Class 7 Maths (Hindi) Parimey Sankhayaen Worksheet - Free Printable

Let’s solve each problem step by step. We’ll go one question at a time, carefully checking our work.

---

1. योग ज्ञात कीजिए (Find the sum):

(a) $-2\frac{1}{3} + 4\frac{3}{5}$

First, convert mixed numbers to improper fractions:

$-2\frac{1}{3} = -\frac{7}{3}$
$4\frac{3}{5} = \frac{23}{5}$

Now find LCM of 3 and 5 → 15

Convert both fractions:

$-\frac{7}{3} = -\frac{35}{15}$
$\frac{23}{5} = \frac{69}{15}$

Add: $-\frac{35}{15} + \frac{69}{15} = \frac{34}{15} = 2\frac{4}{15}$

✔ Answer for (a): $2\frac{4}{15}$

---

(b) $\frac{-8}{19} + \frac{(-2)}{57}$

Note: $\frac{(-2)}{57} = -\frac{2}{57}$

LCM of 19 and 57 → 57 (since 57 = 19×3)

Convert:

$\frac{-8}{19} = \frac{-8 × 3}{57} = \frac{-24}{57}$

So: $\frac{-24}{57} + \frac{-2}{57} = \frac{-26}{57}$

✔ Answer for (b): $-\frac{26}{57}$

---

2. ज्ञात कीजिए (Find the value):

(a) $\frac{-6}{13} - \left(\frac{-7}{15}\right)$

Subtracting a negative is adding:

= $\frac{-6}{13} + \frac{7}{15}$

LCM of 13 and 15 → 195

Convert:

$\frac{-6}{13} = \frac{-6 × 15}{195} = \frac{-90}{195}$
$\frac{7}{15} = \frac{7 × 13}{195} = \frac{91}{195}$

Add: $\frac{-90 + 91}{195} = \frac{1}{195}$

✔ Answer for (a): $\frac{1}{195}$

---

(b) $-2\frac{1}{9} - 6$

Convert mixed number: $-2\frac{1}{9} = -\frac{19}{9}$

Write 6 as $\frac{54}{9}$

So: $-\frac{19}{9} - \frac{54}{9} = \frac{-73}{9} = -8\frac{1}{9}$

✔ Answer for (b): $-8\frac{1}{9}$

---

3. गुणनफल ज्ञात कीजिए (Find the product):

(a) $\frac{-6}{5} × \frac{9}{11}$

Multiply numerators and denominators:

Numerator: $-6 × 9 = -54$
Denominator: $5 × 11 = 55$

→ $\frac{-54}{55}$

✔ Answer for (a): $-\frac{54}{55}$

---

(b) $\frac{3}{-5} × \frac{-5}{3}$

Note: $\frac{3}{-5} = -\frac{3}{5}$, and $\frac{-5}{3}$ stays.

So: $-\frac{3}{5} × -\frac{5}{3} = \frac{15}{15} = 1$

(Or notice: numerator and denominator cancel out completely.)

✔ Answer for (b): $1$

---

4. मान ज्ञात कीजिए (Find the value):

(a) $\frac{-4}{5} ÷ (-3)$

Dividing by -3 is same as multiplying by $-\frac{1}{3}$

So: $\frac{-4}{5} × -\frac{1}{3} = \frac{4}{15}$

✔ Answer for (a): $\frac{4}{15}$

---

(b) $\frac{-7}{12} ÷ \left(\frac{-2}{13}\right)$

Dividing by fraction → multiply by reciprocal:

= $\frac{-7}{12} × \frac{13}{-2}$

Multiply: Numerator: $-7 × 13 = -91$
Denominator: $12 × -2 = -24$

So: $\frac{-91}{-24} = \frac{91}{24} = 3\frac{19}{24}$

✔ Answer for (b): $3\frac{19}{24}$

---

5. दिए गए बक्सों में >, < और = से सही चिह्नों को भरिए (Fill in >, < or =):

(a) $\frac{-7}{4} \square \frac{-8}{5}$

Convert to decimals or common denominator.

