Factors and Multiples Worksheets - Math Monks - Free Printable
Educational worksheet: Factors and Multiples Worksheets - Math Monks. Download and print for classroom or home learning activities.
WEBP
742×1050
31.4 KB
Free · Personal Use
Quality Assured by Worksheets Library Team
Reviewed for educational accuracy and age-appropriateness
ID: #1299374
⭐
Show Answer Key & Explanations
Step-by-step solution for: Factors and Multiples Worksheets - Math Monks
▼
Show Answer Key & Explanations
Step-by-step solution for: Factors and Multiples Worksheets - Math Monks
Let's solve each problem step by step.
---
Solution:
- Multiples of 5 are numbers that can be written as \( 5 \times n \), where \( n \) is an integer.
- The multiples of 5 between 15 and 30 are:
- \( 5 \times 3 = 15 \) (not included since it is not strictly greater than 15)
- \( 5 \times 4 = 20 \)
- \( 5 \times 5 = 25 \)
- \( 5 \times 6 = 30 \) (not included since it is not strictly less than 30)
Thus, the two multiples of 5 between 15 and 30 are 20 and 25.
Answer:
\[
\boxed{20, 25}
\]
---
Given numbers:
\[ 8, \, 16, \, 20, \, 24, \, 30, \, 32, \, 36, \, 40 \]
Solution:
- A multiple of 8 is a number that can be written as \( 8 \times n \), where \( n \) is an integer.
- Check each number:
- \( 8 \div 8 = 1 \) (multiple of 8)
- \( 16 \div 8 = 2 \) (multiple of 8)
- \( 20 \div 8 = 2.5 \) (not a multiple of 8)
- \( 24 \div 8 = 3 \) (multiple of 8)
- \( 30 \div 8 = 3.75 \) (not a multiple of 8)
- \( 32 \div 8 = 4 \) (multiple of 8)
- \( 36 \div 8 = 4.5 \) (not a multiple of 8)
- \( 40 \div 8 = 5 \) (multiple of 8)
The multiples of 8 are: 8, 16, 24, 32, 40.
Answer:
Circle:
\[
\boxed{8, 16, 24, 32, 40}
\]
---
#### a) 13
#### b) 14
#### c) 17
Solution:
- The first three multiples of a number \( n \) are \( n \times 1 \), \( n \times 2 \), and \( n \times 3 \).
#### a) First three multiples of 13:
\[ 13 \times 1 = 13 \]
\[ 13 \times 2 = 26 \]
\[ 13 \times 3 = 39 \]
#### b) First three multiples of 14:
\[ 14 \times 1 = 14 \]
\[ 14 \times 2 = 28 \]
\[ 14 \times 3 = 42 \]
#### c) First three multiples of 17:
\[ 17 \times 1 = 17 \]
\[ 17 \times 2 = 34 \]
\[ 17 \times 3 = 51 \]
Answer:
\[
\boxed{13, 26, 39 \quad \text{(a)}, \quad 14, 28, 42 \quad \text{(b)}, \quad 17, 34, 51 \quad \text{(c)}}
\]
---
Solution:
- To find the LCM, we use the prime factorization method:
- Prime factorization of 2: \( 2 \)
- Prime factorization of 8: \( 2^3 \)
- Prime factorization of 12: \( 2^2 \times 3 \)
- The LCM is found by taking the highest power of each prime factor:
- For \( 2 \): The highest power is \( 2^3 \) (from 8).
- For \( 3 \): The highest power is \( 3^1 \) (from 12).
- Therefore, the LCM is:
\[ \text{LCM} = 2^3 \times 3 = 8 \times 3 = 24 \]
Answer:
\[
\boxed{24}
\]
---
#### a) 12 and 20
#### b) 6 and 14
#### c) 11 and 15
Solution:
#### a) LCM of 12 and 20:
- Prime factorization:
- \( 12 = 2^2 \times 3 \)
- \( 20 = 2^2 \times 5 \)
- Highest powers:
- For \( 2 \): \( 2^2 \)
- For \( 3 \): \( 3^1 \)
- For \( 5 \): \( 5^1 \)
- LCM:
\[ \text{LCM} = 2^2 \times 3 \times 5 = 4 \times 3 \times 5 = 60 \]
#### b) LCM of 6 and 14:
- Prime factorization:
- \( 6 = 2 \times 3 \)
- \( 14 = 2 \times 7 \)
- Highest powers:
- For \( 2 \): \( 2^1 \)
- For \( 3 \): \( 3^1 \)
- For \( 7 \): \( 7^1 \)
- LCM:
\[ \text{LCM} = 2 \times 3 \times 7 = 42 \]
#### c) LCM of 11 and 15:
- Prime factorization:
- \( 11 = 11 \)
- \( 15 = 3 \times 5 \)
- Highest powers:
- For \( 11 \): \( 11^1 \)
- For \( 3 \): \( 3^1 \)
- For \( 5 \): \( 5^1 \)
- LCM:
\[ \text{LCM} = 11 \times 3 \times 5 = 165 \]
Answer:
\[
\boxed{60, 42, 165}
\]
---
#### a) 87
#### b) 196
Solution:
#### a) Factors of 87:
- To find the factors, check divisibility by integers from 1 to \( \sqrt{87} \approx 9.3 \):
- \( 87 \div 1 = 87 \) → Factors: \( 1, 87 \)
- \( 87 \div 3 = 29 \) → Factors: \( 3, 29 \)
- No other divisors between 4 and 28.
