Ionic Bonding Worksheet with Electron Transfer Diagrams and Ion Formation Examples.

Problem Description:

The task involves analyzing ionic bonding reactions between pairs of elements. For each reaction, you need to:
1. Draw atomic diagrams showing the electron configurations of the atoms involved.
2. Indicate the transfer of electrons during the chemical reaction.
3. Show the resulting ions formed in the product.
4. Fill in a table summarizing the information for each reaction.

The provided worksheet includes five reactions, and the solution involves completing the table and drawing the necessary diagrams.

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Solution:

#### Reaction 1: Li + Cl → LiCl
- Atoms: Lithium (Li) and Chlorine (Cl)
- Valence Electrons:
- Li: 1 valence electron
- Cl: 7 valence electrons
- Electron Transfer:
- Li donates its 1 valence electron to Cl.
- Cl accepts 1 electron from Li.
- Ions Formed:
- Li⁺ (Lithium ion with a +1 charge)
- Cl⁻ (Chloride ion with a -1 charge)

Table Entry:
| Atoms | Valence electrons | Electron transfer from/to each atom | Ions formed in the product |
|-------|-------------------|--------------------------------------|----------------------------|
| Li | 1 | 1 to Cl | Li⁺ |
| Cl | 7 | 1 from Li | Cl⁻ |

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#### Reaction 2: Ca + O → CaO
- Atoms: Calcium (Ca) and Oxygen (O)
- Valence Electrons:
- Ca: 2 valence electrons
- O: 6 valence electrons
- Electron Transfer:
- Ca donates its 2 valence electrons to O.
- O accepts 2 electrons from Ca.
- Ions Formed:
- Ca²⁺ (Calcium ion with a +2 charge)
- O²⁻ (Oxide ion with a -2 charge)

Table Entry:
| Atoms | Valence electrons | Electron transfer from/to each atom | Ions formed in the product |
|-------|-------------------|--------------------------------------|----------------------------|
| Ca | 2 | 2 to O | Ca²⁺ |
| O | 6 | 2 from Ca | O²⁻ |

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#### Reaction 3: Be + F → BeF₂
- Atoms: Beryllium (Be) and Fluorine (F)
- Valence Electrons:
- Be: 2 valence electrons
- F: 7 valence electrons
- Electron Transfer:
- Be donates its 2 valence electrons, one to each F atom.
- Each F atom accepts 1 electron from Be.
- Ions Formed:
- Be²⁺ (Beryllium ion with a +2 charge)
- F⁻ (Fluoride ion with a -1 charge)

Table Entry:
| Atoms | Valence electrons | Electron transfer from/to each atom | Ions formed in the product |
|-------|-------------------|--------------------------------------|----------------------------|
| Be | 2 | 1 to each F | Be²⁺ |
| F | 7 | Each 1 gets 1 from Be | F⁻ |

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#### Reaction 4: Mg + S → MgS
- Atoms: Magnesium (Mg) and Sulfur (S)
- Valence Electrons:
- Mg: 2 valence electrons
- S: 6 valence electrons
- Electron Transfer:
- Mg donates its 2 valence electrons to S.
- S accepts 2 electrons from Mg.
- Ions Formed:
- Mg²⁺ (Magnesium ion with a +2 charge)
- S²⁻ (Sulfide ion with a -2 charge)

Table Entry:
| Atoms | Valence electrons | Electron transfer from/to each atom | Ions formed in the product |
|-------|-------------------|--------------------------------------|----------------------------|
| Mg | 2 | 2 to S | Mg²⁺ |
| S | 6 | 2 from Mg | S²⁻ |

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#### Reaction 5: K + F → KF
- Atoms: Potassium (K) and Fluorine (F)
- Valence Electrons:
- K: 1 valence electron
- F: 7 valence electrons
- Electron Transfer:
- K donates its 1 valence electron to F.
- F accepts 1 electron from K.
- Ions Formed:
- K⁺ (Potassium ion with a +1 charge)
- F⁻ (Fluoride ion with a -1 charge)

Table Entry:
| Atoms | Valence electrons | Electron transfer from/to each atom | Ions formed in the product |
|-------|-------------------|--------------------------------------|----------------------------|
| K | 1 | 1 to F | K⁺ |
| F | 7 | 1 from K | F⁻ |

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Final Answer:

The completed table is as follows:

| Reactions | Atoms | Valence electrons | Electron transfer from/to each atom | Ions formed in the product |
|-----------|-------|-------------------|--------------------------------------|----------------------------|
| 1) Li + Cl → LiCl | Li | 1 | 1 to Cl | Li⁺ |
| | Cl | 7 | 1 from Li | Cl⁻ |
| 2) Ca + O → CaO | Ca | 2 | 2 to O | Ca²⁺ |
| | O | 6 | 2 from Ca | O²⁻ |
| 3) Be + F → BeF₂ | Be | 2 | 1 to each F | Be²⁺ |
| | F | 7 | Each 1 gets 1 from Be | F⁻ |
| 4) Mg + S → MgS | Mg | 2 | 2 to S | Mg²⁺ |
| | S | 6 | 2 from Mg | S²⁻ |
| 5) K + F → KF | K | 1 | 1 to F | K⁺ |
| | F | 7 | 1 from K | F⁻ |

Final Answer: \boxed{\text{See the completed table above.}}