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Math worksheet for practicing converting quadratic equations to vertex form.

Worksheet titled "Vertex Form of Parabolas" with math problems for converting equations to vertex form.

Worksheet titled "Vertex Form of Parabolas" with math problems for converting equations to vertex form.

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Show Answer Key & Explanations Step-by-step solution for: Vertex Form of Parabolas - Kuta Software - Infinite Algebra 2 Name ...
Let’s solve each problem step by step. We’re converting quadratic equations from standard form (ax² + bx + c) to vertex form:
y = a(x – h)² + k, where (h, k) is the vertex.

We’ll use completing the square for most of these. Let’s go one by one.

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Problem 1: y = x² + 4x + 3



Step 1: Group x terms:
y = (x² + 4x) + 3

Step 2: Complete the square inside the parentheses.
Take half of 4 → 2, then square it → 4.
Add and subtract 4 inside:

y = (x² + 4x + 4 - 4) + 3
= (x² + 4x + 4) - 4 + 3
= (x + 2)² - 1

Final Answer: y = (x + 2)² - 1

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Problem 2: y = x² - 6x + 8



Group: y = (x² - 6x) + 8
Half of -6 is -3, square it → 9

y = (x² - 6x + 9 - 9) + 8
= (x - 3)² - 9 + 8
= (x - 3)² - 1

Final Answer: y = (x - 3)² - 1

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Problem 3: y = x² + 10x + 25



Wait — this is already a perfect square!

x² + 10x + 25 = (x + 5)²

So y = (x + 5)² + 0

Final Answer: y = (x + 5)²

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Problem 4: y = 2x² + 8x + 5



Factor out the 2 first from the x terms:

y = 2(x² + 4x) + 5

Complete the square inside: half of 4 is 2, square is 4.

But we can’t just add 4 — we have to account for the 2 outside.

So:
y = 2(x² + 4x + 4 - 4) + 5
= 2[(x + 2)² - 4] + 5
= 2(x + 2)² - 8 + 5
= 2(x + 2)² - 3

Final Answer: y = 2(x + 2)² - 3

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Problem 5: y = -x² + 2x + 7



Factor out -1 from x terms:

y = -(x² - 2x) + 7

Complete the square: half of -2 is -1, square is 1.

y = -(x² - 2x + 1 - 1) + 7
= -[(x - 1)² - 1] + 7
= -(x - 1)² + 1 + 7
= -(x - 1)² + 8

Final Answer: y = -(x - 1)² + 8

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Problem 6: y = 3x² - 12x + 10



Factor out 3:

y = 3(x² - 4x) + 10

Half of -4 is -2, square is 4.

y = 3(x² - 4x + 4 - 4) + 10
= 3[(x - 2)² - 4] + 10
= 3(x - 2)² - 12 + 10
= 3(x - 2)² - 2

Final Answer: y = 3(x - 2)² - 2

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Problem 7: y = -2x² + 8x - 5



Factor out -2:

y = -2(x² - 4x) - 5

Half of -4 is -2, square is 4.

y = -2(x² - 4x + 4 - 4) - 5
= -2[(x - 2)² - 4] - 5
= -2(x - 2)² + 8 - 5
= -2(x - 2)² + 3

Final Answer: y = -2(x - 2)² + 3

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Problem 8: y = ½x² + 3x + 1



Factor out ½:

y = ½(x² + 6x) + 1

Half of 6 is 3, square is 9.

y = ½(x² + 6x + 9 - 9) + 1
= ½[(x + 3)² - 9] + 1
= ½(x + 3)² - 9/2 + 1
= ½(x + 3)² - 7/2

Final Answer: y = ½(x + 3)² - 7/2

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Problem 9: y = -¼x² + x - 2



Factor out -¼:

y = -¼(x² - 4x) - 2

Half of -4 is -2, square is 4.

y = -¼(x² - 4x + 4 - 4) - 2
= -¼[(x - 2)² - 4] - 2
= -¼(x - 2)² + 1 - 2
= -¼(x - 2)² - 1

Final Answer: y = -¼(x - 2)² - 1

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Problem 10: y = 5x² - 20x + 18



Factor out 5:

y = 5(x² - 4x) + 18

Half of -4 is -2, square is 4.

y = 5(x² - 4x + 4 - 4) + 18
= 5[(x - 2)² - 4] + 18
= 5(x - 2)² - 20 + 18
= 5(x - 2)² - 2

Final Answer: y = 5(x - 2)² - 2

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Problem 11: y = -3x² + 12x - 10



Factor out -3:

y = -3(x² - 4x) - 10

Half of -4 is -2, square is 4.

y = -3(x² - 4x + 4 - 4) - 10
= -3[(x - 2)² - 4] - 10
= -3(x - 2)² + 12 - 10
= -3(x - 2)² + 2

Final Answer: y = -3(x - 2)² + 2

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Problem 12: y = 4x² + 16x + 15



Factor out 4:

y = 4(x² + 4x) + 15

Half of 4 is 2, square is 4.

y = 4(x² + 4x + 4 - 4) + 15
= 4[(x + 2)² - 4] + 15
= 4(x + 2)² - 16 + 15
= 4(x + 2)² - 1

Final Answer: y = 4(x + 2)² - 1

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## Final Answers:

1. y = (x + 2)² - 1
2. y = (x - 3)² - 1
3. y = (x + 5)²
4. y = 2(x + 2)² - 3
5. y = -(x - 1)² + 8
6. y = 3(x - 2)² - 2
7. y = -2(x - 2)² + 3
8. y = ½(x + 3)² - 7/2
9. y = -¼(x - 2)² - 1
10. y = 5(x - 2)² - 2
11. y = -3(x - 2)² + 2
12. y = 4(x + 2)² - 1
Parent Tip: Review the logic above to help your child master the concept of vertex form of parabolas worksheet answers.
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