Fractions Word Problems | Grade1to6.com - Free Printable

Let's solve each problem step by step.

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Problem 1:

Susan had a meter of rope. She gave \(\frac{1}{5}\)th to her sister and \(\frac{2}{5}\)th to her brother for their craft activity. How much portion of the rope will be with Susan now?

#### Solution:
1. Total rope: 1 meter.
2. Portion given to her sister: \(\frac{1}{5}\).
3. Portion given to her brother: \(\frac{2}{5}\).

To find the total portion given away:
\[
\frac{1}{5} + \frac{2}{5} = \frac{3}{5}
\]

4. Portion left with Susan: Subtract the portion given away from the total rope:
\[
1 - \frac{3}{5} = \frac{5}{5} - \frac{3}{5} = \frac{2}{5}
\]

#### Final Answer:
\[
\boxed{\frac{2}{5}}
\]

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Problem 2:

A shopkeeper had 150 mobile phones. He sold \(\frac{1}{3}\)rd of them in the first week. How many mobile phones will be left with him now?

#### Solution:
1. Total mobile phones: 150.
2. Portion sold: \(\frac{1}{3}\) of 150:
\[
\frac{1}{3} \times 150 = 50
\]

3. Mobile phones left: Subtract the number sold from the total:
\[
150 - 50 = 100
\]

#### Final Answer:
\[
\boxed{100}
\]

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Problem 3:

Rebecca spent \(\frac{1}{10}\)th of her pocket money of $100 to buy a fidget spinner, \(\frac{2}{10}\)th on buying new books. How much did she spend on buying new books and how much will she be left with now?

#### Solution:
1. Total pocket money: $100.
2. Amount spent on fidget spinner: \(\frac{1}{10}\) of $100:
\[
\frac{1}{10} \times 100 = 10
\]

3. Amount spent on new books: \(\frac{2}{10}\) of $100:
\[
\frac{2}{10} \times 100 = 20
\]

4. Total amount spent: Add the amounts spent on the fidget spinner and new books:
\[
10 + 20 = 30
\]

5. Amount left: Subtract the total amount spent from the total pocket money:
\[
100 - 30 = 70
\]

#### Final Answers:
- Amount spent on new books: \(\boxed{20}\)
- Amount left: \(\boxed{70}\)

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Problem 4:

Tom's father filled 50 gallons of petrol in his car. After driving for 3 days, he said \(\frac{1}{4}\)th of the petrol is over. How many gallons of petrol is left in the car now?

#### Solution:
1. Total petrol: 50 gallons.
2. Portion used: \(\frac{1}{4}\) of 50:
\[
\frac{1}{4} \times 50 = 12.5
\]

3. Petrol left: Subtract the portion used from the total:
\[
50 - 12.5 = 37.5
\]

#### Final Answer:
\[
\boxed{37.5}
\]

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Problem 5:

Anne's mom gave her a box containing 30 chocolates. Anne gave \(\frac{1}{6}\)th of the chocolates to Anna her friend and \(\frac{2}{6}\)th to Frank her brother. How many chocolates did she give to Anna and Frank each? How many will be left with Anne now?

#### Solution:
1. Total chocolates: 30.
2. Chocolates given to Anna: \(\frac{1}{6}\) of 30:
\[
\frac{1}{6} \times 30 = 5
\]

3. Chocolates given to Frank: \(\frac{2}{6}\) of 30:
\[
\frac{2}{6} \times 30 = 10
\]

4. Total chocolates given away: Add the chocolates given to Anna and Frank:
\[
5 + 10 = 15
\]

5. Chocolates left with Anne: Subtract the total chocolates given away from the total:
\[
30 - 15 = 15
\]

#### Final Answers:
- Chocolates given to Anna: \(\boxed{5}\)
- Chocolates given to Frank: \(\boxed{10}\)
- Chocolates left with Anne: \(\boxed{15}\)

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Final Summary of Answers:

1. \(\boxed{\frac{2}{5}}\)
2. \(\boxed{100}\)
3. Amount spent on new books: \(\boxed{20}\), Amount left: \(\boxed{70}\)
4. \(\boxed{37.5}\)
5. Chocolates given to Anna: \(\boxed{5}\), Chocolates given to Frank: \(\boxed{10}\), Chocolates left with Anne: \(\boxed{15}\)