SOLUTION: 30 60 90 triangle practice 1w3mynu - Studypool - Free Printable
Educational worksheet: SOLUTION: 30 60 90 triangle practice 1w3mynu - Studypool. Download and print for classroom or home learning activities.
PNG
1275×1650
55.6 KB
Free · Personal Use
Quality Assured by Worksheets Library Team
Reviewed for educational accuracy and age-appropriateness
ID: #1146186
⭐
Show Answer Key & Explanations
Step-by-step solution for: SOLUTION: 30 60 90 triangle practice 1w3mynu - Studypool
▼
Show Answer Key & Explanations
Step-by-step solution for: SOLUTION: 30 60 90 triangle practice 1w3mynu - Studypool
Let’s solve each problem one by one. These are all right triangles with special angles (30° or 60°), so we can use the properties of 30-60-90 triangles.
In a 30-60-90 triangle, the sides are always in this ratio:
- Side opposite 30° → shortest leg = x
- Side opposite 60° → longer leg = x√3
- Hypotenuse (opposite 90°) = 2x
We’ll apply this to each problem.
---
Problem 11:
Triangle has:
- Right angle at bottom left
- Angle at top left = 60° → so angle at bottom right = 30°
- Hypotenuse = 44
- Side adjacent to 60° (bottom side) = x
- Side opposite 60° (left side) = y
Since hypotenuse = 2x (in our ratio), then:
→ 2x = 44 → x = 22
Then, side opposite 60° = x√3 = 22√3 → that’s y
Wait — let’s double-check which side is which.
Actually, in standard labeling for 30-60-90:
If the 30° angle is at the bottom right, then:
- Side opposite 30° = short leg = y? No — wait, look again.
The triangle:
Top vertex: 60°
Bottom left: right angle (90°)
Bottom right: must be 30°
So:
- Side opposite 30° (at bottom right) = vertical side = y → this is the SHORT LEG
- Side opposite 60° (at top) = horizontal side = x → this is the LONG LEG
- Hypotenuse = 44
In 30-60-90:
Short leg (opp 30°) = x
Long leg (opp 60°) = x√3
Hypotenuse = 2x
Here, hypotenuse = 44 → 2x = 44 → x = 22
So short leg (y) = 22
Long leg (x) = 22√3
But wait — in the diagram, they labeled:
Vertical side = y
Horizontal side = x
Angle at top = 60° → so side opposite 60° is the horizontal side → that should be long leg → x = long leg = x√3? Confusing notation.
Let me redefine using variables from the diagram.
Given:
- Angle at top = 60°
- Right angle at bottom left
- So angle at bottom right = 30°
- Hypotenuse = 44 (side between top and bottom right)
- Vertical side (from top to bottom left) = y → this is adjacent to 60°, opposite to 30° → so it's the SHORT LEG
- Horizontal side (from bottom left to bottom right) = x → opposite to 60° → LONG LEG
So:
Short leg (y) = ?
Long leg (x) = ?
Hypotenuse = 44
In 30-60-90:
Short leg : Long leg : Hypotenuse = 1 : √3 : 2
So if hypotenuse = 2 parts = 44 → 1 part = 22
Thus:
Short leg (y) = 22
Long leg (x) = 22√3
✔ Final for #11:
x = 22√3
y = 22
---
Problem 12:
Triangle:
Right angle at bottom right
Angle at top = 30° → so angle at bottom left = 60°
Side adjacent to 30° (vertical side) = 29√3
Hypotenuse = u
Base (horizontal) = v
Labeling:
Top vertex: 30°
Bottom right: 90°
Bottom left: 60°
So:
- Side opposite 30° = base = v → SHORT LEG
- Side opposite 60° = vertical side = 29√3 → LONG LEG
- Hypotenuse = u
In 30-60-90:
Short leg = x
Long leg = x√3
Hypotenuse = 2x
Here, long leg = 29√3 = x√3 → so x = 29
Then:
Short leg (v) = x = 29
Hypotenuse (u) = 2x = 58
✔ Final for #12:
u = 58
v = 29
---
Problem 13:
Triangle:
Right angle at bottom right
Angle at bottom left = 60° → so angle at top = 30°
Vertical side = 36 → this is opposite 60° → LONG LEG
Hypotenuse = a
Base = b → opposite 30° → SHORT LEG
So:
Long leg = 36 = x√3 → x = 36 / √3 = 12√3 (rationalize: 36/√3 * √3/√3 = 36√3 / 3 = 12√3)
Wait — better to keep as:
x = 36 / √3 = 12√3? Let’s compute numerically later, but algebraically:
Set short leg = x
Then long leg = x√3 = 36 → x = 36 / √3 = 12√3? Actually:
36 / √3 = (36 √3) / 3 = 12√3 → yes.
