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Writing Linear Inequalities Worksheet featuring six graphs to derive inequalities from given shaded regions.

Six graphs on a coordinate plane, each showing a linear inequality with a shaded region and a line, labeled 1 through 6, from a "Writing Linear Inequalities Worksheet" by Math Monks.

Six graphs on a coordinate plane, each showing a linear inequality with a shaded region and a line, labeled 1 through 6, from a "Writing Linear Inequalities Worksheet" by Math Monks.

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Show Answer Key & Explanations Step-by-step solution for: Writing Inequalities Worksheets with Answer Key
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Let's solve each of the six problems on the "Writing Linear Inequalities Worksheet" by analyzing the graphs and deriving the correct inequality for each. We’ll go step-by-step.

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General Steps to Write an Inequality from a Graph:



1. Identify the line: Find the equation of the boundary line (slope-intercept form: $ y = mx + b $).
2. Determine if the line is solid or dashed:
- Solid line → includes equality (≤ or ≥)
- Dashed line → strict inequality (< or >)
3. Determine which side is shaded:
- Pick a test point (like the origin (0,0)) and see if it satisfies the inequality.
- If yes, that side is shaded; otherwise, the other side is.
4. Write the inequality using the line equation and appropriate inequality sign.

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Let’s go through each graph:

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Problem 1



- Line: Passes through (0, 2) and (6, -4).
Slope $ m = \frac{-4 - 2}{6 - 0} = \frac{-6}{6} = -1 $
So, $ y = -x + 2 $
- Line is solid → includes equality
- Shaded region: Below the line (includes points like (0,0))
- Test (0,0): $ 0 \leq -0 + 2 $ → $ 0 \leq 2 $ → True
- Inequality: $ y \leq -x + 2 $

✔ Answer: $ y \leq -x + 2 $

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Problem 2



- Line: Passes through (0, 2) and (2, 8)
Slope $ m = \frac{8 - 2}{2 - 0} = \frac{6}{2} = 3 $
Equation: $ y = 3x + 2 $
- Line is solid
- Shaded region: Above the line? Let’s test (0,0):
$ 0 \geq 3(0) + 2 $? → $ 0 \geq 2 $? No → so shaded region is not above
Try a point in shaded area, e.g., (0, -5): $ -5 \geq 2 $? No → wait, look at graph: shaded is below the line?
Wait — actually, shaded region is to the left of the line? No — let’s recheck.

Wait: The shaded region is above the line? But the line goes up from bottom-left to top-right. Shaded region is on the right side of the line?

Wait — no: look carefully. The shaded region is to the left of the line? Actually, no.

Let me analyze:

The line passes through (0,2), (2,8), and (−2, −4). It has positive slope.

But the shaded region is below the line? Let’s test (0,0):

Is (0,0) shaded? Yes — it's in the blue area.

Check: $ 0 \leq 3(0) + 2 $ → $ 0 \leq 2 $ → True

So shaded region is below the line → $ y \leq 3x + 2 $

But wait — is the line solid? Yes.

And shaded region includes (0,0), which is below the line.

✔ Answer: $ y \leq 3x + 2 $

Wait — but looking at the graph again: the shaded region appears to be on the side where x is small, but since the line has positive slope, and shaded is below, yes.

But wait — let’s check another point: say (0, 10) — not shaded. (0, 0) is shaded. (0, 3): $ 3 \leq 2 $? No → so only below.

Yes, so shaded region is below the line.

✔ Answer: $ y \leq 3x + 2 $

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Problem 3



- Vertical line at $ x = 2 $
- Solid line → includes equality
- Shaded region: To the right of $ x = 2 $
- Test point: (3,0) → $ x = 3 > 2 $ → shaded
- (1,0) → not shaded
- So: $ x \geq 2 $

✔ Answer: $ x \geq 2 $

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Problem 4



- Line: Passes through (0, 9) and (6, -6)
- Slope $ m = \frac{-6 - 9}{6 - 0} = \frac{-15}{6} = -\frac{5}{2} $
- Equation: $ y = -\frac{5}{2}x + 9 $
- Solid line → includes equality
- Shaded region: Below the line? Test (0,0):
$ 0 \leq -\frac{5}{2}(0) + 9 $? → $ 0 \leq 9 $ → True → so shaded region includes origin
- So: $ y \leq -\frac{5}{2}x + 9 $

✔ Answer: $ y \leq -\frac{5}{2}x + 9 $

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Problem 5



- Line: Passes through (0, -2) and (4, 2)
- Slope $ m = \frac{2 - (-2)}{4 - 0} = \frac{4}{4} = 1 $
- Equation: $ y = x - 2 $
- Dashed line → strict inequality
- Shaded region: Below the line? Test (0,0):
$ 0 < 0 - 2 $? → $ 0 < -2 $? False → so not shaded
Try (0, -3): $ -3 < 0 - 2 $? → $ -3 < -2 $? True → and (0,-3) is shaded? Yes — looks like shaded region is below the line
But (0,0) is not shaded, and (0,-3) is shaded → so shaded region is below the line

Wait: $ y < x - 2 $? At (0,-3): $ -3 < -2 $? Yes → true

But is the line dashed? Yes → so strict inequality

So: $ y < x - 2 $

Wait — but look: the shaded region is below the line, and line is dashed → yes.

✔ Answer: $ y < x - 2 $

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Problem 6



- Same line as Problem 5: $ y = x - 2 $
- But line is solid → includes equality
- Shaded region: Same as before? Still below? Let’s test (0,0):
$ 0 \leq 0 - 2 $? → $ 0 \leq -2 $? False → so (0,0) is not shaded
Try (0,-3): $ -3 \leq -2 $? True → and it is shaded

So shaded region is below the line → $ y \leq x - 2 $

✔ Answer: $ y \leq x - 2 $

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✔ Final Answers:



1. $ y \leq -x + 2 $
2. $ y \leq 3x + 2 $
3. $ x \geq 2 $
4. $ y \leq -\frac{5}{2}x + 9 $
5. $ y < x - 2 $
6. $ y \leq x - 2 $

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