Let's solve each of the triple beam balance problems step by step. A
triple beam balance has three beams, each with a sliding weight (rider) that measures mass in grams:
1. The
largest beam (top) measures in
100-gram increments.
2. The
middle beam measures in
10-gram increments.
3. The
bottom beam (with a finer scale) measures in
1-gram increments, and often includes a
0.1 gram precision if there’s a decimal scale.
We add the values from all three beams to get the total mass.
---
Problem 1
- Top beam: Rider at
200 g
- Middle beam: Rider at
50 g
- Bottom beam: Rider at
3.0 g
Total = 200 + 50 + 3 = 253 g
✔ Answer: 253 g
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Problem 2
- Top beam: Rider at
500 g
- Middle beam: Rider at
40 g
- Bottom beam: Rider at
7.0 g
Total = 500 + 40 + 7 = 547 g
✔ Answer: 547 g
---
Problem 3
- Top beam: Rider at
300 g
- Middle beam: Rider at
30 g
- Bottom beam: Rider at
6.0 g
Total = 300 + 30 + 6 = 336 g
✔ Answer: 336 g
---
Problem 4
- Top beam: Rider at
200 g
- Middle beam: Rider at
10 g
- Bottom beam: Rider at
2.0 g
Total = 200 + 10 + 2 = 212 g
✔ Answer: 212 g
---
Problem 5
- Top beam: Rider at
100 g
- Middle beam: Rider at
20 g
- Bottom beam: Rider at
2.0 g
Total = 100 + 20 + 2 = 122 g
✔ Answer: 122 g
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Problem 6
- Top beam: Rider at
500 g
- Middle beam: Rider at
10 g
- Bottom beam: Rider at
6.0 g
Total = 500 + 10 + 6 = 516 g
✔ Answer: 516 g
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Problem 7
- Top beam: Rider at
300 g
- Middle beam: Rider at
50 g
- Bottom beam: Rider at
5.7 g (since it's between 5 and 6, and the mark is at 7 small divisions after 5 — each division is 0.1 g)
Total = 300 + 50 + 5.7 = 355.7 g
✔ Answer: 355.7 g
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Problem 8
Now convert the mass from Problem 7 into
milligrams (mg).
We know:
> 1 gram = 1000 milligrams
So:
> 355.7 g = 355.7 × 1000 =
355,700 mg
✔ Answer: 355,700 mg
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✔ Final Answers:
1.
253 g
2.
547 g
3.
336 g
4.
212 g
5.
122 g
6.
516 g
7.
355.7 g
8.
355,700 mg
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Let me know if you'd like this formatted as a printable answer sheet!
Parent Tip: Review the logic above to help your child master the concept of using a balance measuring mass worksheet.