But actually, we want exact values.
So:
Short leg (b) = x = 36 / √3 = 12√3? Wait no:
If long leg = x√3 = 36 → then x = 36 / √3
Rationalize: (36 / √3) * (√3 / √3) = (36√3)/3 = 12√3
So short leg b = 12√3
Hypotenuse a = 2x = 2*(12√3) = 24√3
But wait — is that correct?
Alternative approach: since long leg = 36, and in ratio long leg = x√3, hypotenuse = 2x
So from long leg: x√3 = 36 → x = 36/√3 = 12√3
Then hypotenuse = 2x = 24√3
Short leg = x = 12√3
But let’s check: is short leg really 12√3? That seems large.
Wait — maybe I mixed up.
In triangle:
Angle at bottom left = 60° → so side opposite to it is the vertical side = 36 → that’s correct, long leg.
Side opposite 30° (top angle) is base = b → short leg.
Yes.
So:
b = short leg = x
36 = long leg = x√3 → x = 36/√3 = 12√3
a = hypotenuse = 2x = 24√3
But 12√3 is about 20.78, and 24√3 ≈ 41.57, and 36 is given — does Pythagoras hold?
Check: (12√3)^2 + 36^2 =? (24√3)^2
Left: (144 * 3) + 1296 = 432 + 1296 = 1728
Right: (576 * 3) = 1728 → yes, correct.
So:
a = 24√3
b = 12√3
But perhaps simplify or write differently? The problem might expect simplified radical form.
Alternatively, sometimes people write without radicals in denominator, but here it’s fine.
Wait — another way: since long leg = 36, and in 30-60-90, long leg = (√3/2) * hypotenuse? Let’s see.
Standard ratios:
If hypotenuse = H, then:
Short leg = H/2
Long leg = (H√3)/2
So here, long leg = 36 = (H√3)/2 → H = 36 * 2 / √3 = 72 / √3 = 24√3 → same as before.
Short leg = H/2 = 12√3
So yes.
✔ Final for #13:
a = 24√3
b = 12√3
---
Problem 14:
Triangle:
Right angle at bottom left
Angle at bottom right = 30° → so angle at top = 60°
Vertical side = 4√3 → this is opposite 30°? Let’s see.
Vertices:
Top: ?
Bottom left: 90°
Bottom right: 30° → so top angle = 60°
Sides:
Vertical side (from top to bottom left) = 4√3 → this is adjacent to 30°, opposite to 60° → so it’s the LONG LEG
Horizontal side (base) = y → opposite 30° → SHORT LEG
Hypotenuse = x
So:
Long leg = 4√3 = x√3 (if short leg = x) → so x = 4
Then:
Short leg (y) = x = 4
Hypotenuse (x) = 2x = 8
Wait — variable conflict: they used x for hypotenuse, but in ratio I used x for short leg.
Let me use different letter.
Let short leg = s
Then long leg = s√3 = 4√3 → so s = 4
Then hypotenuse = 2s = 8
So:
y = short leg = 4
x = hypotenuse = 8
✔ Final for #14:
x = 8
y = 4
---
Now, problems 15–18 are too blurry to read accurately. Since the user didn’t specify which ones to solve, and only 11–14 are clear, I’ll assume we’re to solve 11–14.
Final Answers:
11) x = 22√3, y = 22
12) u = 58, v = 29
13) a = 24√3, b = 12√3
14) x = 8, y = 4
But let me write them clearly per problem.
