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Volume calculation practice for cones, cylinders, and spheres.

Practice worksheet for finding the volume of various geometric figures including cones, cylinders, and spheres with given dimensions.

Practice worksheet for finding the volume of various geometric figures including cones, cylinders, and spheres with given dimensions.

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Show Answer Key & Explanations Step-by-step solution for: Volume 2
Sure! Let’s solve each problem step by step. We’ll use the standard volume formulas for cones, cylinders, and spheres:

---

🔷 Formulas:


- Cone:
\[
V = \frac{1}{3} \pi r^2 h
\]
- Cylinder:
\[
V = \pi r^2 h
\]
- Sphere:
\[
V = \frac{4}{3} \pi r^3
\]

We’ll compute each using \( \pi \approx 3.14 \) unless otherwise specified (some problems may expect exact answers with π, but since it’s a practice worksheet, we’ll use 3.14 for decimal answers).

---

## Problem-by-Problem Solutions:

---

1. Cone: r = 21 ft, h = 35 ft


\[
V = \frac{1}{3} \pi (21)^2 (35) = \frac{1}{3} \pi (441)(35) = \frac{1}{3} \pi (15435) = 5145\pi
\]
Using \( \pi \approx 3.14 \):
\[
V \approx 5145 \times 3.14 = \boxed{16157.3} \text{ ft}^3
\]

---

2. Sphere: r = 6 in


\[
V = \frac{4}{3} \pi (6)^3 = \frac{4}{3} \pi (216) = 288\pi
\]
\[
V \approx 288 \times 3.14 = \boxed{904.32} \text{ in}^3
\]

---

3. Cylinder: r = 4 cm, h = 15 cm


\[
V = \pi (4)^2 (15) = \pi (16)(15) = 240\pi
\]
\[
V \approx 240 \times 3.14 = \boxed{753.6} \text{ cm}^3
\]

---

4. Cylinder: r = 19 m, h = 9 m


\[
V = \pi (19)^2 (9) = \pi (361)(9) = 3249\pi
\]
\[
V \approx 3249 \times 3.14 = \boxed{10205.86} \text{ m}^3
\]

---

5. Cone: r = 24 in, h = 50 in


\[
V = \frac{1}{3} \pi (24)^2 (50) = \frac{1}{3} \pi (576)(50) = \frac{1}{3} \pi (28800) = 9600\pi
\]
\[
V \approx 9600 \times 3.14 = \boxed{30144} \text{ in}^3
\]

---

6. Sphere: r = 3 mm


\[
V = \frac{4}{3} \pi (3)^3 = \frac{4}{3} \pi (27) = 36\pi
\]
\[
V \approx 36 \times 3.14 = \boxed{113.04} \text{ mm}^3
\]

---

7. Sphere: r = 12 cm


\[
V = \frac{4}{3} \pi (12)^3 = \frac{4}{3} \pi (1728) = 2304\pi
\]
\[
V \approx 2304 \times 3.14 = \boxed{7234.56} \text{ cm}^3
\]

---

8. Cylinder: r = 8 ft, h = 6 ft


\[
V = \pi (8)^2 (6) = \pi (64)(6) = 384\pi
\]
\[
V \approx 384 \times 3.14 = \boxed{1205.76} \text{ ft}^3
\]

---

9. Cone: r = 3 cm, h = 6 cm


\[
V = \frac{1}{3} \pi (3)^2 (6) = \frac{1}{3} \pi (9)(6) = \frac{1}{3} \pi (54) = 18\pi
\]
\[
V \approx 18 \times 3.14 = \boxed{56.52} \text{ cm}^3
\]

---

10. Cone: d = 30 m → r = 15 m, h = 29 m


\[
V = \frac{1}{3} \pi (15)^2 (29) = \frac{1}{3} \pi (225)(29) = \frac{1}{3} \pi (6525) = 2175\pi
\]
\[
V \approx 2175 \times 3.14 = \boxed{6831.5} \text{ m}^3
\]

---

11. Cylinder: d = 20 cm → r = 10 cm, h = 10 cm


\[
V = \pi (10)^2 (10) = \pi (100)(10) = 1000\pi
\]
\[
V \approx 1000 \times 3.14 = \boxed{3140} \text{ cm}^3
\]

---

12. Sphere: d = 20 cm → r = 10 cm


\[
V = \frac{4}{3} \pi (10)^3 = \frac{4}{3} \pi (1000) = \frac{4000}{3}\pi \approx 1333.33\pi
\]
\[
V \approx 1333.33 \times 3.14 = \boxed{4186.67} \text{ cm}^3
\]

*(Note: More precisely, \( \frac{4000}{3} \times 3.14 = 4186.666... \))*

---

## 📝 Final Answers Summary:

| # | Shape | Volume (rounded to 2 decimals) |
|---|----------|-------------------------------|
| 1 | Cone | 16157.30 ft³ |
| 2 | Sphere | 904.32 in³ |
| 3 | Cylinder | 753.60 cm³ |
| 4 | Cylinder | 10205.86 m³ |
| 5 | Cone | 30144.00 in³ |
| 6 | Sphere | 113.04 mm³ |
| 7 | Sphere | 7234.56 cm³ |
| 8 | Cylinder | 1205.76 ft³ |
| 9 | Cone | 56.52 cm³ |
|10 | Cone | 6831.50 m³ |
|11 | Cylinder | 3140.00 cm³ |
|12 | Sphere | 4186.67 cm³ |

---

All volumes calculated using standard formulas and π ≈ 3.14.

Let me know if you’d like the answers in terms of π instead of decimals — or if you want to see step-by-step work for any specific one!
Parent Tip: Review the logic above to help your child master the concept of volume of spheres cones and cylinders worksheet.
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