Thus, the factors of 87 are: 1, 3, 29, 87.
- Is 87 prime?
- A prime number has exactly two factors: 1 and itself.
- Since 87 has more than two factors (1, 3, 29, 87), it is not prime.
#### b) Factors of 196:
- To find the factors, check divisibility by integers from 1 to \( \sqrt{196} = 14 \):
- \( 196 \div 1 = 196 \) → Factors: \( 1, 196 \)
- \( 196 \div 2 = 98 \) → Factors: \( 2, 98 \)
- \( 196 \div 4 = 49 \) → Factors: \( 4, 49 \)
- \( 196 \div 7 = 28 \) → Factors: \( 7, 28 \)
- \( 196 \div 14 = 14 \) → Factor: \( 14 \) (repeated)
Thus, the factors of 196 are: 1, 2, 4, 7, 14, 28, 49, 98, 196.
- Is 196 prime?
- Since 196 has more than two factors, it is not prime.
Answer:
\[
\boxed{1, 3, 29, 87 \quad \text{(not prime)}, \quad 1, 2, 4, 7, 14, 28, 49, 98, 196 \quad \text{(not prime)}}
\]
---
1. \(\boxed{20, 25}\)
2. \(\boxed{8, 16, 24, 32, 40}\)
3. \(\boxed{13, 26, 39 \quad \text{(a)}, \quad 14, 28, 42 \quad \text{(b)}, \quad 17, 34, 51 \quad \text{(c)}}\)
4. \(\boxed{24}\)
5. \(\boxed{60, 42, 165}\)
6. \(\boxed{1, 3, 29, 87 \quad \text{(not prime)}, \quad 1, 2, 4, 7, 14, 28, 49, 98, 196 \quad \text{(not prime)}}\)
---
Problem 1: Write two multiples of 5 between 15 and 30.
Solution:
- Multiples of 5 are numbers that can be written as \( 5 \times n \), where \( n \) is an integer.
- The multiples of 5 between 15 and 30 are:
- \( 5 \times 3 = 15 \) (not included since it is not strictly greater than 15)
- \( 5 \times 4 = 20 \)
- \( 5 \times 5 = 25 \)
- \( 5 \times 6 = 30 \) (not included since it is not strictly less than 30)
Thus, the two multiples of 5 between 15 and 30 are 20 and 25.
Answer:
\[
\boxed{20, 25}
\]
---
Problem 2: Circle the numbers that are multiples of 8.
Given numbers:
\[ 8, \, 16, \, 20, \, 24, \, 30, \, 32, \, 36, \, 40 \]
Solution:
- A multiple of 8 is a number that can be written as \( 8 \times n \), where \( n \) is an integer.
- Check each number:
- \( 8 \div 8 = 1 \) (multiple of 8)
- \( 16 \div 8 = 2 \) (multiple of 8)
- \( 20 \div 8 = 2.5 \) (not a multiple of 8)
- \( 24 \div 8 = 3 \) (multiple of 8)
- \( 30 \div 8 = 3.75 \) (not a multiple of 8)
- \( 32 \div 8 = 4 \) (multiple of 8)
- \( 36 \div 8 = 4.5 \) (not a multiple of 8)
- \( 40 \div 8 = 5 \) (multiple of 8)
The multiples of 8 are: 8, 16, 24, 32, 40.
Answer:
Circle:
\[
\boxed{8, 16, 24, 32, 40}
\]
---
Problem 3: Write the first three multiples of:
#### a) 13
#### b) 14
#### c) 17
Solution:
- The first three multiples of a number \( n \) are \( n \times 1 \), \( n \times 2 \), and \( n \times 3 \).
#### a) First three multiples of 13:
\[ 13 \times 1 = 13 \]
\[ 13 \times 2 = 26 \]
\[ 13 \times 3 = 39 \]
#### b) First three multiples of 14:
\[ 14 \times 1 = 14 \]
\[ 14 \times 2 = 28 \]
\[ 14 \times 3 = 42 \]
#### c) First three multiples of 17:
\[ 17 \times 1 = 17 \]
\[ 17 \times 2 = 34 \]
\[ 17 \times 3 = 51 \]
Answer:
\[
\boxed{13, 26, 39 \quad \text{(a)}, \quad 14, 28, 42 \quad \text{(b)}, \quad 17, 34, 51 \quad \text{(c)}}
\]
---
Problem 4: Write the least common multiple (LCM) of 2, 8, and 12.
