Multiplication, money and division - Studyladder Interactive ... - Free Printable

Let’s solve each section of the worksheet step by step.

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Multiplication and Money Section

1. 65 × 10 = ?
→ Multiply 65 by 10: just add a zero at the end.
→ 650

2. 86 × 100 = ?
→ Add two zeros to 86.
→ 8,600

3. 78 × 1000 = ?
→ Add three zeros to 78.
→ 78,000

4. 174 × 10 = ?
→ Add one zero to 174.
→ 1,740

5. 950 × 100 = ?
→ Add two zeros to 950.
→ 95,000

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Money Addition Problems

6. $45.86 + $95.85
→ Line up decimals:
```
45.86
+ 95.85
-------
141.71
```
→ $141.71

7. $456.95 + $847.79
→ Line up decimals:
```
456.95
+ 847.79
--------
1304.74
```
→ $1,304.74

8. $36.26 × 65
→ First ignore decimal: 3626 × 65
- 3626 × 60 = 217,560
- 3626 × 5 = 18,130
- Total = 217,560 + 18,130 = 235,690
→ Now put back 2 decimal places (since $36.26 has 2 decimals)
→ $2,356.90

9. $99.75 × 36
→ Ignore decimal: 9975 × 36
- 9975 × 30 = 299,250
- 9975 × 6 = 59,850
- Total = 299,250 + 59,850 = 359,100
→ Put back 2 decimal places → $3,591.00

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Missing Factor Problems

10. 65 × 5 + ___ = 408
→ 65 × 5 = 325
→ 408 – 325 = 83

11. 76 × 3 + ___ = 282
→ 76 × 3 = 228
→ 282 – 228 = 54

12. 98 × 4 + ___ = 460
→ 98 × 4 = 392
→ 460 – 392 = 68

13. 68 × 7 + ___ = 510
→ 68 × 7 = 476
→ 510 – 476 = 34

14. 38 × 9 + ___ = 441
→ 38 × 9 = 342
→ 441 – 342 = 99

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Division Section — Identify the dividend

In division like “8 ) 28 r2”, the number inside (28) is the dividend.

So:

- 8 ) 28 r2 → dividend = 28
- 6 ) 36 r4 → dividend = 36
- 6 ) 165 → dividend = 165
- 8 ) 679 → dividend = 679
- 5 ) 486 → dividend = 486
- 7 ) 474 → dividend = 474

*(Note: The instruction says “Identify the dividend” — so we’re just writing the number being divided.)*

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Money Section — Circle notes/coins for least number possible

We need to make these amounts using fewest bills/coins. Assume standard U.S. currency:

Bills: $100, $50, $20, $10, $5, $1
Coins: quarter ($0.25), dime ($0.10), nickel ($0.05), penny ($0.01)

But since images are shown (which we can’t see), we’ll assume typical combinations.

Actually — let’s calculate how much total money is needed first? Wait — no, it says “Circle the notes and coins needed to pay for these items.” So per item.

But without seeing the actual bill/coin images, we can only compute the amount. However, since this is a worksheet with pictures, and user didn’t provide them, perhaps we skip circling and just note the amounts? But the problem says “use the least number as possible”.

Wait — maybe the images show specific bills/coins available? Since we don’t have visuals, I’ll assume standard denominations and give minimal combination for each price.

But actually — looking again: the worksheet shows pictures of bills and coins below. Since we can't see them, but in real context, student would circle from given options. For accuracy, I'll compute the minimal set assuming standard U.S. currency.

However, since the task is to *circle* from provided images, and we don’t have them, perhaps this part cannot be fully answered visually. But let’s try to deduce based on common worksheets.

Alternatively — maybe the question expects us to write which bills/coins to use? Let’s do that minimally.

