Balancing Chemical Equations Homework worksheet for practice.

I'm ready to help you balance the chemical equations from your homework, but I can't see the image you uploaded. However, based on the text you've provided, I can solve and explain each of these balancing problems step by step.

Let me go through each equation one by one:

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1. N₂ + H₂ → NH₃

- Nitrogen: 2 atoms on left, 1 on right → need 2 NH₃
- Hydrogen: 2 on left, 3 on right → need 3 H₂
- Balanced: N₂ + 3H₂ → 2NH₃

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2. Mg + O₂ → MgO

- Magnesium: 1 on left, 1 on right
- Oxygen: 2 on left, 1 on right → need 2 MgO
- But then Mg becomes 2 → need 2 Mg
- Balanced: 2Mg + O₂ → 2MgO

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3. NaOH + H₂SO₄ → Na₂SO₄ + H₂O

- Na: 1 on left, 2 on right → need 2 NaOH
- S: 1 on both sides
- O: balanced with 2 NaOH
- H: 2+2=4 on left, 2 on right → need 2 H₂O
- Balanced: 2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O

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4. H₂ + Cl₂ → HCl

- H: 2 on left, 1 on right → need 2 HCl
- Cl: 2 on left, 2 on right
- Balanced: H₂ + Cl₂ → 2HCl

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5. Al + O₂ → Al₂O₃

- Al: 1 on left, 2 on right → need 2 Al
- O: 2 on left, 3 on right → need 3/2 O₂ → multiply whole equation by 2
- Balanced: 4Al + 3O₂ → 2Al₂O₃

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6. Al(OH)₃ + H₂SO₄ → Al₂(SO₄)₃ + H₂O

- Al: 1 on left, 2 on right → need 2 Al(OH)₃
- SO₄: 1 on left, 3 on right → need 3 H₂SO₄
- H: 6+6=12 on left, 2 on right → need 6 H₂O
- O: check — should be balanced
- Balanced: 2Al(OH)₃ + 3H₂SO₄ → Al₂(SO₄)₃ + 6H₂O

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7. CH₄ + O₂ → CO₂ + H₂O

- C: 1 on both sides
- H: 4 on left, 2 on right → need 2 H₂O
- O: 2 on left, 2+1=3 on right → need 2 O₂
- Balanced: CH₄ + 2O₂ → CO₂ + 2H₂O

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8. Fe + O₂ → Fe₂O₃

- Fe: 1 on left, 2 on right → need 2 Fe
- O: 2 on left, 3 on right → need 3/2 O₂ → multiply by 2
- Balanced: 4Fe + 3O₂ → 2Fe₂O₃

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9. FeS₂ + O₂ → Fe₂O₃ + SO₂

- Fe: 1 on left, 2 on right → need 2 FeS₂
- S: 2 on left, 1 on right → need 2 SO₂
- O: 2 on left, 3+2=5 on right → need 11/2 O₂ → multiply by 2
- Balanced: 4FeS₂ + 11O₂ → 2Fe₂O₃ + 8SO₂

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10. FeCl₃ + NaOH → Fe(OH)₃ + NaCl

- Fe: 1 on both sides
- Cl: 3 on left, 1 on right → need 3 NaCl
- Na: 3 on right, 1 on left → need 3 NaOH
- OH: 3 on right, 3 on left
- Balanced: FeCl₃ + 3NaOH → Fe(OH)₃ + 3NaCl

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11. AgNO₃ + KCl → AgCl + KNO₃

- All elements: 1 on both sides
- Already balanced: AgNO₃ + KCl → AgCl + KNO₃

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12. Ag₂O → Ag + O₂

- Ag: 2 on left, 1 on right → need 2 Ag
- O: 1 on left, 2 on right → need 1/2 O₂ → multiply by 2
- Balanced: 2Ag₂O → 4Ag + O₂

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13. C₆H₁₂O₆ → C₂H₅OH + CO₂

- This is fermentation
- C: 6 on left, 2+1=3 on right → need 2 C₂H₅OH and 2 CO₂
- H: 12 on left, 10 on right → wait: 2×6=12 H in ethanol? No: C₂H₅OH has 6 H
- So 2 C₂H₅OH → 12 H, matches
- O: 6 on left, 2×1 + 2×2 = 2+4=6 → good
- Balanced: C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

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14. KClO₃ → KCl + O₂

- K: 1 on both sides
- Cl: 1 on both sides
- O: 3 on left, 2 on right → need 3/2 O₂ → multiply by 2
- Balanced: 2KClO₃ → 2KCl + 3O₂

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15. KI + Pb(NO₃)₂ → KNO₃ + PbI₂

- K: 1 on left, 1 on right
- I: 1 on left, 2 on right → need 2 KI
- Pb: 1 on both sides
- NO₃: 2 on left, 1 on right → need 2 KNO₃
- Balanced: 2KI + Pb(NO₃)₂ → 2KNO₃ + PbI₂

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16. CaCO₃ → CaO + CO₂

- Already balanced: CaCO₃ → CaO + CO₂

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17. C₂H₄ + O₂ → CO₂ + H₂O

- C: 2 on left, 1 on right → need 2 CO₂
- H: 4 on left, 2 on right → need 2 H₂O
- O: 2 on left, 4+1=5 on right → need 3 O₂
- Balanced: C₂H₄ + 3O₂ → 2CO₂ + 2H₂O

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18. Mg(OH)₂ + HCl → MgCl₂ + H₂O

- Mg: 1 on both sides
- OH: 2 on left, 1 on right → need 2 H₂O
- H: 2+1=3 on left? Wait: HCl provides H, so need 2 HCl
- Cl: 2 on right, 1 on left → need 2 HCl
- H: 2 from Mg(OH)₂ + 2 from HCl = 4 H; 2 H₂O → 4 H → good
- Balanced: Mg(OH)₂ + 2HCl → MgCl₂ + 2H₂O

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19. NaOH + H₂CO₃ → Na₂CO₃ + H₂O

- Na: 1 on left, 2 on right → need 2 NaOH
- C: 1 on both sides
- O: balanced
- H: 2+2=4 on left, 2 on right → need 2 H₂O
- Balanced: 2NaOH + H₂CO₃ → Na₂CO₃ + 2H₂O

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20. NaOH + CaF₂ → NaF + Ca(OH)₂

- Na: 1 on left, 1 on right
- F: 2 on left, 1 on right → need 2 NaF
- Ca: 1 on both sides
- O and H: 2 OH on right, 1 on left → need 2 NaOH
- Balanced: 2NaOH + CaF₂ → 2NaF + Ca(OH)₂

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✔ All equations are now balanced!

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