Solution:
- To find the LCM, we use the prime factorization method:
- Prime factorization of 2: \( 2 \)
- Prime factorization of 8: \( 2^3 \)
- Prime factorization of 12: \( 2^2 \times 3 \)
- The LCM is found by taking the highest power of each prime factor:
- For \( 2 \): The highest power is \( 2^3 \) (from 8).
- For \( 3 \): The highest power is \( 3^1 \) (from 12).
- Therefore, the LCM is:
\[ \text{LCM} = 2^3 \times 3 = 8 \times 3 = 24 \]
Answer:
\[
\boxed{24}
\]
---
Problem 5: Write the least common multiple for each set of numbers.
#### a) 12 and 20
#### b) 6 and 14
#### c) 11 and 15
Solution:
#### a) LCM of 12 and 20:
- Prime factorization:
- \( 12 = 2^2 \times 3 \)
- \( 20 = 2^2 \times 5 \)
- Highest powers:
- For \( 2 \): \( 2^2 \)
- For \( 3 \): \( 3^1 \)
- For \( 5 \): \( 5^1 \)
- LCM:
\[ \text{LCM} = 2^2 \times 3 \times 5 = 4 \times 3 \times 5 = 60 \]
#### b) LCM of 6 and 14:
- Prime factorization:
- \( 6 = 2 \times 3 \)
- \( 14 = 2 \times 7 \)
- Highest powers:
- For \( 2 \): \( 2^1 \)
- For \( 3 \): \( 3^1 \)
- For \( 7 \): \( 7^1 \)
- LCM:
\[ \text{LCM} = 2 \times 3 \times 7 = 42 \]
#### c) LCM of 11 and 15:
- Prime factorization:
- \( 11 = 11 \)
- \( 15 = 3 \times 5 \)
- Highest powers:
- For \( 11 \): \( 11^1 \)
- For \( 3 \): \( 3^1 \)
- For \( 5 \): \( 5^1 \)
- LCM:
\[ \text{LCM} = 11 \times 3 \times 5 = 165 \]
Answer:
\[
\boxed{60, 42, 165}
\]
---
Problem 6: List all the factors for each number. Is the number prime?
#### a) 87
#### b) 196
Solution:
#### a) Factors of 87:
- To find the factors, check divisibility by integers from 1 to \( \sqrt{87} \approx 9.3 \):
- \( 87 \div 1 = 87 \) → Factors: \( 1, 87 \)
- \( 87 \div 3 = 29 \) → Factors: \( 3, 29 \)
- No other divisors between 4 and 28.
Thus, the factors of 87 are: 1, 3, 29, 87.
- Is 87 prime?
- A prime number has exactly two factors: 1 and itself.
- Since 87 has more than two factors (1, 3, 29, 87), it is not prime.
#### b) Factors of 196:
- To find the factors, check divisibility by integers from 1 to \( \sqrt{196} = 14 \):
- \( 196 \div 1 = 196 \) → Factors: \( 1, 196 \)
- \( 196 \div 2 = 98 \) → Factors: \( 2, 98 \)
- \( 196 \div 4 = 49 \) → Factors: \( 4, 49 \)
- \( 196 \div 7 = 28 \) → Factors: \( 7, 28 \)
- \( 196 \div 14 = 14 \) → Factor: \( 14 \) (repeated)
Thus, the factors of 196 are: 1, 2, 4, 7, 14, 28, 49, 98, 196.
- Is 196 prime?
- Since 196 has more than two factors, it is not prime.
Answer:
\[
\boxed{1, 3, 29, 87 \quad \text{(not prime)}, \quad 1, 2, 4, 7, 14, 28, 49, 98, 196 \quad \text{(not prime)}}
\]
---
Final Answers:
1. \(\boxed{20, 25}\)
2. \(\boxed{8, 16, 24, 32, 40}\)
3. \(\boxed{13, 26, 39 \quad \text{(a)}, \quad 14, 28, 42 \quad \text{(b)}, \quad 17, 34, 51 \quad \text{(c)}}\)
4. \(\boxed{24}\)
5. \(\boxed{60, 42, 165}\)
6. \(\boxed{1, 3, 29, 87 \quad \text{(not prime)}, \quad 1, 2, 4, 7, 14, 28, 49, 98, 196 \quad \text{(not prime)}}\)
Parent Tip: Review the logic above to help your child master the concept of multiples worksheet grade 5.