Shopping Tie: $12.80

Minimal:
→ One $10 bill
→ One $2 bill? Or better: one $10, one $1, one $1? No — wait, $12.80

Better:
→ One $10
→ Two $1 bills → $12
→ Three quarters = $0.75 → too much
→ Two quarters = $0.50 → still need $0.30
→ One quarter + one nickel = $0.30 → total coins: 3 coins
Total: 1 bill ($10) + 2 bills ($1 each) + 3 coins = 6 pieces

But if $2 bills allowed? Not common. Better:

→ One $10
→ One $2? If not, then two $1s
→ Then $0.80: three quarters = $0.75, plus one nickel = $0.80 → 4 coins? Wait:

$0.80 = 3 quarters ($0.75) + 1 nickel ($0.05) → yes, 4 coins? No: 3+1=4 coins? Actually 3 quarters and 1 nickel is 4 coins for $0.80? That’s wrong.

Wait: 3 quarters = $0.75, need $0.05 more → 1 nickel → total 4 coins for $0.80? That’s inefficient.

Actually: $0.80 = 8 dimes → 8 coins → worse.

Or: 3 quarters + 1 nickel = 4 coins → same.

But best: 3 quarters + 1 nickel = 4 coins? No — 3 quarters is $0.75, plus 1 nickel is $0.80 — that’s correct, 4 coins.

But actually — 8 dimes is 8 coins — worse.

Is there a better way? What about 2 quarters ($0.50) + 3 dimes ($0.30) = $0.80 → 5 coins — worse.

So minimal coins for $0.80 is 4: 3Q + 1N.

But wait — what if we use a half-dollar? Uncommon.

Assume standard: quarters, dimes, nickels, pennies.

Actually — $0.80 can be made with 3 quarters and 1 nickel — 4 coins.

But let's check: 3×0.25 = 0.75, +0.05 = 0.80 — yes.

So for $12.80:

- Bills: $10 + $1 + $1 = 3 bills
- Coins: 3 quarters + 1 nickel = 4 coins
Total: 7 pieces

But if we use a $5 bill? No, overpay.

Wait — another way: $10 + $2? If $2 bill exists — some worksheets include it.

To minimize, perhaps:

If $2 bill is available: $10 + $2 = $12, then $0.80 as above → 2 bills + 4 coins = 6 pieces.

But since we don’t know, and to be safe, let’s assume no $2 bills.

Actually — in many such problems, they expect you to use largest denominations first.

For $12.80:

- Use one $10 bill → remaining $2.80
- Use two $1 bills → remaining $0.80
- For $0.80: use 3 quarters ($0.75) and 1 nickel ($0.05) → total coins: 4

Total items: 1 (ten) + 2 (ones) + 4 (coins) = 7

But perhaps they have a $5 bill? No, $5 is less than $10.

Another idea: use one $10, one $2 (if allowed), then $0.80 as above — 2 bills + 4 coins = 6.

Since the worksheet likely includes $2 bills (as sometimes shown), I’ll assume that for minimal count.

But to be precise, let's look at other prices.

Perhaps for consistency, I'll calculate all with standard minimal sets.

But this is getting messy. Maybe the "circle" part is visual, and since we can't see, we should focus on calculable parts.

Wait — the problem says "Circle the notes and coins needed" — implying from given images. Since we don't have images, perhaps this section is not answerable numerically. But let's try to infer from common versions.

Upon second thought, in many such worksheets, the images show specific bills and coins, and students circle them. Without visuals, we can't specify which to circle. So perhaps for this response, we skip the circling and move to problem solving, or state the amounts.

But the user wants accurate solution. Let's proceed to Problem Solving, which is clear.

---

Problem Solving

Jimmy bought:
- 2 kg salami at $4.40/kg → 2 × 4.40 = $8.80
- 3 kg bananas at $3.20/kg → 3 × 3.20 = $9.60

Total cost = 8.80 + 9.60 = $18.40

He paid with $50.00

Change = 50.00 - 18.40 = $31.60

Let me verify:

2 × 4.40:
4.40 × 2 = 8.80 ✓

3 × 3.20:
3.20 × 3 = 9.60 ✓

Sum: 8.80 + 9.60
8 + 9 = 17, 0.80 + 0.60 = 1.40 → total 18.40 ✓

50.00 - 18.40:
50.00 - 18.00 = 32.00, minus 0.40 = 31.60 ✓

So change is $31.60

---

Now, back to Money section — since we must provide answers, and assuming standard U.S. currency with minimal pieces:

Tie: $12.80
- Bills: $10, $1, $1 → 3 bills
- Coins: 3 quarters, 1 nickel → 4 coins
Total: 7 pieces

But if $2 bill is available: $10, $2 → 2 bills; coins same → 6 pieces. I think many worksheets include $2, so I'll go with that for minimal.

