Dimensional Analysis Practice worksheet - Free Printable
Educational worksheet: Dimensional Analysis Practice worksheet. Download and print for classroom or home learning activities.
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Step-by-step solution for: Dimensional Analysis Practice worksheet
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Show Answer Key & Explanations
Step-by-step solution for: Dimensional Analysis Practice worksheet
Let's solve each problem step-by-step using dimensional analysis (also known as the factor-label method). We'll use the given relationships and show all conversion steps.
---
A runner competed in a 5-mile run. How many yards did she run?
Given relationship:
1 mile = 1760 yards
Set up the conversion:
$$
5 \text{ miles} \times \frac{1760 \text{ yds}}{1 \text{ mile}} = ?
$$
Now calculate:
$$
5 \times 1760 = 8,800 \text{ yards}
$$
✔ Answer: 8,800 yards
---
In the Tour de France, cyclists ride 3,653.6 km over 20 days. How many miles do they go? [Hint: watch for unimportant information!]
We are asked to convert kilometers to miles, so the 20 days is irrelevant (just a distractor).
Given relationship:
1 mile = 1.61 km → So, $ \frac{1 \text{ mi}}{1.61 \text{ km}} $
Set up the conversion:
$$
3,653.6 \text{ km} \times \frac{1 \text{ mi}}{1.61 \text{ km}} = ?
$$
Now calculate:
$$
\frac{3,653.6}{1.61} \approx 2,270 \text{ miles}
$$
(Using calculator: $ 3,653.6 \div 1.61 = 2,270 $)
✔ Answer: 2,270 miles
---
After a nice meal, perhaps you’d finish it off with a pound cake for dessert. What would the name of this cake be in grams?
Given relationships:
- 1 lb = 16 oz
- 1 oz = 28.35 g
So we need to convert 1 lb → grams via ounces.
Set up the conversion:
$$
1 \text{ lb} \times \frac{16 \text{ oz}}{1 \text{ lb}} \times \frac{28.35 \text{ g}}{1 \text{ oz}} = ?
$$
Now calculate:
First: $ 1 \times 16 = 16 $ oz
Then: $ 16 \times 28.35 = 453.6 $ g
✔ Answer: 453.6 grams → A "453.6-g cake"
---
How many liters of milk would you need to equal one gallon?
Given relationships:
- 1 L = 1.06 qts
- 4 qts = 1 gal
We want to convert 1 gallon → liters, so we go through quarts.
Set up the conversion:
$$
1 \text{ gal} \times \frac{4 \text{ qts}}{1 \text{ gal}} \times \frac{1 \text{ L}}{1.06 \text{ qts}} = ?
$$
Now calculate:
First: $ 1 \times 4 = 4 $ qts
Then: $ 4 \div 1.06 \approx 3.7736 $ L
Round to reasonable precision: ≈ 3.77 L
✔ Answer: Approximately 3.77 liters
---
If you go to school for 180 days each year and each day is 7 hours long, how many hours are spent in school in one year?
Given:
- 180 days per school year
- 7 hours per school day
We just multiply:
$$
180 \text{ days/year} \times 7 \text{ hrs/day} = 1,260 \text{ hours/year}
$$
We can write it using dimensional analysis:
$$
\frac{180 \text{ days}}{1 \text{ (school) year}} \times \frac{7 \text{ hrs}}{1 \text{ day}} = 1,260 \text{ hrs/year}
$$
✔ Answer: 1,260 hours per school year
---
| Problem | Answer |
|--------|--------|
| 1 | 8,800 yards |
| 2 | 2,270 miles |
| 3 | 453.6 grams |
| 4 | ~3.77 liters |
| 5 | 1,260 hours |
All conversions used proper dimensional analysis with correct unit cancellation. Let me know if you'd like these formatted as boxed answers or printed!
---
Problem 1:
A runner competed in a 5-mile run. How many yards did she run?
Given relationship:
1 mile = 1760 yards
Set up the conversion:
$$
5 \text{ miles} \times \frac{1760 \text{ yds}}{1 \text{ mile}} = ?
$$
Now calculate:
$$
5 \times 1760 = 8,800 \text{ yards}
$$
✔ Answer: 8,800 yards
---
Problem 2:
In the Tour de France, cyclists ride 3,653.6 km over 20 days. How many miles do they go? [Hint: watch for unimportant information!]
We are asked to convert kilometers to miles, so the 20 days is irrelevant (just a distractor).
Given relationship:
1 mile = 1.61 km → So, $ \frac{1 \text{ mi}}{1.61 \text{ km}} $
Set up the conversion:
$$
3,653.6 \text{ km} \times \frac{1 \text{ mi}}{1.61 \text{ km}} = ?
$$
Now calculate:
$$
\frac{3,653.6}{1.61} \approx 2,270 \text{ miles}
$$
(Using calculator: $ 3,653.6 \div 1.61 = 2,270 $)
✔ Answer: 2,270 miles
---
Problem 3:
After a nice meal, perhaps you’d finish it off with a pound cake for dessert. What would the name of this cake be in grams?
Given relationships:
- 1 lb = 16 oz
- 1 oz = 28.35 g
So we need to convert 1 lb → grams via ounces.
Set up the conversion:
$$
1 \text{ lb} \times \frac{16 \text{ oz}}{1 \text{ lb}} \times \frac{28.35 \text{ g}}{1 \text{ oz}} = ?
$$
Now calculate:
First: $ 1 \times 16 = 16 $ oz
Then: $ 16 \times 28.35 = 453.6 $ g
✔ Answer: 453.6 grams → A "453.6-g cake"
---
Problem 4:
How many liters of milk would you need to equal one gallon?
Given relationships:
- 1 L = 1.06 qts
- 4 qts = 1 gal
We want to convert 1 gallon → liters, so we go through quarts.
Set up the conversion:
$$
1 \text{ gal} \times \frac{4 \text{ qts}}{1 \text{ gal}} \times \frac{1 \text{ L}}{1.06 \text{ qts}} = ?
$$
Now calculate:
First: $ 1 \times 4 = 4 $ qts
Then: $ 4 \div 1.06 \approx 3.7736 $ L
Round to reasonable precision: ≈ 3.77 L
✔ Answer: Approximately 3.77 liters
---
Problem 5:
If you go to school for 180 days each year and each day is 7 hours long, how many hours are spent in school in one year?
Given:
- 180 days per school year
- 7 hours per school day
We just multiply:
$$
180 \text{ days/year} \times 7 \text{ hrs/day} = 1,260 \text{ hours/year}
$$
We can write it using dimensional analysis:
$$
\frac{180 \text{ days}}{1 \text{ (school) year}} \times \frac{7 \text{ hrs}}{1 \text{ day}} = 1,260 \text{ hrs/year}
$$
✔ Answer: 1,260 hours per school year
---
✔ Final Answers Summary:
| Problem | Answer |
|--------|--------|
| 1 | 8,800 yards |
| 2 | 2,270 miles |
| 3 | 453.6 grams |
| 4 | ~3.77 liters |
| 5 | 1,260 hours |
All conversions used proper dimensional analysis with correct unit cancellation. Let me know if you'd like these formatted as boxed answers or printed!
Parent Tip: Review the logic above to help your child master the concept of unit analysis worksheet.