To solve the problem of finding the area of each rectangle, we use the formula for the area of a rectangle:
\[
\text{Area} = \text{length} \times \text{width}
\]
Let's calculate the area for each rectangle step by step.
---
Rectangle 1
- Length: \( 13 \, \text{in} \)
- Width: \( 7 \, \text{in} \)
\[
\text{Area} = 13 \, \text{in} \times 7 \, \text{in} = 91 \, \text{in}^2
\]
---
Rectangle 2
- Length: \( 22 \, \text{ft} \)
- Width: \( 8 \, \text{ft} \)
\[
\text{Area} = 22 \, \text{ft} \times 8 \, \text{ft} = 176 \, \text{ft}^2
\]
---
Rectangle 3
- Length: \( 11 \, \text{mm} \)
- Width: \( 4 \, \text{mm} \)
\[
\text{Area} = 11 \, \text{mm} \times 4 \, \text{mm} = 44 \, \text{mm}^2
\]
---
Rectangle 4
- Length: \( 19 \, \text{cm} \)
- Width: \( 9 \, \text{cm} \)
\[
\text{Area} = 19 \, \text{cm} \times 9 \, \text{cm} = 171 \, \text{cm}^2
\]
---
Rectangle 5
- Length: \( 12 \, \text{yd} \)
- Width: \( 3 \, \text{yd} \)
\[
\text{Area} = 12 \, \text{yd} \times 3 \, \text{yd} = 36 \, \text{yd}^2
\]
---
Rectangle 6
- Length: \( 10 \, \text{km} \)
- Width: \( 6 \, \text{km} \)
\[
\text{Area} = 10 \, \text{km} \times 6 \, \text{km} = 60 \, \text{km}^2
\]
---
Rectangle 7
- Length: \( 18 \, \text{m} \)
- Width: \( 8 \, \text{m} \)
\[
\text{Area} = 18 \, \text{m} \times 8 \, \text{m} = 144 \, \text{m}^2
\]
---
Rectangle 8
- Length: \( 7.5 \, \text{in} \)
- Width: \( 3.5 \, \text{in} \)
\[
\text{Area} = 7.5 \, \text{in} \times 3.5 \, \text{in} = 26.25 \, \text{in}^2
\]
---
Final Answers
\[
\boxed{
\begin{array}{ll}
1. & 91 \, \text{in}^2 \\
2. & 176 \, \text{ft}^2 \\
3. & 44 \, \text{mm}^2 \\
4. & 171 \, \text{cm}^2 \\
5. & 36 \, \text{yd}^2 \\
6. & 60 \, \text{km}^2 \\
7. & 144 \, \text{m}^2 \\
8. & 26.25 \, \text{in}^2 \\
\end{array}
}
\]
Parent Tip: Review the logic above to help your child master the concept of worksheet for finding area of rectangles and squares.