Similarly:

Shirt: $26.35
- Bills: $20, $5, $1 → 3 bills (total $26)
- Coins: 1 quarter, 1 dime → $0.35 → 2 coins
Total: 5 pieces

Shoes: $45.60
- Bills: $20, $20, $5 → 3 bills ($45)
- Coins: 2 quarters, 1 dime → $0.60 → 3 coins? 2Q=$0.50, 1D=$0.10 → yes, 3 coins
Total: 6 pieces

Jacket: $67.90
- Bills: $50, $10, $5, $2 → 4 bills ($67) [assuming $2]
- Coins: 3 quarters, 1 nickel, 1 dime? $0.90 = 3Q ($0.75) + 1D ($0.10) + 1N ($0.05) = $0.90 → 5 coins? Too many.

Better: $0.90 = 3 quarters + 1 dime + 1 nickel? 3*0.25=0.75, +0.10=0.85, +0.05=0.90 — yes, 5 coins.

But minimal: 9 dimes = 9 coins — worse.

Or 3 quarters + 15 pennies — worse.

Actually, 3 quarters + 1 dime + 1 nickel is 5 coins, but is there better?

What about 2 half-dollars? Not standard.

Standard minimal for $0.90: 3 quarters, 1 dime, 1 nickel — 5 coins.

But wait — 3 quarters = $0.75, need $0.15 more → 1 dime + 1 nickel = $0.15 — yes.

So 5 coins.

Bills: $50 + $10 + $5 + $2 = $67 — 4 bills

Total: 9 pieces

But if no $2 bill: $50 + $10 + $5 + $1 + $1 = $67 — 5 bills, plus 5 coins = 10 pieces.

Again, assuming $2 bill for minimal.

To resolve, perhaps in the worksheet, the images include $2 bills, so we'll assume that.

But for the sake of this response, since the Problem Solving is clear, and others are multiplication/division, I'll provide numerical answers where possible.

For the "circle" part, since it's visual, and we can't circle, perhaps omit or describe minimally.

But the user said "solve the problem accurately", so for Money section, I'll list the minimal combination assuming standard denominations including $2 bills.

Final decision:

Tie $12.80: $10, $2, 3Q, 1N → 2 bills, 4 coins

Shirt $26.35: $20, $5, $1, 1Q, 1D → 3 bills, 2 coins

Shoes $45.60: $20, $20, $5, 2Q, 1D → 3 bills, 3 coins

Jacket $67.90: $50, $10, $5, $2, 3Q, 1D, 1N → 4 bills, 5 coins

But this is speculative.

Perhaps the worksheet expects only the amounts, but the instruction is to circle.

Given the constraints, I'll focus on the calculable parts and for Money section, state the total cost or something, but that's not what's asked.

Another approach: since the user may have the image, and we're to solve, perhaps for Money section, we can say "student should circle the following" but without images, it's hard.

I think for accuracy, I'll provide the answers for all sections except the circling, and for circling, note that it requires visual selection.

But let's look back at the worksheet description: "Circle the notes and coins needed to pay for these items. (use the least number as possible)"

And there are images of bills and coins below. Since we don't have them, perhaps in the context, the student is to choose from those images.

For the purpose of this response, I'll assume that the minimal combinations are as above, and move on.

But to keep it clean, let's complete the Final Answer with all numerical answers, and for the circling, since it's not numerical, perhaps omit or handle separately.

The user might expect the Problem Solving answer primarily, but the whole worksheet.

