Math worksheet for calculating volume and surface area of cones and spheres.
Worksheet titled "Volume and Surface Area of Cones and Spheres" with eight problems involving calculations of volume, surface area, and radius for cones and spheres, featuring diagrams and measurement labels.
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Step-by-step solution for: Volume and Surface Area of Cones and Spheres Worksheet | PDF ...
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Show Answer Key & Explanations
Step-by-step solution for: Volume and Surface Area of Cones and Spheres Worksheet | PDF ...
Let’s solve each problem step by step.
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Problem 1: Sphere with radius = 2 cm
Volume of sphere = (4/3)πr³
= (4/3) × π × (2)³
= (4/3) × π × 8
= 32π/3 ≈ 33.51 cm³
Surface area of sphere = 4πr²
= 4 × π × (2)²
= 4 × π × 4
= 16π ≈ 50.27 cm²
✔ Volume = 33.51 cm³
✔ Surface area = 50.27 cm²
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Problem 2: Sphere with diameter = 14 mm → radius = 7 mm
Volume = (4/3)πr³
= (4/3) × π × (7)³
= (4/3) × π × 343
= 1372π/3 ≈ 1436.76 mm³
Surface area = 4πr²
= 4 × π × 49
= 196π ≈ 615.75 mm²
✔ Volume = 1436.76 mm³
✔ Surface area = 615.75 mm²
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Problem 3: Sphere with volume = 180 cm³ → find radius
Volume = (4/3)πr³ = 180
→ r³ = 180 × 3 / (4π) = 540 / (4π) = 135 / π
→ r³ ≈ 135 / 3.1416 ≈ 42.97
→ r ≈ ∛42.97 ≈ 3.50 cm
✔ Radius = 3.50 cm
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Problem 4: Sphere with surface area = 25 mm² → find radius
Surface area = 4πr² = 25
→ r² = 25 / (4π) ≈ 25 / 12.5664 ≈ 1.9894
→ r ≈ √1.9894 ≈ 1.41 mm
✔ Radius = 1.41 mm
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Problem 5: Cone with radius = 5 cm, height = 12 cm, slant height = 13 cm
Curved surface area = πrl = π × 5 × 13 = 65π ≈ 204.20 cm²
Total surface area = curved + base = πrl + πr² = 65π + 25π = 90π ≈ 282.74 cm²
✔ Curved surface area = 204.20 cm²
✔ Total surface area = 282.74 cm²
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Problem 6: Cone with radius = 7 cm, slant height = 25 cm → find volume and total surface area
First, find height using Pythagoras:
h = √(l² - r²) = √(25² - 7²) = √(625 - 49) = √576 = 24 cm
Volume = (1/3)πr²h = (1/3) × π × 49 × 24 = (1/3) × 1176π = 392π ≈ 1231.50 cm³
Total surface area = πr² + πrl = π×49 + π×7×25 = 49π + 175π = 224π ≈ 703.72 cm²
✔ Volume = 1231.50 cm³
✔ Total surface area = 703.72 cm²
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Problem 7: Cone with diameter = 14.4 cm → radius = 7.2 cm, height = 9.6 cm
Volume = (1/3)πr²h = (1/3) × π × (7.2)² × 9.6
= (1/3) × π × 51.84 × 9.6
= (1/3) × π × 497.664
= 165.888π ≈ 521.15 cm³
Slant height l = √(r² + h²) = √(7.2² + 9.6²) = √(51.84 + 92.16) = √144 = 12 cm
Total surface area = πr² + πrl = π×51.84 + π×7.2×12 = 51.84π + 86.4π = 138.24π ≈ 434.30 cm²
✔ Volume = 521.15 cm³
✔ Total surface area = 434.30 cm²
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Problem 8: Composite shape — cone on top of hemisphere
Cone: height = 15 cm, radius = ? Wait — diagram shows total height from bottom to tip is 23 cm, and cone height is 15 cm → so hemisphere radius = 23 - 15 = 8 cm? But wait — let’s check labels.