For problem 11:
x = 22√3
y = 22
Problem 12:
u = 58
v = 29
Problem 13:
a = 24√3
b = 12√3
Problem 14:
x = 8
y = 4
I think that’s all.
Final Answer:
11) x = 22√3, y = 22
12) u = 58, v = 29
13) a = 24√3, b = 12√3
14) x = 8, y = 4
In a 30-60-90 triangle, the sides are always in this ratio:
- Side opposite 30° → shortest leg = x
- Side opposite 60° → longer leg = x√3
- Hypotenuse (opposite 90°) = 2x
We’ll apply this to each problem.
---
Problem 11:
Triangle has:
- Right angle at bottom left
- Angle at top left = 60° → so angle at bottom right = 30°
- Hypotenuse = 44
- Side adjacent to 60° (bottom side) = x
- Side opposite 60° (left side) = y
Since hypotenuse = 2x (in our ratio), then:
→ 2x = 44 → x = 22
Then, side opposite 60° = x√3 = 22√3 → that’s y
Wait — let’s double-check which side is which.
Actually, in standard labeling for 30-60-90:
If the 30° angle is at the bottom right, then:
- Side opposite 30° = short leg = y? No — wait, look again.
The triangle:
Top vertex: 60°
Bottom left: right angle (90°)
Bottom right: must be 30°
So:
- Side opposite 30° (at bottom right) = vertical side = y → this is the SHORT LEG
- Side opposite 60° (at top) = horizontal side = x → this is the LONG LEG
- Hypotenuse = 44
In 30-60-90:
Short leg (opp 30°) = x
Long leg (opp 60°) = x√3
Hypotenuse = 2x
Here, hypotenuse = 44 → 2x = 44 → x = 22
So short leg (y) = 22
Long leg (x) = 22√3
But wait — in the diagram, they labeled:
Vertical side = y
Horizontal side = x
Angle at top = 60° → so side opposite 60° is the horizontal side → that should be long leg → x = long leg = x√3? Confusing notation.
Let me redefine using variables from the diagram.
Given:
- Angle at top = 60°
- Right angle at bottom left
- So angle at bottom right = 30°
- Hypotenuse = 44 (side between top and bottom right)
- Vertical side (from top to bottom left) = y → this is adjacent to 60°, opposite to 30° → so it's the SHORT LEG
- Horizontal side (from bottom left to bottom right) = x → opposite to 60° → LONG LEG
So:
Short leg (y) = ?
Long leg (x) = ?
Hypotenuse = 44
In 30-60-90:
Short leg : Long leg : Hypotenuse = 1 : √3 : 2
So if hypotenuse = 2 parts = 44 → 1 part = 22
Thus:
Short leg (y) = 22
Long leg (x) = 22√3
✔ Final for #11:
x = 22√3
y = 22
---
Problem 12:
Triangle:
Right angle at bottom right
Angle at top = 30° → so angle at bottom left = 60°
Side adjacent to 30° (vertical side) = 29√3
Hypotenuse = u
Base (horizontal) = v
Labeling:
Top vertex: 30°
Bottom right: 90°
Bottom left: 60°
So:
- Side opposite 30° = base = v → SHORT LEG
- Side opposite 60° = vertical side = 29√3 → LONG LEG
- Hypotenuse = u
In 30-60-90:
Short leg = x
Long leg = x√3
Hypotenuse = 2x
Here, long leg = 29√3 = x√3 → so x = 29
Then:
Short leg (v) = x = 29
Hypotenuse (u) = 2x = 58
✔ Final for #12:
u = 58
v = 29
---
Problem 13:
Triangle:
Right angle at bottom right
Angle at bottom left = 60° → so angle at top = 30°
Vertical side = 36 → this is opposite 60° → LONG LEG
Hypotenuse = a
Base = b → opposite 30° → SHORT LEG
So:
Long leg = 36 = x√3 → x = 36 / √3 = 12√3 (rationalize: 36/√3 * √3/√3 = 36√3 / 3 = 12√3)
Wait — better to keep as:
x = 36 / √3 = 12√3? Let’s compute numerically later, but algebraically:
Set short leg = x
Then long leg = x√3 = 36 → x = 36 / √3 = 12√3? Actually:
36 / √3 = (36 √3) / 3 = 12√3 → yes.
