Fraction word problems worksheet for students to practice adding and subtracting fractions in practical contexts.

Let's solve each problem step by step.

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Problem 1:

Melanie completed \(\frac{5}{6}\) of Wednesday's crossword and \(\frac{7}{10}\) of Thursday's crossword. In total, what fraction of these crosswords did Melanie finish?

Solution:
To find the total fraction of crosswords Melanie finished, we add the two fractions:
\[
\frac{5}{6} + \frac{7}{10}
\]

First, find a common denominator. The least common multiple (LCM) of 6 and 10 is 30. Convert each fraction:
\[
\frac{5}{6} = \frac{5 \times 5}{6 \times 5} = \frac{25}{30}
\]
\[
\frac{7}{10} = \frac{7 \times 3}{10 \times 3} = \frac{21}{30}
\]

Now add the fractions:
\[
\frac{25}{30} + \frac{21}{30} = \frac{25 + 21}{30} = \frac{46}{30}
\]

Simplify the fraction:
\[
\frac{46}{30} = \frac{23}{15}
\]

So, Melanie finished \(\frac{23}{15}\) of the crosswords in total.

Answer:
\[
\boxed{\frac{23}{15}}
\]

---

Problem 2:

Nancy planted \(\frac{5}{8}\) rows of beans and \(\frac{5}{12}\) rows of spinach in a garden. In total, how many rows of vegetables did Nancy plant?

Solution:
To find the total number of rows planted, add the two fractions:
\[
\frac{5}{8} + \frac{5}{12}
\]

Find a common denominator. The LCM of 8 and 12 is 24. Convert each fraction:
\[
\frac{5}{8} = \frac{5 \times 3}{8 \times 3} = \frac{15}{24}
\]
\[
\frac{5}{12} = \frac{5 \times 2}{12 \times 2} = \frac{10}{24}
\]

Now add the fractions:
\[
\frac{15}{24} + \frac{10}{24} = \frac{15 + 10}{24} = \frac{25}{24}
\]

So, Nancy planted \(\frac{25}{24}\) rows of vegetables in total.

Answer:
\[
\boxed{\frac{25}{24}}
\]

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Problem 3:

Fred has to read 2 books for school. Fred read \(\frac{5}{12}\) of the first book on Friday and \(\frac{1}{12}\) of the second book on Thursday. What total fraction of these two books has Fred read?

Solution:
To find the total fraction of the books Fred read, add the two fractions:
\[
\frac{5}{12} + \frac{1}{12}
\]

Since the denominators are the same, simply add the numerators:
\[
\frac{5}{12} + \frac{1}{12} = \frac{5 + 1}{12} = \frac{6}{12}
\]

Simplify the fraction:
\[
\frac{6}{12} = \frac{1}{2}
\]

So, Fred has read \(\frac{1}{2}\) of the total books.

Answer:
\[
\boxed{\frac{1}{2}}
\]

---

Problem 4:

Fred picked \(\frac{4}{9}\) of a bucket of lemons, and Mary picked \(\frac{4}{9}\) of a bucket of lemons. How many buckets total did they pick?

Solution:
To find the total number of buckets picked, add the two fractions:
\[
\frac{4}{9} + \frac{4}{9}
\]

Since the denominators are the same, simply add the numerators:
\[
\frac{4}{9} + \frac{4}{9} = \frac{4 + 4}{9} = \frac{8}{9}
\]

So, they picked \(\frac{8}{9}\) of a bucket in total.

Answer:
\[
\boxed{\frac{8}{9}}
\]

---

Problem 5:

Tom did \(\frac{10}{11}\) of a load of laundry on Monday and \(\frac{3}{11}\) of a load of laundry on Saturday. What fraction of laundry did Tom do in total?

Solution:
To find the total fraction of laundry Tom did, add the two fractions:
\[
\frac{10}{11} + \frac{3}{11}
\]

Since the denominators are the same, simply add the numerators:
\[
\frac{10}{11} + \frac{3}{11} = \frac{10 + 3}{11} = \frac{13}{11}
\]

So, Tom did \(\frac{13}{11}\) of a load of laundry in total.

Answer:
\[
\boxed{\frac{13}{11}}
\]

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Problem 6:

Alyssa has \(\frac{3}{4}\) of last week's allowance and \(\frac{7}{9}\) of this week's allowance. How many weeks of allowance in total does Alyssa have left?