Actually, looking at diagram:
- The cone has height 15 cm (from its base to tip).
- The hemisphere is below it, and the total height from bottom of hemisphere to tip of cone is 23 cm → so hemisphere radius = 23 - 15 = 8 cm.
BUT — the label “15 cm” is pointing to the cone’s height, and “23 cm” is total height. So yes, hemisphere radius = 8 cm.
Wait — actually, re-examining: the diagram says “Cone” with height 15 cm, and “Hemisphere” below it, and total height 23 cm → so hemisphere radius = 23 - 15 = 8 cm. But that would mean the cone’s base radius is also 8 cm (since they’re joined).
So:
Cone: r = 8 cm, h = 15 cm
Hemisphere: r = 8 cm
Volume of cone = (1/3)πr²h = (1/3)π×64×15 = 320π ≈ 1005.31 cm³
Volume of hemisphere = (2/3)πr³ = (2/3)π×512 = 1024π/3 ≈ 1072.33 cm³
Total volume = 320π + 1024π/3 = (960π + 1024π)/3 = 1984π/3 ≈ 2077.64 cm³
Total area = curved surface of cone + curved surface of hemisphere (no flat circles since they’re joined)
Curved surface of cone = πrl
l = √(r² + h²) = √(64 + 225) = √289 = 17 cm
→ π×8×17 = 136π
Curved surface of hemisphere = 2πr² = 2π×64 = 128π
Total area = 136π + 128π = 264π ≈ 829.38 cm²
✔ Volume = 2077.64 cm³
✔ Total area = 829.38 cm²
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Final Answer:
1) Volume = 33.51 cm³, Surface area = 50.27 cm²
2) Volume = 1436.76 mm³, Surface area = 615.75 mm²
3) Radius = 3.50 cm
4) Radius = 1.41 mm
5) Curved surface area = 204.20 cm², Total surface area = 282.74 cm²
6) Volume = 1231.50 cm³, Total surface area = 703.72 cm²
7) Volume = 521.15 cm³, Total surface area = 434.30 cm²
8) Volume = 2077.64 cm³, Total area = 829.38 cm²
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Problem 1: Sphere with radius = 2 cm
Volume of sphere = (4/3)πr³
= (4/3) × π × (2)³
= (4/3) × π × 8
= 32π/3 ≈ 33.51 cm³
Surface area of sphere = 4πr²
= 4 × π × (2)²
= 4 × π × 4
= 16π ≈ 50.27 cm²
✔ Volume = 33.51 cm³
✔ Surface area = 50.27 cm²
---
Problem 2: Sphere with diameter = 14 mm → radius = 7 mm
Volume = (4/3)πr³
= (4/3) × π × (7)³
= (4/3) × π × 343
= 1372π/3 ≈ 1436.76 mm³
Surface area = 4πr²
= 4 × π × 49
= 196π ≈ 615.75 mm²
✔ Volume = 1436.76 mm³
✔ Surface area = 615.75 mm²
---
Problem 3: Sphere with volume = 180 cm³ → find radius
Volume = (4/3)πr³ = 180
→ r³ = 180 × 3 / (4π) = 540 / (4π) = 135 / π
→ r³ ≈ 135 / 3.1416 ≈ 42.97
→ r ≈ ∛42.97 ≈ 3.50 cm
✔ Radius = 3.50 cm
---
Problem 4: Sphere with surface area = 25 mm² → find radius
Surface area = 4πr² = 25
→ r² = 25 / (4π) ≈ 25 / 12.5664 ≈ 1.9894
→ r ≈ √1.9894 ≈ 1.41 mm
✔ Radius = 1.41 mm
---
Problem 5: Cone with radius = 5 cm, height = 12 cm, slant height = 13 cm
Curved surface area = πrl = π × 5 × 13 = 65π ≈ 204.20 cm²
Total surface area = curved + base = πrl + πr² = 65π + 25π = 90π ≈ 282.74 cm²
✔ Curved surface area = 204.20 cm²
✔ Total surface area = 282.74 cm²
---
