Free Printable Naming Ionic Compounds Worksheets - Free Printable

Let’s solve this step by step.

We’re forming ionic compounds. That means we combine positive ions (cations) and negative ions (anions) so that the total charge is zero — neutral compound.

First, let’s list the charges of each ion:

Cations (positive ions):
- Zinc → Zn²⁺
- Iron (II) → Fe²⁺
- Iron (III) → Fe³⁺
- Gallium → Ga³⁺ (Group 13, usually +3)
- Silver → Ag⁺ (always +1 in ionic compounds)
- Lead (IV) → Pb⁴⁺

Anions (negative ions):
- Chloride → Cl⁻
- Acetate → C₂H₃O₂⁻ or CH₃COO⁻ (we’ll write as C₂H₃O₂ for simplicity; charge = -1)
- Oxide → O²⁻
- Nitrate → NO₃⁻ (charge = -1)
- Nitride → N³⁻
- Sulfate → SO₄²⁻ (charge = -2)

Now, to make a neutral compound, we balance the charges.

---

Part 1: Fill in the table

We’ll go row by row.

#### Row 1: Chloride (Cl⁻)

- Zinc (Zn²⁺) + Cl⁻ → need 2 Cl⁻ to balance → ZnCl₂
- Iron (II) (Fe²⁺) + Cl⁻ → FeCl₂
- Iron (III) (Fe³⁺) + Cl⁻ → need 3 Cl⁻ → FeCl₃
- Gallium (Ga³⁺) + Cl⁻ → GaCl₃
- Silver (Ag⁺) + Cl⁻ → AgCl
- Lead (IV) (Pb⁴⁺) + Cl⁻ → need 4 Cl⁻ → PbCl₄

#### Row 2: Acetate (C₂H₃O₂⁻)

Same pattern — acetate is -1.

- Zn²⁺ → needs 2 acetates → Zn(C₂H₃O₂)₂
- Fe²⁺ → Fe(C₂H₃O₂)₂
- Fe³⁺ → Fe(C₂H₃O₂)₃
- Ga³⁺ → Ga(C₂H₃O₂)₃
- Ag⁺ → AgC₂H₃O₂
- Pb⁴⁺ → Pb(C₂H₃O₂)₄

*(Note: Sometimes written with parentheses around polyatomic ions when more than one is needed.)*

#### Row 3: Oxide (O²⁻)

Oxide is -2.

- Zn²⁺ + O²⁻ → 1:1 → ZnO
- Fe²⁺ + O²⁻ → FeO
- Fe³⁺ + O²⁻ → need to balance: LCM of 3 and 2 is 6 → 2 Fe³⁺ and 3 O²⁻ → Fe₂O₃
- Ga³⁺ + O²⁻ → same as above → Ga₂O₃
- Ag⁺ + O²⁻ → need 2 Ag⁺ → Ag₂O
- Pb⁴⁺ + O²⁻ → 1 Pb⁴⁺ and 2 O²⁻ → PbO₂

#### Row 4: Nitrate (NO₃⁻)

Nitrate is -1.

- Zn²⁺ → Zn(NO₃)₂
- Fe²⁺ → Fe(NO₃)₂
- Fe³⁺ → Fe(NO₃)₃
- Ga³⁺ → Ga(NO₃)₃
- Ag⁺ → AgNO₃
- Pb⁴⁺ → Pb(NO₃)₄

#### Row 5: Nitride (N³⁻)

Nitride is -3.

- Zn²⁺ + N³⁻ → LCM of 2 and 3 is 6 → 3 Zn²⁺ and 2 N³⁻ → Zn₃N₂
- Fe²⁺ + N³⁻ → same → Fe₃N₂
- Fe³⁺ + N³⁻ → 1:1 → FeN
- Ga³⁺ + N³⁻ → GaN
- Ag⁺ + N³⁻ → need 3 Ag⁺ → Ag₃N
- Pb⁴⁺ + N³⁻ → LCM of 4 and 3 is 12 → 3 Pb⁴⁺ and 4 N³⁻ → Pb₃N₄

#### Row 6: Sulfate (SO₄²⁻)

Sulfate is -2.

- Zn²⁺ + SO₄²⁻ → ZnSO₄
- Fe²⁺ + SO₄²⁻ → FeSO₄
- Fe³⁺ + SO₄²⁻ → LCM of 3 and 2 is 6 → 2 Fe³⁺ and 3 SO₄²⁻ → Fe₂(SO₄)₃
- Ga³⁺ + SO²⁻ → same → Ga₂(SO₄)₃
- Ag⁺ + SO₄²⁻ → need 2 Ag⁺ → Ag₂SO₄
- Pb⁴⁺ + SO₄²⁻ → need 2 SO₄²⁻ to balance 4+ → Pb(SO₄)₂

---

Part 2: Write formulas for given compounds

a. Lithium Acetate
Lithium = Li⁺, Acetate = C₂H₃O₂ → LiC₂H₃O₂

b. Cobalt (III) Chloride
Co³⁺ + Cl⁻ → need 3 Cl⁻ → CoCl₃

c. Copper (II) Chlorate
Cu²⁺ + ClO₃⁻ → need 2 chlorate ions → Cu(ClO₃)₂

d. Titanium (II) Selenide
Ti²⁺ + Se²⁻ → 1:1 → TiSe

e. Calcium Oxide
Ca²⁺ + O²⁻ → CaO

---

Final Answer:

Part 1 Table:

| | Zinc | Iron (II) | Iron (III) | Gallium | Silver | Lead (IV) |
|----------|------------|-------------|---------------|-------------|-------------|--------------|
| Chloride | ZnCl₂ | FeCl₂ | FeCl₃ | GaCl₃ | AgCl | PbCl₄ |
| Acetate | Zn(C₂H₃O₂)₂| Fe(C₂H₃O₂)₂ | Fe(C₂H₃O₂)₃ | Ga(C₂H₃O₂)₃ | AgC₂H₃O₂ | Pb(C₂H₃O₂)₄ |
| Oxide | ZnO | FeO | Fe₂O₃ | Ga₂O₃ | Ag₂O | PbO₂ |
| Nitrate | Zn(NO₃)₂ | Fe(NO₃)₂ | Fe(NO₃)₃ | Ga(NO₃)₃ | AgNO₃ | Pb(NO₃)₄ |
| Nitride | Zn₃N₂ | Fe₃N₂ | FeN | GaN | Ag₃N | Pb₃N₄ |
| Sulfate | ZnSO₄ | FeSO₄ | Fe₂(SO₄)₃ | Ga₂(SO₄)₃ | Ag₂SO₄ | Pb(SO₄)₂ |

Part 2:

a. LiC₂H₃O₂
b. CoCl₃
c. Cu(ClO₃)₂
d. TiSe
e. CaO