Ionic Compound Formula Writing-2 | PDF | Acetate | Hydroxide - Free Printable

Let’s solve this step by step.

We’re writing chemical formulas for ionic compounds. That means we need to balance the charges of the cation (positive ion) and anion (negative ion) so the total charge is zero.

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Part 1: Table – Intersection of Cations and Anions

We’ll go row by row, column by column.

Remember:
- Zinc = Zn²⁺
- Iron(II) = Fe²⁺
- Iron(III) = Fe³⁺
- Gallium = Ga³⁺
- Silver = Ag⁺
- Lead(IV) = Pb⁴⁺

Anions:
- Chloride = Cl⁻ → already done: ZnCl₂
- Acetate = C₂H₃O₂⁻ or CH₃COO⁻ → usually written as C₂H₃O₂⁻
- Nitrate = NO₃⁻
- Oxide = O²⁻
- Nitride = N³⁻
- Sulfate = SO₄²⁻

Now fill in each box:

Row 1: chloride (Cl⁻)
Already given: ZnCl₂
Fe²⁺ + Cl⁻ → FeCl₂
Fe³⁺ + Cl⁻ → FeCl₃
Ga³⁺ + Cl⁻ → GaCl₃
Ag⁺ + Cl⁻ → AgCl
Pb⁴⁺ + Cl → PbCl₄

Row 2: acetate (C₂H₃O₂)
Zn²⁺ → Zn(C₂H₃O₂)₂
Fe²⁺ → Fe(C₂H₃O₂)₂
Fe³⁺ → Fe(C₂H₃O₂)₃
Ga³⁺ → Ga(C₂H₃O₂)₃
Ag⁺ → AgC₂H₃O₂
Pb⁴⁺ → Pb(C₂H₃O₂)₄

Row 3: nitrate (NO₃⁻)
Zn²⁺ → Zn(NO₃)₂
Fe²⁺ → Fe(NO₃)₂
Fe³⁺ → Fe(NO₃)₃
Ga³⁺ → Ga(NO₃)₃
Ag → AgNO₃
Pb⁴⁺ → Pb(NO₃)₄

Row 4: oxide (O²⁻)
Zn²⁺ → ZnO
Fe²⁺ → FeO
Fe³⁺ → Fe₂O₃ (because 2×Fe³⁺ = +6, 3×O²⁻ = -6)
Ga³⁺ → Ga₂O₃
Ag⁺ → Ag₂O (2×Ag⁺ = +2, O²⁻ = -2)
Pb⁴⁺ → PbO₂ (Pb⁴⁺ and 2×O²⁻ = -4)

Row 5: nitride (N³⁻)
Zn²⁺ → Zn₃N₂ (3×Zn²⁺ = +6, 2×N³⁻ = -6)
Fe²⁺ → Fe₃N₂
Fe³⁺ → FeN (Fe³⁺ and N³⁻ cancel)
Ga³⁺ → GaN
Ag⁺ → Ag₃N
Pb⁴⁺ → Pb₃N₄ (3×Pb⁴⁺ = +12, 4×N³⁻ = -12)

Row 6: sulfate (SO₄²⁻)
Zn²⁺ → ZnSO₄
Fe²⁺ → FeSO₄
Fe³⁺ → Fe₂(SO₄)₃ (2×Fe³⁺ = +6, 3×SO₄²⁻ = -6)
Ga³⁺ → Ga₂(SO₄)₃
Ag⁺ → Ag₂SO₄
Pb⁴⁺ → Pb(SO₄)₂ (Pb⁴⁺ and 2×SO₄²⁻ = -4)

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Part 2: Write formulas for named compounds

1) copper (II) chloride → Cu²⁺ and Cl⁻ → CuCl₂
2) lithium acetate → Li⁺ and C₂H₃O₂⁻ → LiC₂H₃O₂
3) vanadium (III) selenide → V³⁺ and Se²⁻ → need LCM of 3 and 2 = 6 → V₂Se₃ → V₂Se₃
4) manganese (IV) nitride → Mn⁴⁺ and N³⁻ → LCM of 4 and 3 = 12 → Mn₃N₄ → Mn₃N₄
5) beryllium oxide → Be²⁺ and O²⁻ → BeO
6) sodium sulfate → Na⁺ and SO₄²⁻ → Na₂SO₄
7) aluminum arsenide → Al³⁺ and As³⁻ → AlAs
8) potassium permanganate → K⁺ and MnO₄⁻ → KMnO₄
9) chromium (VI) cyanide → Cr⁶⁺ and CN⁻ → Cr(CN)₆
10) tin (II) sulfite → Sn²⁺ and SO₃²⁻ → SnSO₃
11) vanadium (V) fluoride → V⁵⁺ and F → VF₅
12) ammonium nitrate → NH₄⁺ and NO⁻ → NH₄NO₃

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Final Answer:

Table filled:

| | zinc | iron (II) | iron (III) | gallium | silver | lead (IV) |
|----------|------------|-------------|-------------|-------------|-------------|-------------|
| chloride | ZnCl₂ | FeCl₂ | FeCl₃ | GaCl₃ | AgCl | PbCl₄ |
| acetate | Zn(C₂H₃O₂)₂| Fe(C₂H₃O₂)₂ | Fe(C₂H₃O₂)₃ | Ga(C₂H₃O₂)₃ | AgC₂H₃O₂ | Pb(C₂H₃O₂)₄ |
| nitrate | Zn(NO₃)₂ | Fe(NO₃)₂ | Fe(NO₃)₃ | Ga(NO₃)₃ | AgNO₃ | Pb(NO₃)₄ |
| oxide | ZnO | FeO | Fe₂O₃ | Ga₂O₃ | Ag₂O | PbO₂ |
| nitride | Zn₃N₂ | Fe₃N₂ | FeN | GaN | Ag₃N | Pb₃N₄ |
| sulfate | ZnSO₄ | FeSO₄ | Fe₂(SO₄)₃ | Ga₂(SO₄)₃ | Ag₂SO₄ | Pb(SO₄)₂ |

List answers:

1) CuCl₂
2) LiC₂H₃O₂
3) V₂Se₃
4) Mn₃N₄
5) BeO
6) Na₂SO₄
7) AlAs
8) KMnO₄
9) Cr(CN)₆
10) SnSO₃
11) VF₅
12) NH₄NO₃