Problem 6: Cone with radius = 7 cm, slant height = 25 cm → find volume and total surface area
First, find height using Pythagoras:
h = √(l² - r²) = √(25² - 7²) = √(625 - 49) = √576 = 24 cm
Volume = (1/3)πr²h = (1/3) × π × 49 × 24 = (1/3) × 1176π = 392π ≈ 1231.50 cm³
Total surface area = πr² + πrl = π×49 + π×7×25 = 49π + 175π = 224π ≈ 703.72 cm²
✔ Volume = 1231.50 cm³
✔ Total surface area = 703.72 cm²
---
Problem 7: Cone with diameter = 14.4 cm → radius = 7.2 cm, height = 9.6 cm
Volume = (1/3)πr²h = (1/3) × π × (7.2)² × 9.6
= (1/3) × π × 51.84 × 9.6
= (1/3) × π × 497.664
= 165.888π ≈ 521.15 cm³
Slant height l = √(r² + h²) = √(7.2² + 9.6²) = √(51.84 + 92.16) = √144 = 12 cm
Total surface area = πr² + πrl = π×51.84 + π×7.2×12 = 51.84π + 86.4π = 138.24π ≈ 434.30 cm²
✔ Volume = 521.15 cm³
✔ Total surface area = 434.30 cm²
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Problem 8: Composite shape — cone on top of hemisphere
Cone: height = 15 cm, radius = ? Wait — diagram shows total height from bottom to tip is 23 cm, and cone height is 15 cm → so hemisphere radius = 23 - 15 = 8 cm? But wait — let’s check labels.
Actually, looking at diagram:
- The cone has height 15 cm (from its base to tip).
- The hemisphere is below it, and the total height from bottom of hemisphere to tip of cone is 23 cm → so hemisphere radius = 23 - 15 = 8 cm.
BUT — the label “15 cm” is pointing to the cone’s height, and “23 cm” is total height. So yes, hemisphere radius = 8 cm.
Wait — actually, re-examining: the diagram says “Cone” with height 15 cm, and “Hemisphere” below it, and total height 23 cm → so hemisphere radius = 23 - 15 = 8 cm. But that would mean the cone’s base radius is also 8 cm (since they’re joined).
So:
Cone: r = 8 cm, h = 15 cm
Hemisphere: r = 8 cm
Volume of cone = (1/3)πr²h = (1/3)π×64×15 = 320π ≈ 1005.31 cm³
Volume of hemisphere = (2/3)πr³ = (2/3)π×512 = 1024π/3 ≈ 1072.33 cm³
Total volume = 320π + 1024π/3 = (960π + 1024π)/3 = 1984π/3 ≈ 2077.64 cm³
Total area = curved surface of cone + curved surface of hemisphere (no flat circles since they’re joined)
Curved surface of cone = πrl
l = √(r² + h²) = √(64 + 225) = √289 = 17 cm
→ π×8×17 = 136π
Curved surface of hemisphere = 2πr² = 2π×64 = 128π
Total area = 136π + 128π = 264π ≈ 829.38 cm²
✔ Volume = 2077.64 cm³
✔ Total area = 829.38 cm²
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Final Answer:
1) Volume = 33.51 cm³, Surface area = 50.27 cm²
2) Volume = 1436.76 mm³, Surface area = 615.75 mm²
3) Radius = 3.50 cm
4) Radius = 1.41 mm
5) Curved surface area = 204.20 cm², Total surface area = 282.74 cm²
6) Volume = 1231.50 cm³, Total surface area = 703.72 cm²
7) Volume = 521.15 cm³, Total surface area = 434.30 cm²
8) Volume = 2077.64 cm³, Total area = 829.38 cm²
Parent Tip: Review the logic above to help your child master the concept of volume of cylinders and cones worksheet.