 3 = 6$ Br on the left, so put a 6 in front of KBr.
- Balance Potassium (K): Now there are 6 K on the right, so put a 3 in front of K₂SO₄.
- Check Sulfate (SO₄): 3 on left, 3 on right. Balanced.
- Answer: 2, 3, 6, 1

14) CH₄ + O₂ → CO₂ + H₂O
- Balance Carbon (C): 1 on both sides.
- Balance Hydrogen (H): 4 on left, so put a 2 in front of H₂O.
- Balance Oxygen (O): Right side has $2 (\text{from } CO_2) + 2 (\text{from } 2H_2O) = 4$ O. Put a 2 in front of O₂.
- Answer: 1, 2, 1, 2

15) Na₃PO₄ + CaCl₂ → NaCl + Ca₃(PO)₂
- Balance Calcium (Ca): 3 on right, so put a 3 in front of CaCl₂.
- Balance Phosphate (PO₄): 2 on right, so put a 2 in front of Na₃PO₄.
- Balance Sodium (Na): $2 \times 3 = 6$ on left, so put a 6 in front of NaCl.
- Check Chlorine (Cl): $3 \times 2 = 6$ on left, 6 on right. Balanced.
- Answer: 2, 3, 6, 1

16) K + Cl₂ → KCl
- Balance Chlorine (Cl): 2 on left, so put a 2 in front of KCl.
- Balance Potassium (K): 2 on right, so put a 2 in front of K.
- Answer: 2, 1, 2

17) Al + HCl → H₂ + AlCl₃
- Balance Chlorine (Cl): 3 on right, 2 on left. The least common multiple is 6.
- Put a 2 in front of AlCl₃ (makes 6 Cl) and a 3 in front of HCl? No, that makes 3 H. Let's try putting 6 in front of HCl.
- If 6 HCl: We have 6 H and 6 Cl.
- Right side: Need 3 H₂ (to make 6 H) and 2 AlCl₃ (to make 6 Cl).
- Left side: Need 2 Al to match the 2 AlCl₃.
- Answer: 2, 6, 3, 2

18) N₂ + F₂ → NF₃
- Balance Nitrogen (N): 2 on left, so put a 2 in front of NF₃.
- Balance Fluorine (F): $2 \times 3 = 6$ on right, so put a 3 in front of F₂.
- Answer: 1, 3, 2

19) SO₂ + Li₂Se → SSe₂ + Li₂O
- Balance Selenium (Se): 2 on right, so put a 2 in front of Li₂Se.
- Balance Lithium (Li): $2 \times 2 = 4$ on left, so put a 2 in front of Li₂O.
- Check Oxygen (O): 2 on left, 2 on right. Sulfur (S): 1 on left, 1 on right.
- Answer: 1, 2, 1, 2

20) NH₃ + H₂SO₄ → (NH₄)₂SO₄
- Balance Nitrogen (N): 2 on right, so put a 2 in front of NH₃.
- Check Hydrogen (H): Left has $2 \times 3 (\text{from ammonia}) + 2 (\text{from acid}) = 8$. Right has $2 \times 4 = 8$. Balanced.
- Answer: 2, 1, 1

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Final Answer:
1) 1, 3, 3, 1
2) 1, 1, 1, 2
3) 1, 3, 2
4) 2, 1, 1, 2
5) 2, 1, 1, 2
6) 1, 2, 1, 2
7) 2, 1, 1, 1
8) 1, 3, 3, 1
9) 1, 1, 1, 1
10) 1, 3, 2
11) 2, 1, 2, 1
12) 1, 2, 2, 1
13) 2, 3, 6, 1
14) 1, 2, 1, 2
15) 2, 3, 6, 1
16) 2, 1, 2
17) 2, 6, 3, 2
18) 1, 3, 2
19) 1, 2, 1, 2
20) 2, 1, 1