3 Digit Subtraction with Regrouping - Amy Lemons - Free Printable

Problem Overview:

The task involves solving a series of triple-digit subtraction problems. The worksheet is divided into two sections, each containing multiple subtraction problems. Some problems require regrouping (borrowing) in the ones place, while others may require regrouping in both the tens and ones places.

Solution Approach:

We will solve each subtraction problem step by step, ensuring to handle regrouping correctly where necessary. Let's go through each problem systematically.

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#### Section 1: Triple-Digit Subtraction Problems

1. Problem A: \( 683 - 349 \)
- Subtract digit by digit:
- Ones place: \( 3 - 9 \). Borrow 1 from the tens place (8 becomes 7), so \( 13 - 9 = 4 \).
- Tens place: \( 7 - 4 = 3 \).
- Hundreds place: \( 6 - 3 = 3 \).
- Result: \( 334 \).

2. Problem B: \( 705 - 398 \)
- Subtract digit by digit:
- Ones place: \( 5 - 8 \). Borrow 1 from the tens place (0 becomes 9), so \( 15 - 8 = 7 \).
- Tens place: \( 9 - 9 = 0 \).
- Hundreds place: \( 7 - 3 = 4 \).
- Result: \( 307 \).

3. Problem C: \( 842 - 125 \)
- Subtract digit by digit:
- Ones place: \( 2 - 5 \). Borrow 1 from the tens place (4 becomes 3), so \( 12 - 5 = 7 \).
- Tens place: \( 3 - 2 = 1 \).
- Hundreds place: \( 8 - 1 = 7 \).
- Result: \( 717 \).

4. Problem D: \( 483 - 205 \)
- Subtract digit by digit:
- Ones place: \( 3 - 5 \). Borrow 1 from the tens place (8 becomes 7), so \( 13 - 5 = 8 \).
- Tens place: \( 7 - 0 = 7 \).
- Hundreds place: \( 4 - 2 = 2 \).
- Result: \( 278 \).

5. Problem E: \( 398 - 129 \)
- Subtract digit by digit:
- Ones place: \( 8 - 9 \). Borrow 1 from the tens place (9 becomes 8), so \( 18 - 9 = 9 \).
- Tens place: \( 8 - 2 = 6 \).
- Hundreds place: \( 3 - 1 = 2 \).
- Result: \( 269 \).

6. Problem F: \( 98 - 52 \)
- Subtract digit by digit:
- Ones place: \( 8 - 2 = 6 \).
- Tens place: \( 9 - 5 = 4 \).
- Result: \( 46 \).

7. Problem G: \( 743 - 399 \)
- Subtract digit by digit:
- Ones place: \( 3 - 9 \). Borrow 1 from the tens place (4 becomes 3), so \( 13 - 9 = 4 \).
- Tens place: \( 3 - 9 \). Borrow 1 from the hundreds place (7 becomes 6), so \( 13 - 9 = 4 \).
- Hundreds place: \( 6 - 3 = 3 \).
- Result: \( 344 \).

8. Problem H: \( 830 - 263 \)
- Subtract digit by digit:
- Ones place: \( 0 - 3 \). Borrow 1 from the tens place (3 becomes 2), so \( 10 - 3 = 7 \).
- Tens place: \( 2 - 6 \). Borrow 1 from the hundreds place (8 becomes 7), so \( 12 - 6 = 6 \).
- Hundreds place: \( 7 - 2 = 5 \).
- Result: \( 567 \).

9. Problem I: \( 542 - 198 \)
- Subtract digit by digit:
- Ones place: \( 2 - 8 \). Borrow 1 from the tens place (4 becomes 3), so \( 12 - 8 = 4 \).
- Tens place: \( 3 - 9 \). Borrow 1 from the hundreds place (5 becomes 4), so \( 13 - 9 = 4 \).
- Hundreds place: \( 4 - 1 = 3 \).
- Result: \( 344 \).

10. Problem J: \( 733 - 456 \)
- Subtract digit by digit:
- Ones place: \( 3 - 6 \). Borrow 1 from the tens place (3 becomes 2), so \( 13 - 6 = 7 \).
- Tens place: \( 2 - 5 \). Borrow 1 from the hundreds place (7 becomes 6), so \( 12 - 5 = 7 \).
- Hundreds place: \( 6 - 4 = 2 \).
- Result: \( 277 \).

11. Problem K: \( 521 - 145 \)
- Subtract digit by digit:
- Ones place: \( 1 - 5 \). Borrow 1 from the tens place (2 becomes 1), so \( 11 - 5 = 6 \).
- Tens place: \( 1 - 4 \). Borrow 1 from the hundreds place (5 becomes 4), so \( 11 - 4 = 7 \).
- Hundreds place: \( 4 - 1 = 3 \).
- Result: \( 376 \).

12. Problem L: \( 702 - 367 \)
- Subtract digit by digit:
- Ones place: \( 2 - 7 \). Borrow 1 from the tens place (0 becomes 9), so \( 12 - 7 = 5 \).
- Tens place: \( 9 - 6 = 3 \).
- Hundreds place: \( 7 - 3 = 4 \).
- Result: \( 335 \).

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Final Answers:

\[
\boxed{
\begin{array}{ll}
A. 334 & F. 46 \\
B. 307 & G. 344 \\
C. 717 & H. 567 \\
D. 278 & I. 344 \\
E. 269 & J. 277 \\
K. 376 & L. 335 \\
\end{array}
}
\]