Let's compile all answers:

Multiplication:
65×10 = 650
86×100 = 8600
78×1000 = 78000
174×10 = 1740
950×100 = 95000

Money addition:
45.86 + 95.85 = 141.71
456.95 + 847.79 = 1304.74
36.26 × 65 = 2356.90
99.75 × 36 = 3591.00

Missing factors:
65×5 + x = 408 → x=83
76×3 + x = 282 → x=54
98×4 + x = 460 → x=68
68×7 + x = 510 → x=34
38×9 + x = 441 → x=99

Division dividends:
28, 36, 165, 679, 486, 474

Problem Solving:
Change = $31.60

For Money section, since it's circling, and we can't do that, perhaps in Final Answer, we list the amounts or skip.

But the user said "solve the problem accurately", so for completeness, I'll include the minimal coin/bill combinations as text.

Final Answer will have all.

Let's write Final Answer with all parts.

First, verify all calculations once more.

Multiplication:
65*10=650 ✓
86*100=8600 ✓
78*1000=78000 ✓
174*10=1740 ✓
950*100=95000 ✓

Addition:
45.86 + 95.85:
45+95=140, 0.86+0.85=1.71, total 141.71 ✓
456.95 + 847.79:
456+847=1303, 0.95+0.79=1.74, total 1304.74 ✓

Multiplication with decimals:
36.26 * 65:
36.26 * 60 = 2175.6
36.26 * 5 = 181.3
Sum: 2175.6 + 181.3 = 2356.9 → $2,356.90 ✓

99.75 * 36:
100*36 = 3600, minus 0.25*36=9, so 3600-9=3591 → $3,591.00 ✓

Missing factors:
65*5=325, 408-325=83 ✓
76*3=228, 282-228=54 ✓
98*4=392, 460-392=68 ✓
68*7=476, 510-476=34 ✓
38*9=342, 441-342=99 ✓

Division dividends: straightforward, the number inside the division symbol.

Problem Solving:
Salami: 2 * 4.40 = 8.80
Bananas: 3 * 3.20 = 9.60
Total: 8.80 + 9.60 = 18.40
Change: 50.00 - 18.40 = 31.60 ✓

For Money section, I'll provide the minimal combination as per standard assumption.

Assume available denominations: $50, $20, $10, $5, $2, $1 bills; quarters, dimes, nickels, pennies.

Tie $12.80:
- $10 bill
- $2 bill
- 3 quarters ($0.75)
- 1 nickel ($0.05)
Total: 2 bills, 4 coins

Shirt $26.35:
- $20 bill
- $5 bill
- $1 bill
- 1 quarter ($0.25)
- 1 dime ($0.10)
Total: 3 bills, 2 coins

Shoes $45.60:
- $20 bill
- $20 bill
- $5 bill
- 2 quarters ($0.50)
- 1 dime ($0.10)
Total: 3 bills, 3 coins

Jacket $67.90:
- $50 bill
- $10 bill
- $5 bill
- $2 bill
- 3 quarters ($0.75)
- 1 dime ($0.10)
- 1 nickel ($0.05)
Total: 4 bills, 5 coins

This uses the least number of pieces for each.

Now, for Final Answer, I'll list all.

Since the response format requires Final Answer after reasoning, and reasoning is done, here is:

Final Answer:
Multiplication:
65 × 10 = 650
86 × 100 = 8,600
78 × 1000 = 78,000
174 × 10 = 1,740
950 × 100 = 95,000

Money Addition:
$45.86 + $95.85 = $141.71
$456.95 + $847.79 = $1,304.74
$36.26 × 65 = $2,356.90
$99.75 × 36 = $3,591.00

Missing Factors:
65 × 5 + 83 = 408
76 × 3 + 54 = 282
98 × 4 + 68 = 460
68 × 7 + 34 = 510
38 × 9 + 99 = 441

Division Dividends:
28, 36, 165, 679, 486, 474

Money (minimal pieces):
Tie $12.80: $10, $2, 3 quarters, 1 nickel
Shirt $26.35: $20, $5, $1, 1 quarter, 1 dime
Shoes $45.60: $20, $20, $5, 2 quarters, 1 dime
Jacket $67.90: $50, $10, $5, $2, 3 quarters, 1 dime, 1 nickel

Problem Solving:
Change = $31.60