Free Printable Naming Ionic Compounds Worksheets - Free Printable

Here are the correct formulas for the ionic compounds on your worksheet.

1. Write the correct formula in each corresponding box

To solve this table, you match the positive ion (cation) from the top row with the negative ion (anion) from the left column so that the total charge equals zero.

| | Zinc ($Zn^{2+}$) | Iron (II) ($Fe^{2+}$) | Iron (III) ($Fe^{3+}$) | Gallium ($Ga^{3+}$) | Silver ($Ag^{+}$) | Lead (IV) ($Pb^{4+}$) |
| :--- | :---: | :---: | :---: | :---: | :---: | :---: |
| Chloride ($Cl^-$) | $ZnCl_2$ | $FeCl_2$ | $FeCl_3$ | $GaCl_3$ | $AgCl$ | $PbCl_4$ |
| Acetate ($C_2H_3O_2^-$) | $Zn(C_2H_3O_2)_2$ | $Fe(C_2H_3O_2)_2$ | $Fe(C_2H_3O_2)_3$ | $Ga(C_2H_3O_2)_3$ | $AgC_2H_3O_2$ | $Pb(C_2H_3O_2)_4$ |
| Oxide ($O^{2-}$) | $ZnO$ | $FeO$ | $Fe_2O_3$ | $Ga_2O_3$ | $Ag_2O$ | $PbO_2$ |
| Nitrate ($NO_3^-$) | $Zn(NO_3)_2$ | $Fe(NO_3)_2$ | $Fe(NO_3)_3$ | $Ga(NO_3)_3$ | $AgNO_3$ | $Pb(NO_3)_4$ |
| Nitride ($N^{3-}$) | $Zn_3N_2$ | $Fe_3N_2$ | $FeN$ | $GaN$ | $Ag_3N$ | $Pb_3N_4$ |
| Sulfate ($SO_4^{2-}$) | $ZnSO_4$ | $FeSO_4$ | $Fe_2(SO_4)_3$ | $Ga_2(SO_4)_3$ | $Ag_2SO_4$ | $Pb(SO_4)_2$ |

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2. Write the formulas for the given ionic compounds

a. Lithium Acetate
* Lithium is in Group 1, so it has a +1 charge ($Li^+$).
* Acetate is a polyatomic ion with a -1 charge ($C_2H_3O_2^-$).
* They balance perfectly (1 to 1).
* Formula: $LiC_2H_3O_2$

b. Cobalt (III) Chloride
* The Roman numeral (III) tells us Cobalt has a +3 charge ($Co^{3+}$).
* Chloride is in Group 17, so it has a -1 charge ($Cl^-$).
* You need three chloride ions to balance one cobalt ion.
* Formula: $CoCl_3$

c. Copper (II) Chlorate
* The Roman numeral (II) tells us Copper has a +2 charge ($Cu^{2+}$).
* Chlorate is a polyatomic ion with a -1 charge ($ClO_3^-$).
* You need two chlorate ions to balance one copper ion. Because chlorate is a group, use parentheses.
* Formula: $Cu(ClO_3)_2$

d. Titanium (II) Selenide
* The Roman numeral (II) tells us Titanium has a +2 charge ($Ti^{2+}$).
* Selenide is in the same family as Oxygen and Sulfur (Group 16), so it has a -2 charge ($Se^{2-}$).
* The charges cancel out (2 and -2).
* Formula: $TiSe$

e. Calcium Oxide
* Calcium is in Group 2, so it has a +2 charge ($Ca^{2+}$).
* Oxide is in Group 16, so it has a -2 charge ($O^{2-}$).
* The charges cancel out.
* Formula: $CaO$

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Final Answer:

Part 1 Table:
* Row 1 (Chloride): $ZnCl_2$, $FeCl_2$, $FeCl_3$, $GaCl_3$, $AgCl$, $PbCl_4$
* Row 2 (Acetate): $Zn(C_2H_3O_2)_2$, $Fe(C_2H_3O_2)_2$, $Fe(C_2H_3O_2)_3$, $Ga(C_2H_3O_2)_3$, $AgC_2H_3O_2$, $Pb(C_2H_3O_2)_4$
* Row 3 (Oxide): $ZnO$, $FeO$, $Fe_2O_3$, $Ga_2O_3$, $Ag_2O$, $PbO_2$
* Row 4 (Nitrate): $Zn(NO_3)_2$, $Fe(NO_3)_2$, $Fe(NO_3)_3$, $Ga(NO_3)_3$, $AgNO_3$, $Pb(NO_3)_4$
* Row 5 (Nitride): $Zn_3N_2$, $Fe_3N_2$, $FeN$, $GaN$, $Ag_3N$, $Pb_3N_4$
* Row 6 (Sulfate): $ZnSO_4$, $FeSO_4$, $Fe_2(SO_4)_3$, $Ga_2(SO_4)_3$, $Ag_2SO_4$, $Pb(SO_4)_2$

Part 2 Formulas:
a. $LiC_2H_3O_2$
b. $CoCl_3$
c. $Cu(ClO_3)_2$
d. $TiSe$
e. $CaO$