1. The speed during the first 10 seconds (segment AB) is calculated as distance divided by time. Distance covered is 200 m in 10 s, so speed = 200 m / 10 s = 20 m/s.
2. The car stopped during segment BC, which spans from t = 10 s to t = 30 s. Therefore, the car stopped for 30 s - 10 s = 20 seconds.
3. On segment CD, the car travels from 200 m to 500 m, a distance of 300 m, over a time interval from t = 30 s to t = 60 s, which is 30 seconds. Speed = 300 m / 30 s = 10 m/s.
4. Comparing the speeds: AB = 20 m/s, CD = 10 m/s. The car traveled faster on segment AB (first 10 seconds).
5. For the whole journey (A to D), total distance = 500 m, total time = 60 s. Average speed = 500 m / 60 s ≈ 8.33 m/s.
6. The car was moving during segments AB and CD. Total moving distance = 500 m. Total moving time = 10 s (AB) + 30 s (CD) = 40 s. Average speed while moving = 500 m / 40 s = 12.5 m/s.
Parent Tip: Review the logic above to help your child master the concept of velocity time graphs worksheets.
