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Identify the vertex and axis of symmetry for each quadratic function and sketch the graph.

Graphs of four quadratic functions in vertex form, each with a coordinate grid for plotting the vertex and axis of symmetry.

Graphs of four quadratic functions in vertex form, each with a coordinate grid for plotting the vertex and axis of symmetry.

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Show Answer Key & Explanations Step-by-step solution for: SOLUTION: Vertex Form of Parabolas - Studypool
Let’s solve each problem step by step. We’ll find the vertex and axis of symmetry, then describe how to sketch the graph.

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Problem 15:


f(x) = -3(x - 2)² - 4

This is in vertex form:
> f(x) = a(x - h)² + k
where (h, k) is the vertex.

Here:
- a = -3 → parabola opens downward
- h = 2
- k = -4

Vertex: (2, -4)
Axis of symmetry: x = 2 (vertical line through the vertex)

To sketch:
- Plot vertex at (2, -4)
- Since |a| = 3, it’s narrower than y = x²
- Opens downward
- Pick one point on either side of x=2 to help draw curve:
- Let x = 1 → f(1) = -3(1-2)² - 4 = -3(1) - 4 = -7 → point (1, -7)
- Let x = 3 → same as x=1 due to symmetry → (3, -7)
- Draw smooth U-shape opening down through these points.

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Problem 16:


f(x) = -¼(x - 1)² + 4

Vertex form again:
- a = -¼ → opens downward, very wide
- h = 1
- k = 4

Vertex: (1, 4)
Axis of symmetry: x = 1

To sketch:
- Plot vertex at (1, 4)
- Wide parabola opening down
- Try x = 0 → f(0) = -¼(-1)² + 4 = -¼ + 4 = 3.75 → (0, 3.75)
- x = 2 → same as x=0 → (2, 3.75)
- Maybe try x = -1 → f(-1) = -¼(-2)² + 4 = -¼(4) + 4 = -1 + 4 = 3 → (-1, 3)
- Symmetric point: x = 3 → also 3 → (3, 3)
- Connect with smooth wide downward curve.

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Problem 17:


f(x) = ¼(x + 4)² + 3

Rewrite as: f(x) = ¼(x - (-4))² + 3

So:
- a = ¼ → opens upward, wide
- h = -4
- k = 3

Vertex: (-4, 3)
Axis of symmetry: x = -4

To sketch:
- Plot vertex at (-4, 3)
- Try x = -2 → f(-2) = ¼(-2+4)² + 3 = ¼(4) + 3 = 1 + 3 = 4 → (-2, 4)
- x = -6 → same → (-6, 4)
- x = 0 → f(0) = ¼(4)² + 3 = ¼(16) + 3 = 4 + 3 = 7 → (0, 7)
- x = -8 → same → (-8, 7)
- Draw wide upward U-shape.

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Problem 18:


f(x) = ¼(x + 5)² + 2

Rewrite: f(x) = ¼(x - (-5))² + 2

So:
- a = ¼ → opens upward, wide
- h = -5
- k = 2

Vertex: (-5, 2)
Axis of symmetry: x = -5

To sketch:
- Plot vertex at (-5, 2)
- Try x = -3 → f(-3) = ¼(-3+5)² + 2 = ¼(4) + 2 = 1 + 2 = 3 → (-3, 3)
- x = -7 → same → (-7, 3)
- x = -1 → f(-1) = ¼(-1+5)² + 2 = ¼(16) + 2 = 4 + 2 = 6 → (-1, 6)
- x = -9 → same → (-9, 6)
- Draw wide upward U-shape.

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## Final Answer:

15)
Vertex: (2, -4)
Axis of symmetry: x = 2

16)
Vertex: (1, 4)
Axis of symmetry: x = 1

17)
Vertex: (-4, 3)
Axis of symmetry: x = -4

18)
Vertex: (-5, 2)
Axis of symmetry: x = -5

*(Graphs should be sketched using the vertex, axis of symmetry, and additional calculated points as shown above.)*
Parent Tip: Review the logic above to help your child master the concept of vertex form of parabolas worksheet answers.
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