Common denominator of 4 and 5 → 20

$\frac{-7}{4} = \frac{-35}{20}$
$\frac{-8}{5} = \frac{-32}{20}$

Since -35 < -32 → $\frac{-7}{4} < \frac{-8}{5}$

✔ Fill: <

---

(b) $\frac{-5}{11} \square \frac{5}{11}$

Negative vs positive → negative is always less.

✔ Fill: <

---

(c) $\frac{1}{-3} \square \frac{-1}{4}$

$\frac{1}{-3} = -\frac{1}{3}$, compare with $-\frac{1}{4}$

Which is bigger? Think on number line: $-\frac{1}{4}$ is closer to zero than $-\frac{1}{3}$, so it’s larger.

So: $-\frac{1}{3} < -\frac{1}{4}$

✔ Fill: <

---

6. नीचे दी गई संख्याओं में से कौन-सा बड़ा है? (Which is greater?)

Compare: $-3\frac{2}{7}$ and $-3\frac{4}{5}$

Both are negative. The one closer to zero is greater.

Convert to improper fractions:

$-3\frac{2}{7} = -\frac{23}{7} ≈ -3.2857$
$-3\frac{4}{5} = -\frac{19}{5} = -3.8$

Since -3.2857 > -3.8 → $-3\frac{2}{7}$ is greater.

✔ Answer: $-3\frac{2}{7}$

---

7. दो परिमेय संख्याओं का गुणनफल $-\frac{4}{5}$ है। यदि उनमें से एक $\frac{8}{35}$ है तो दूसरी संख्या ज्ञात कीजिए।

Let the other number be $x$.

Then: $\frac{8}{35} × x = -\frac{4}{5}$

Solve for $x$:

$x = -\frac{4}{5} ÷ \frac{8}{35} = -\frac{4}{5} × \frac{35}{8}$

Simplify:

$-\frac{4 × 35}{5 × 8} = -\frac{140}{40} = -\frac{7}{2} = -3\frac{1}{2}$

✔ Answer: $-\frac{7}{2}$ or $-3\frac{1}{2}$

---

8.

(a) $\frac{-5}{8}$ में क्या जोड़ा जाए कि $\frac{2}{9}$ प्राप्त हो जाए?

Let the number to add be $x$.

So: $\frac{-5}{8} + x = \frac{2}{9}$

Then: $x = \frac{2}{9} - \left(-\frac{5}{8}\right) = \frac{2}{9} + \frac{5}{8}$

LCM of 9 and 8 → 72

$\frac{2}{9} = \frac{16}{72}$, $\frac{5}{8} = \frac{45}{72}$

Sum: $\frac{61}{72}$

✔ Answer: $\frac{61}{72}$

---

(b) 0 और 1 के बीच तीन परिमेय संख्याएँ बताइए।

Any three fractions between 0 and 1.

Examples: $\frac{1}{2}, \frac{1}{3}, \frac{2}{5}$ — all are between 0 and 1.

You can also write: $\frac{1}{4}, \frac{3}{4}, \frac{1}{5}$ — any will do.

✔ Sample answer: $\frac{1}{2}, \frac{1}{3}, \frac{1}{4}$

---

## Final Answer:

1. (a) $2\frac{4}{15}$
(b) $-\frac{26}{57}$

2. (a) $\frac{1}{195}$
(b) $-8\frac{1}{9}$

3. (a) $-\frac{54}{55}$
(b) $1$

4. (a) $\frac{4}{15}$
(b) $3\frac{19}{24}$

5. (a) <
(b) <
(c) <

6. $-3\frac{2}{7}$

7. $-\frac{7}{2}$ or $-3\frac{1}{2}$

8. (a) $\frac{61}{72}$
(b) Example: $\frac{1}{2}, \frac{1}{3}, \frac{1}{4}$