Let's solve each algebraic expression step by step using the given values of the variables.
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① $\frac{w}{2} - 5$ at $w = 12$
$$
\frac{12}{2} - 5 = 6 - 5 = \boxed{1}
$$
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② $\frac{c^2}{4} + 2$ at $c = 2$
$$
\frac{2^2}{4} + 2 = \frac{4}{4} + 2 = 1 + 2 = \boxed{3}
$$
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③ $\frac{n}{2} + 6$ at $n = 8$
$$
\frac{8}{2} + 6 = 4 + 6 = \boxed{10}
$$
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④ $3 - \frac{p^2}{2}$ at $p = 5$
$$
3 - \frac{5^2}{2} = 3 - \frac{25}{2} = 3 - 12.5 = \boxed{-9.5}
$$
Or as a fraction:
$$
3 - \frac{25}{2} = \frac{6}{2} - \frac{25}{2} = \frac{-19}{2} = \boxed{-\frac{19}{2}}
$$
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⑤ $\frac{q}{3} + 4$ at $q = 3$
$$
\frac{3}{3} + 4 = 1 + 4 = \boxed{5}
$$
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⑥ $(x + 4)^2$ at $x = -4$
$$
(-4 + 4)^2 = (0)^2 = \boxed{0}
$$
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⑦ $8(l - 6)$ at $l = -1$
$$
8(-1 - 6) = 8(-7) = \boxed{-56}
$$
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⑧ $\frac{5v + 3}{2}$ at $v = -3$
$$
\frac{5(-3) + 3}{2} = \frac{-15 + 3}{2} = \frac{-12}{2} = \boxed{-6}
$$
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⑨ $(q - 5)^3$ at $q = 2$
$$
(2 - 5)^3 = (-3)^3 = -27 = \boxed{-27}
$$
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⑩ $\frac{d}{2} - 1$ at $d = 16$
$$
\frac{16}{2} - 1 = 8 - 1 = \boxed{7}
$$
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✔ Final Answers:
1. $1$
2. $3$
3. $10$
4. $-9.5$ or $-\frac{19}{2}$
5. $5$
6. $0$
7. $-56$
8. $-6$
9. $-27$
10. $7$
Let me know if you'd like these written in a formatted worksheet style!
Parent Tip: Review the logic above to help your child master the concept of evaluating algebraic expressions worksheet.