But actually, we want exact values.
So:
Short leg (b) = x = 36 / √3 = 12√3? Wait no:
If long leg = x√3 = 36 → then x = 36 / √3
Rationalize: (36 / √3) * (√3 / √3) = (36√3)/3 = 12√3
So short leg b = 12√3
Hypotenuse a = 2x = 2*(12√3) = 24√3
But wait — is that correct?
Alternative approach: since long leg = 36, and in ratio long leg = x√3, hypotenuse = 2x
So from long leg: x√3 = 36 → x = 36/√3 = 12√3
Then hypotenuse = 2x = 24√3
Short leg = x = 12√3
But let’s check: is short leg really 12√3? That seems large.
Wait — maybe I mixed up.
In triangle:
Angle at bottom left = 60° → so side opposite to it is the vertical side = 36 → that’s correct, long leg.
Side opposite 30° (top angle) is base = b → short leg.
Yes.
So:
b = short leg = x
36 = long leg = x√3 → x = 36/√3 = 12√3
a = hypotenuse = 2x = 24√3
But 12√3 is about 20.78, and 24√3 ≈ 41.57, and 36 is given — does Pythagoras hold?
Check: (12√3)^2 + 36^2 =? (24√3)^2
Left: (144 * 3) + 1296 = 432 + 1296 = 1728
Right: (576 * 3) = 1728 → yes, correct.
So:
a = 24√3
b = 12√3
But perhaps simplify or write differently? The problem might expect simplified radical form.
Alternatively, sometimes people write without radicals in denominator, but here it’s fine.
Wait — another way: since long leg = 36, and in 30-60-90, long leg = (√3/2) * hypotenuse? Let’s see.
Standard ratios:
If hypotenuse = H, then:
Short leg = H/2
Long leg = (H√3)/2
So here, long leg = 36 = (H√3)/2 → H = 36 * 2 / √3 = 72 / √3 = 24√3 → same as before.
Short leg = H/2 = 12√3
So yes.
✔ Final for #13:
a = 24√3
b = 12√3
---
Problem 14:
Triangle:
Right angle at bottom left
Angle at bottom right = 30° → so angle at top = 60°
Vertical side = 4√3 → this is opposite 30°? Let’s see.
Vertices:
Top: ?
Bottom left: 90°
Bottom right: 30° → so top angle = 60°
Sides:
Vertical side (from top to bottom left) = 4√3 → this is adjacent to 30°, opposite to 60° → so it’s the LONG LEG
Horizontal side (base) = y → opposite 30° → SHORT LEG
Hypotenuse = x
So:
Long leg = 4√3 = x√3 (if short leg = x) → so x = 4
Then:
Short leg (y) = x = 4
Hypotenuse (x) = 2x = 8
Wait — variable conflict: they used x for hypotenuse, but in ratio I used x for short leg.
Let me use different letter.
Let short leg = s
Then long leg = s√3 = 4√3 → so s = 4
Then hypotenuse = 2s = 8
So:
y = short leg = 4
x = hypotenuse = 8
✔ Final for #14:
x = 8
y = 4
---
Now, problems 15–18 are too blurry to read accurately. Since the user didn’t specify which ones to solve, and only 11–14 are clear, I’ll assume we’re to solve 11–14.
Final Answers:
11) x = 22√3, y = 22
12) u = 58, v = 29
13) a = 24√3, b = 12√3
14) x = 8, y = 4
But let me write them clearly per problem.
For problem 11:
x = 22√3
y = 22
Problem 12:
u = 58
v = 29
Problem 13:
a = 24√3
b = 12√3
Problem 14:
x = 8
y = 4
I think that’s all.
Final Answer:
11) x = 22√3, y = 22
12) u = 58, v = 29
13) a = 24√3, b = 12√3
14) x = 8, y = 4
Parent Tip: Review the logic above to help your child master the concept of 30 60 90 triangles worksheet.