Solution:
To find the total allowance Alyssa has, add the two fractions:
\[
\frac{3}{4} + \frac{7}{9}
\]

Find a common denominator. The LCM of 4 and 9 is 36. Convert each fraction:
\[
\frac{3}{4} = \frac{3 \times 9}{4 \times 9} = \frac{27}{36}
\]
\[
\frac{7}{9} = \frac{7 \times 4}{9 \times 4} = \frac{28}{36}
\]

Now add the fractions:
\[
\frac{27}{36} + \frac{28}{36} = \frac{27 + 28}{36} = \frac{55}{36}
\]

So, Alyssa has \(\frac{55}{36}\) weeks of allowance in total.

Answer:
\[
\boxed{\frac{55}{36}}
\]

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Problem 7:

Mike had to complete chores. Mike has completed \(\frac{11}{12}\) of the house chores and \(\frac{9}{11}\) of the yard chores. What fraction of all the chores has Mike done?

Solution:
To find the total fraction of chores Mike has done, add the two fractions:
\[
\frac{11}{12} + \frac{9}{11}
\]

Find a common denominator. The LCM of 12 and 11 is 132. Convert each fraction:
\[
\frac{11}{12} = \frac{11 \times 11}{12 \times 11} = \frac{121}{132}
\]
\[
\frac{9}{11} = \frac{9 \times 12}{11 \times 12} = \frac{108}{132}
\]

Now add the fractions:
\[
\frac{121}{132} + \frac{108}{132} = \frac{121 + 108}{132} = \frac{229}{132}
\]

So, Mike has done \(\frac{229}{132}\) of all the chores.

Answer:
\[
\boxed{\frac{229}{132}}
\]

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Problem 8:

Keith ate \(\frac{1}{2}\) of a pie, while Mary ate \(\frac{1}{2}\) of a pie. In total, how much pie did these two eat?

Solution:
To find the total amount of pie eaten, add the two fractions:
\[
\frac{1}{2} + \frac{1}{2}
\]

Since the denominators are the same, simply add the numerators:
\[
\frac{1}{2} + \frac{1}{2} = \frac{1 + 1}{2} = \frac{2}{2} = 1
\]

So, Keith and Mary ate 1 whole pie in total.

Answer:
\[
\boxed{1}
\]

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Problem 9:

Tom drank \(\frac{8}{9}\) of a cup of milk at breakfast and \(\frac{2}{5}\) of a cup of milk at dinner. In total, how many cups of milk did Tom drink today?

Solution:
To find the total amount of milk Tom drank, add the two fractions:
\[
\frac{8}{9} + \frac{2}{5}
\]

Find a common denominator. The LCM of 9 and 5 is 45. Convert each fraction:
\[
\frac{8}{9} = \frac{8 \times 5}{9 \times 5} = \frac{40}{45}
\]
\[
\frac{2}{5} = \frac{2 \times 9}{5 \times 9} = \frac{18}{45}
\]

Now add the fractions:
\[
\frac{40}{45} + \frac{18}{45} = \frac{40 + 18}{45} = \frac{58}{45}
\]

So, Tom drank \(\frac{58}{45}\) cups of milk in total.

Answer:
\[
\boxed{\frac{58}{45}}
\]

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Problem 10:

A recipe called for \(\frac{11}{12}\) cup of chopped tomatoes and \(\frac{7}{12}\) cup of diced tomatoes. In total, how many cups of tomatoes did the recipe call for?

Solution:
To find the total amount of tomatoes, add the two fractions:
\[
\frac{11}{12} + \frac{7}{12}
\]

Since the denominators are the same, simply add the numerators:
\[
\frac{11}{12} + \frac{7}{12} = \frac{11 + 7}{12} = \frac{18}{12}
\]

Simplify the fraction:
\[
\frac{18}{12} = \frac{3}{2}
\]

So, the recipe called for \(\frac{3}{2}\) cups of tomatoes in total.

Answer:
\[
\boxed{\frac{3}{2}}
\]

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Final Answers:

1. \(\boxed{\frac{23}{15}}\)
2. \(\boxed{\frac{25}{24}}\)
3. \(\boxed{\frac{1}{2}}\)
4. \(\boxed{\frac{8}{9}}\)
5. \(\boxed{\frac{13}{11}}\)
6. \(\boxed{\frac{55}{36}}\)
7. \(\boxed{\frac{229}{132}}\)
8. \(\boxed{1}\)
9. \(\boxed{\frac{58}{45}}\)
10. \(\boxed{\frac{3}{2}}\)