Activity 7 Balancing Equations Worksheet 1 | StudyX - Free Printable

Final Answer:
1) 1 Na₃PO₄ + 3 KOH → 3 NaOH + 1 K₃PO₄
2) 1 MgF₂ + 1 Li₂CO₃ → 1 MgCO₃ + 2 LiF
3) 4 P₄ + 3 O₂ → 2 P₂O₃
4) 2 RbNO₃ + 1 BeF₂ → 1 Be(NO₃)₂ + 2 RbF
5) 2 AgNO₃ + 1 Cu → 1 Cu(NO₃)₂ + 2 Ag
6) 1 CF₄ + 2 Br₂ → 1 CBr₄ + 2 F₂
7) 2 HCN + 1 CuSO₄ → 1 H₂SO₄ + 1 Cu(CN)₂
8) 1 GaF₃ + 3 Cs → 3 CsF + 1 Ga
9) 1 BaS + 1 PtF₂ → 1 BaF₂ + 1 PtS
10) 1 N₂ + 3 H₂ → 2 NH₃
11) 2 NaE + 1 Br₂ → 2 NaBr + 1 E₂ *(Note: “E” is likely a placeholder; if it’s meant to be a halogen like Cl, then 2 NaCl + Br₂ → 2 NaBr + Cl₂ — but as written, assume E is monatomic)*
However, since "NaE" and "E" are nonstandard, and given context of other problems (all real elements), it's likely a typo. More plausibly: 2 Na + Br₂ → 2 NaBr — but the problem says *NaE*, so unless clarified, we treat E as a generic monatomic element → 2 NaE + Br₂ → 2 NaBr + E₂.
But standard practice in such worksheets: if “E” appears, it’s often a mistake. Given all others are real compounds, and no element “E”, safest assumption: It should be NaI or similar, but per strict instruction, balance as written:
→ 2 NaE + 1 Br₂ → 2 NaBr + 1 E₂

Yet looking at pattern, problem (11) is likely intended to be: 2 Na + Br₂ → 2 NaBr, but it says *NaE*. Since we must answer based on given, and E is unknown, but balancing requires atoms equal:
Left: Na=1, E=1, Br=2
Right: Na=1, Br=1, F=2? No — product is NaBr and F₂? No, it says NaBr + F₂? Wait, original says:
“__ NaE + __ Br₂ → __ NaBr + __ F₂” — oh! It says F₂, not E₂. So product is NaBr and F₂. That means E must be F. So NaE = NaF. Then:
1 NaF + ? Br₂ → ? NaBr + ? F₂
Balance:
Na: 1 → 1
F: 1 → 2 on right (in F₂), so need 2 NaF
Then: 2 NaF + Br₂ → 2 NaBr + F₂ ✔
So answer: 2 NaF + 1 Br₂ → 2 NaBr + 1 F₂

Thus:
11) 2 NaF + 1 Br₂ → 2 NaBr + 1 F₂

12) 1 Pb(OH)₂ + 2 HCl → 2 H₂O + 1 PbCl₂
13) 2 AlBr₃ + 3 K₂SO₄ → 6 KBr + 1 Al₂(SO₄)₃
14) 1 CH₄ + 2 O₂ → 1 CO₂ + 2 H₂O
15) 2 Na₃PO₄ + 3 CaCl₂ → 6 NaCl + 1 Ca₃(PO₄)₂
16) 2 K + 1 Cl₂ → 2 KCl
17) 2 Al + 6 HCl → 3 H₂ + 2 AlCl₃
18) 1 N₂ + 3 F₂ → 2 NF₃
19) 1 SO₂ + 1 Li₂Se → 1 SSe₂ + 1 Li₂O
Wait: Right side is SSe₂ and Li₂O. Check atoms:
Left: S=1, O=2, Li=2, Se=1
Right: S=1, Se=2, Li=2, O=1 → not balanced.
Try: 2 SO₂ + 2 Li₂Se → 2 SSe₂ + 2 Li₂O?
Left: S=2, O=4, Li=4, Se=2
Right: S=2, Se=4, Li=4, O=2 → Se and O mismatch.
Alternative: Maybe product is S₂Se₂? But it says SSe₂.
Standard reaction: SO₂ + 2 Li₂Se → Li₂S + Li₂SeO₂? Not matching.
Given worksheet likely expects simple atom balance:
Assume formula is correct: __ SO₂ + __ Li₂Se → __ SSe₂ + __ Li₂O
Let coefficients be a, b, c, d:
S: a = c
O: 2a = d
Li: 2b = 2d → b = d
Se: b = 2c
From b = d and d = 2a → b = 2a
From Se: b = 2c, and c = a → b = 2a → consistent.
So let a = 1 → c = 1, d = 2, b = 2
Check:
1 SO₂ + 2 Li₂Se → 1 SSe₂ + 2 Li₂O
Atoms:
Left: S=1, O=2, Li=4, Se=2
Right: S=1, Se=2, Li=4, O=2 ✔
So: 1 SO₂ + 2 Li₂Se → 1 SSe₂ + 2 Li₂O

20) 2 NH₃ + 1 H₂SO₄ → 1 (NH₄)₂SO₄

Now compile final answers cleanly:

1) 1, 3, 3, 1
2) 1, 1, 1, 2
3) 4, 3, 2
4) 2, 1, 1, 2
5) 2, 1, 1, 2
6) 1, 2, 1, 2
7) 2, 1, 1, 1
8) 1, 3, 3, 1
9) 1, 1, 1, 1
10) 1, 3, 2
11) 2, 1, 2, 1
12) 1, 2, 2, 1
13) 2, 3, 6, 1
14) 1, 2, 1, 2
15) 2, 3, 6, 1
16) 2, 1, 2
17) 2, 6, 3, 2
18) 1, 3, 2
19) 1, 2, 1, 2
20) 2, 1, 1