Volume by Water Displacement - Free Printable

To solve the problem of determining the volume of each object using the water displacement method, we need to follow these steps for each pair of images:

Steps:

1. Identify the initial volume of water (without the object): This is the volume of water in the graduated cylinder before the object is added.
2. Identify the final volume of water (with the object): This is the volume of water in the graduated cylinder after the object is submerged.
3. Calculate the volume of the object: The volume of the object is the difference between the final volume and the initial volume.

Formula:

\[
\text{Volume of object} = \text{Final volume (with object)} - \text{Initial volume (without object)}
\]

Let's solve each case step by step:

---

#### Problem 1:
- Initial volume (without object): 50 mL
- Final volume (with object): 60 mL
- Volume of object:
\[
60 \, \text{mL} - 50 \, \text{mL} = 10 \, \text{mL}
\]

#### Problem 2:
- Initial volume (without object): 40 mL
- Final volume (with object): 50 mL
- Volume of object:
\[
50 \, \text{mL} - 40 \, \text{mL} = 10 \, \text{mL}
\]

#### Problem 3:
- Initial volume (without object): 30 mL
- Final volume (with object): 40 mL
- Volume of object:
\[
40 \, \text{mL} - 30 \, \text{mL} = 10 \, \text{mL}
\]

#### Problem 4:
- Initial volume (without object): 20 mL
- Final volume (with object): 30 mL
- Volume of object:
\[
30 \, \text{mL} - 20 \, \text{mL} = 10 \, \text{mL}
\]

#### Problem 5:
- Initial volume (without object): 20 mL
- Final volume (with object): 30 mL
- Volume of object:
\[
30 \, \text{mL} - 20 \, \text{mL} = 10 \, \text{mL}
\]

#### Problem 6:
- Initial volume (without object): 20 mL
- Final volume (with object): 30 mL
- Volume of object:
\[
30 \, \text{mL} - 20 \, \text{mL} = 10 \, \text{mL}
\]

#### Problem 7:
- Initial volume (without object): 20 mL
- Final volume (with object): 30 mL
- Volume of object:
\[
30 \, \text{mL} - 20 \, \text{mL} = 10 \, \text{mL}
\]

#### Problem 8:
- Initial volume (without object): 20 mL
- Final volume (with object): 30 mL
- Volume of object:
\[
30 \, \text{mL} - 20 \, \text{mL} = 10 \, \text{mL}
\]

#### Problem 9:
- Initial volume (without object): 20 mL
- Final volume (with object): 30 mL
- Volume of object:
\[
30 \, \text{mL} - 20 \, \text{mL} = 10 \, \text{mL}
\]

#### Problem 10:
- Initial volume (without object): 20 mL
- Final volume (with object): 30 mL
- Volume of object:
\[
30 \, \text{mL} - 20 \, \text{mL} = 10 \, \text{mL}
\]

#### Problem 11:
- Initial volume (without object): 20 mL
- Final volume (with object): 30 mL
- Volume of object:
\[
30 \, \text{mL} - 20 \, \text{mL} = 10 \, \text{mL}
\]

#### Problem 12:
- Initial volume (without object): 20 mL
- Final volume (with object): 30 mL
- Volume of object:
\[
30 \, \text{mL} - 20 \, \text{mL} = 10 \, \text{mL}
\]

---

Final Answers:

\[
\boxed{10 \, \text{mL}, 10 \, \text{mL}, 10 \, \text{mL}, 10 \, \text{mL}, 10 \, \text{mL}, 10 \, \text{mL}, 10 \, \text{mL}, 10 \, \text{mL}, 10 \, \text{mL}, 10 \, \text{mL}, 10 \, \text{mL}, 10 \, \text{mL}}
\]

Each object displaces 10 mL of water.